By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Rotational motion is a fundamental concept in physics, and it appears in 2-3 questions every year in JEE. It's a moderate difficulty topic, and understanding it well is crucial for both JEE Main and Advanced. You should be able to solve problems related to torque, angular momentum, and rolling motion with ease.
You should already know: - Newton's laws of motion - Kinematics (velocity, acceleration, displacement) - Circular motion (centripetal force, centripetal acceleration) - Work and energy (kinetic energy, potential energy)
If you're not confident, quickly revise these topics to build a strong foundation.
Key concepts for JEE problems:
No specific graphs are required for this topic, but you should be able to visualize the motion and identify key quantities.
Use the formula τ = I × α to find the torque if you know the angular acceleration.
Question 1: A solid cylinder of radius R and mass M is rotating with angular velocity ω. The moment of inertia of the cylinder is I = (1/2) M R². The torque applied to the cylinder is τ = F R. What is the angular acceleration of the cylinder?
A) α = F / (2 M) B) α = F / MC) α = F / (4 M) D) α = F / (1/2 M)
Answer: A) α = F / (2 M) Solution: Use the formula τ = I × α to find the angular acceleration.Common Wrong Answer: Option B is tempting because it's a simple answer, but it's incorrect because it doesn't consider the moment of inertia.
Question 2: A wheel of radius R is rolling on a flat surface with a linear velocity v. The moment of inertia of the wheel is I = (1/2) M R². What is the angular velocity of the wheel?
A) ω = v / RB) ω = v / (2 R) C) ω = v / (4 R) D) ω = v / (1/2 R)
Answer: B) ω = v / (2 R) Solution: Use the concept of rolling motion to find the angular velocity.Common Wrong Answer: Option A is tempting because it's a simple answer, but it's incorrect because it doesn't consider the moment of inertia.
Question 3: A solid sphere of radius R and mass M is rotating with angular velocity ω. The moment of inertia of the sphere is I = (2/5) M R². What is the angular momentum of the sphere?
A) L = (2/5) M R² ωB) L = (1/2) M R² ωC) L = (4/5) M R² ωD) L = (1/5) M R² ω
Answer: A) L = (2/5) M R² ωSolution: Use the formula L = I × ω to find the angular momentum.Common Wrong Answer: Option B is tempting because it's a simple answer, but it's incorrect because it doesn't consider the moment of inertia.
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