Fatskills
Practice. Master. Repeat.
Study Guide: JEE Physics Kinematics Motion in 1D Equations Graphs Relative Motion
Source: https://www.fatskills.com/joint-entrance-examination-jee/chapter/jee-physics-kinematics-motion-in-1d-equations-graphs-relative-motion

JEE Physics Kinematics Motion in 1D Equations Graphs Relative Motion

By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.

⏱️ ~4 min read

Kinematics — Motion in 1D: Equations, Graphs, Relative Motion


What This Is and Why It Matters for JEE

Kinematics in 1D deals with motion along a straight line. It's a moderate difficulty topic, appearing in 2-3 questions every year. This topic is crucial for both JEE Main and Advanced, with a slight emphasis on Advanced.

Prerequisites

  • Motion in 1D basics (displacement, velocity, acceleration)
  • Equations of motion (s = ut + 1/2at^2, v = u + at, etc.)
  • Graphs and diagrams (position-time, velocity-time, etc.)

Core Concepts (Exam-Focused)

  • Equations of motion:
  • s = ut + 1/2at^2 (displacement)
  • v = u + at (velocity)
  • v^2 = u^2 + 2as (velocity)
  • Important conditions:
  • Initial velocity (u) and acceleration (a) should be given.
  • Displacement (s) is a scalar quantity.
  • Common unit conventions:
  • Distance (m)
  • Velocity (m/s)
  • Acceleration (m/s^2)

Step-by-Step Problem-Solving Strategy

  1. Identify the given information (u, a, s, t, etc.).
  2. Choose the correct equation of motion.
  3. Plug in the values and solve for the unknown quantity.
  4. Check for multiple cases or special conditions (e.g., negative time).
  5. Verify the dimensional consistency of the answer.

Important Graphs / Diagrams

  • Position-time graph: A straight line with a slope representing velocity.
  • Velocity-time graph: A straight line with a slope representing acceleration.
  • Acceleration-time graph: A straight line with a slope representing jerk.

Typical JEE Question Patterns

  • Find minimum/maximum value of...: Use calculus or algebra to find the critical point(s).
  • Compare time periods...: Use the equations of motion to find the time taken for each case.
  • Determine the motion...: Use the equations of motion to find the displacement, velocity, or acceleration.

Common Mistakes & Exam Traps

  • The mistake: Assuming a constant acceleration when it's not given.
  • Why it happens: Misreading the problem or misunderstanding the concept.
  • How to avoid it: Carefully read the problem and identify the given information.
  • Exam board insight: Examiners may penalize this mistake by giving a wrong answer.
  • The mistake: Not checking for multiple cases or special conditions.
  • Why it happens: Rushing or not reading the problem carefully.
  • How to avoid it: Take your time and carefully read the problem.
  • Exam board insight: Examiners may penalize this mistake by giving a wrong answer.

Time-Saving Shortcuts

  • Use the equations of motion to find the time taken: Instead of using the time equation, use the displacement equation to find the time taken.
  • Use the velocity equation to find the displacement: Instead of using the displacement equation, use the velocity equation to find the displacement.

Practice MCQs (Exam-Style)

Question 1: A particle moves with a constant acceleration of 2 m/s^2. If its initial velocity is 4 m/s, find its velocity after 3 seconds.

A) 10 m/s B) 12 m/s C) 14 m/s D) 16 m/s

Answer: B Solution: v = u + at = 4 + 2(3) = 10 m/s ⚠️ Common Wrong Answer: A) 10 m/s (tempting because it's a multiple of 2)

Question 2: A car travels from rest to a speed of 60 km/h in 10 seconds. Find its acceleration.

A) 2 m/s^2 B) 4 m/s^2 C) 6 m/s^2 D) 8 m/s^2

Answer: C Solution: a = Δv / Δt = (60/3.6) / 10 = 1.67 m/s^2 ≈ 2 m/s^2 ⚠️ Common Wrong Answer: A) 2 m/s^2 (tempting because it's a small value)

Question 3: A particle moves with a constant acceleration of 2 m/s^2. If its initial velocity is 4 m/s, find its displacement after 3 seconds.

A) 20 m B) 24 m C) 28 m D) 32 m

Answer: B Solution: s = ut + 1/2at^2 = 4(3) + 1/2(2)(3)^2 = 24 m Common Wrong Answer: A) 20 m (tempting because it's a multiple of 4)

Quick Revision Card (60-Second Summary)

  • Equations of motion:
  • s = ut + 1/2at^2
  • v = u + at
  • v^2 = u^2 + 2as
  • Important conditions:
  • Initial velocity (u) and acceleration (a) should be given.
  • Displacement (s) is a scalar quantity.
  • Common unit conventions:
  • Distance (m)
  • Velocity (m/s)
  • Acceleration (m/s^2)

If You Get Stuck in Exam

  • Write partial marks: If you're unsure, write the answer you know and get partial marks.
  • Eliminate distractors: Carefully read the options and eliminate the ones you know are wrong.
  • Skip and return: If you're stuck, skip the question and return to it later with a fresh mind.

Related JEE Topics

  • Motion in 2D: Uses the concepts of motion in 1D to solve problems in two dimensions.
  • Projectile motion: Applies the concepts of motion in 1D to solve problems involving projectiles.
  • Relative motion: Uses the concepts of motion in 1D to solve problems involving relative motion.


ADVERTISEMENT