By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
A z-score measures how many standard deviations a data point (x) is from the mean (?). The standard normal distribution (mean = 0, SD = 1) allows us to find probabilities and percentiles using z-scores. This is essential for hypothesis testing, confidence intervals, and comparing data across different scales (e.g., comparing SAT scores to ACT scores, or determining if a factory’s product defect rate is unusually high).
? = population standard deviation
Standard Normal Distribution (Z-distribution):
Used to find probabilities for normal distributions via normalcdf() or invNorm().
normalcdf()
invNorm()
Empirical Rule (68-95-99.7 Rule):
~68% of data falls within 1? of ?, ~95% within 2?, ~99.7% within 3?.
normalcdf(lower, upper, ?, ?) (TI-84):
normalcdf(lower, upper, ?, ?)
For standard normal, use normalcdf(lower, upper, 0, 1).
normalcdf(lower, upper, 0, 1)
invNorm(area, ?, ?) (TI-84):
invNorm(area, ?, ?)
For standard normal, use invNorm(area, 0, 1).
invNorm(area, 0, 1)
Standardizing Data:
Converting a normal distribution to Z (standard normal) by subtracting-and dividing by ?.
Percentile:
The percentage of data below a given value (e.g., 90th percentile = 90% of data is below this value).
Outlier Rule (Using z-scores):
What are ? and ??
Standardize (if needed):
Convert x to z using z = (x – ?) / ?.
Use normalcdf() or invNorm():
For percentiles: invNorm(area, ?, ?)
Interpret in context:
Example: "There is a 15% chance that a randomly selected battery lasts less than 8 hours."
Check for reasonableness:
Correction: Always convert to z first (or input ? and ? into the calculator).
Mistake: Mixing up normalcdf() and invNorm().
Correction:
Mistake: Using sample statistics (x?, s) instead of population parameters (?, ?) in z-score formula.
Correction: Only use z = (x – ?) / ? when ? and ? are known. For samples, use t-scores.
Mistake: Misinterpreting percentiles (e.g., saying the 90th percentile means 90% of data is above it).
Correction: The 90th percentile means 90% of data is below it.
Mistake: Assuming all distributions are normal.
Compare z-scores across different distributions (e.g., "Is a 1200 SAT or 28 ACT more impressive?").
Tricky Distinctions:
Probability vs. Percentile: normalcdf() gives probability; invNorm() gives a value.
Calculator Pitfalls:
Answer: (B) 0.682 (Empirical Rule: ~68% within 1?).
FRQ: The weights of newborn babies are normally distributed with ? = 7.5 lbs and ? = 1.2 lbs.
normalcdf(-1E99, 6, 7.5, 1.2)-0.1056
invNorm(0.90, 7.5, 1.2)-9.03 lbs
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