By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
This topic explains how to find the mean (expected value) and standard deviation (SD) of the sum or difference of two (or more) independent random variables. It’s essential for the AP exam because it allows you to analyze real-world scenarios like: - A factory produces two types of widgets; what’s the total expected weight and variability if you combine one of each? - A student takes two exams; what’s the expected difference in their scores, and how much could that difference vary? - A company’s revenue comes from two independent products; what’s the total expected revenue and its uncertainty?
Mastering this helps you solve FRQs on probability, sampling distributions, and confidence intervals where combining variables is required.
Follow these steps for a typical FRQ on combining independent random variables:
Check if they are independent (if not, you can’t combine variances!).
Determine What You’re Combining (Sum or Difference?)
Are you asked for X + Y (e.g., total score) or X – Y (e.g., difference in scores)?
Calculate the Mean of the Combined Variable
For difference: E(X – Y) = –
Calculate the Variance of the Combined Variable
If not independent, you cannot combine variances (this is a common trap!).
Find the Standard Deviation
SD(X ± Y) = ?(² + ²)
Check for Normality (If Needed)
If normal, use normalcdf( on TI-84 for probabilities.
normalcdf(
Answer the Question in Context
Why? Variance is additive for independent variables, but SD is not.
Mistake: Forgetting to check independence before combining variances.
Why? Dependence introduces covariance, which affects variance.
Mistake: Assuming X – Y has a different variance than X + Y.
Why? Variance is always positive, so subtracting doesn’t change it.
Mistake: Ignoring the 10% condition when sampling without replacement.
Why? Without replacement, selections are not independent unless the sample is small relative to the population.
Mistake: Using the wrong distribution for probabilities.
Linear combinations (e.g., 2X + 3Y).
Tricky Distinctions:
Normality matters: If X and Y are not normal, the sum/difference may not be normal unless n is large.
Calculator Tips:
normalcdf(lower, upper, ?, ?)
For linear combinations, first compute the new mean and SD, then use normalcdf.
normalcdf
Common FRQ Setup:
A factory produces two types of batteries. Battery A has a mean lifetime of 100 hours with a standard deviation of 10 hours. Battery B has a mean lifetime of 120 hours with a standard deviation of 15 hours. The lifetimes are independent. What is the standard deviation of the difference in lifetimes (A – B)?
(A) 5 hours (B) ?(10² + 15²) hours (C) 10 + 15 hours (D) ?(10² – 15²) hours (E) 15 – 10 hours
Correct Answer: (B) ?(10² + 15²) hours Explanation: Var(A – B) = Var(A) + Var(B) = 10² + 15², so SD(A – B) = ?(10² + 15²).
A college student’s commute consists of two parts: X = time spent on the bus (mean = 20 minutes, SD = 5 minutes) and Y = time spent walking (mean = 10 minutes, SD = 2 minutes). The times are independent.
a) What is the mean and standard deviation of the total commute time (X + Y)? b) What is the probability that the total commute time exceeds 35 minutes? Assume X + Y is normally distributed.
Correct Answers: a) Mean = 30 minutes, SD = ?(5² + 2²) = ?29-5.39 minutes - E(X + Y) = 20 + 10 = 30 - Var(X + Y) = 5² + 2² = 29-SD = ?29
b) P(X + Y > 35)-0.180 (using normalcdf(35, 1E99, 30, ?29) on TI-84) - Z = (35 – 30) / ?29-0.928-P(Z > 0.928)-0.1766
normalcdf(35, 1E99, 30, ?29)
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