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Hydrocarbons - Alkenes: Markovnikov, Anti-Markovnikov, Ozonolysis is a crucial topic in JEE, appearing in 2-3 questions every year. It's moderately difficult and equally important for both JEE Main and Advanced.
You should be familiar with: - Alkanes and Alkene Structures - Addition Reactions - Electrophilic Addition Reactions - Stereochemistry Basics
Quick revision: - Review alkane and alkene structures. - Brush up on addition reactions and stereochemistry.
Key concepts for JEE problems:
Mistake: Assuming Markovnikov's rule applies to all addition reactions. Fix: Check the specific reaction conditions and mechanism.
No specific graphs or diagrams are relevant to this topic.
No specific shortcuts are relevant to this topic.
Question 1 (Easy) What is the product of the reaction between ethene and ozone? A) CH3CHO and CH3COCH3 B) CH3CHO and CH3COOH C) CH3COCH3 and CH3COOH D) CH3COCH3 and CH3COCH3
Answer: A) CH3CHO and CH3COCH3 Solution: Ozonolysis of ethene results in the formation of CH3CHO and CH3COCH3. Common Wrong Answer: Option B, assuming a simple addition reaction.
Question 2 (Moderate) What is the major product of the reaction between propene and HBr, following Markovnikov's rule? A) CH3CH2CH2Br B) CH3CH(CH3)CH2Br C) CH3CH2CH(Br)CH3 D) CH3CH(Br)CH3
Answer: B) CH3CH(CH3)CH2Br Solution: Following Markovnikov's rule, the hydrogen atom attaches to the carbon with more hydrogen atoms, resulting in the formation of CH3CH(CH3)CH2Br. Common Wrong Answer: Option A, assuming a simple addition reaction.
Question 3 (JEE Advanced) What is the stereochemistry of the product formed in the reaction between cis-2-butene and ozone? A) cis B) trans C) meso D) racemic
Answer: B) trans Solution: Ozonolysis of cis-2-butene results in the formation of a trans product. Common Wrong Answer: Option A, assuming a simple addition reaction.
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