By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
SHM — Combination of SHMs, Lissajous Figures is a fundamental topic in Physics that deals with the superposition of two or more simple harmonic motions (SHMs). It appears in 2-3 questions every year in JEE, with a moderate difficulty level. This topic is more important for JEE Advanced, where it can account for a significant portion of the marks.
Key Formulae: * Equation of SHM: y = A sin(?t + ?) * Amplitude of combined SHM: A = ?(A1^2 + A2^2 + 2A1A2 cos(?)) * Phase Difference: ? = tan^(-1) (A2 sin(?1t) / A1 cos(?1t))
Mistake: Assuming the phase difference is zero without checking the given information.
Lissajous figures are graphical representations of the combined motion of two SHMs. Examiners test your ability to identify the shape and orientation of the Lissajous figure based on the phase difference.
Exam board insight: Examiners penalize students who assume the phase difference is zero without justification.
The mistake: Failing to check for special conditions, such as resonance or destructive interference.
Question 1: (Easy) Two SHMs have amplitudes of 2 cm and 3 cm, and a phase difference of 30°. What is the amplitude of the combined SHM?
A) 2.5 cm B) 3.5 cm C) 4.5 cm D) 5.5 cm
Answer: A) 2.5 cm Solution: Use the formula A = ?(A1^2 + A2^2 + 2A1A2 cos(?)) to find the amplitude of the combined SHM. Common Wrong Answer: Option B) 3.5 cm, because students often assume the phase difference is zero.
Question 2: (Moderate) Two SHMs have frequencies of 5 Hz and 7 Hz, and a phase difference of 60°. What is the shape and orientation of the Lissajous figure?
A) Ellipse with a major axis of 10 cm B) Ellipse with a minor axis of 10 cm C) Circle with a radius of 5 cm D) Rectangle with a width of 10 cm
Answer: A) Ellipse with a major axis of 10 cm Solution: Use the phase difference to determine the shape and orientation of the Lissajous figure. Common Wrong Answer: Option D) Rectangle with a width of 10 cm, because students often misunderstand the concept of phase difference.
Question 3: (JEE Advanced level) Two SHMs have amplitudes of 5 cm and 10 cm, and a phase difference of 90°. What is the equation of the combined SHM?
A) y = 5 sin(2?t) + 10 sin(2?t + 90°) B) y = 5 sin(2?t) - 10 sin(2?t + 90°) C) y = 15 sin(2?t + 45°) D) y = 15 sin(2?t - 45°)
Answer: A) y = 5 sin(2?t) + 10 sin(2?t + 90°) Solution: Use the superposition principle to find the equation of the combined SHM. Common Wrong Answer: Option B) y = 5 sin(2?t) - 10 sin(2?t + 90°), because students often misunderstand the concept of phase difference.
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