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The two-sample t-test for the difference of means determines whether the average of one population differs from the average of another. It’s essential for comparing treatments (e.g., does a new fertilizer increase crop yield more than the old one?) or groups (e.g., do men and women spend different amounts on coffee per month?). The AP exam tests this in FRQs and MCQs, often requiring you to justify conditions, compute the test statistic, and interpret results in context.
t = (x – x) / ?(s?²/n? + s?²/n?)
Degrees of freedom (df): Use min(n?–1, n?–1) or the conservative df (AP prefers this for simplicity). For exact df, use the Welch-Satterthwaite equation (not required on AP).
min(n?–1, n?–1)
Two-Sample t-Interval for – :
(x – x) ± t* ?(s?²/n? + s?²/n?)
t* = critical value from invT(area, df) (e.g., invT(0.975, df) for 95% CI).
invT(area, df)
invT(0.975, df)
Conditions (LINER):
Equal variance (optional): If s?-s?, use pooled t-test (not required on AP).
Calculator Commands (TI-84):
STAT-TESTS-4:2-SampTTest
STAT-TESTS-0:2-SampTInt
For a typical FRQ:1. State hypotheses: - H?: = (no difference) - H?: - (or >/< depending on context).
Random: Data from random samples/experiments.
Compute test statistic:
2-SampTTest
Report t and df (use min(n?–1, n?–1)).
Find p-value:
tcdf(lower, upper, df)
tcdf(-1E99, -t, df) * 2
For calculator: 2-SampTTest gives p-value directly.
Make conclusion:
Correction: Paired tests require matched pairs (e.g., before/after measurements). Two-sample tests compare independent groups.
Mistake: Forgetting to check normality for small samples.
Correction: If n < 30, plot data (boxplot/histogram) to confirm no skew/outliers.
Mistake: Mixing up – vs. – in hypotheses.
Correction: Define groups clearly (e.g., " = treatment group, = control group").
Mistake: Using pooled variance (AP does not require this).
Correction: Always select Pooled: No in 2-SampTTest.
Mistake: Misinterpreting the confidence interval.
(D) Chi-square test Answer: (B) Two-sample t-test (comparing two independent groups).
FRQ Part: Two samples of students took a math test: Sample 1 (n?=40, x=82, s?=5) and Sample 2 (n?=50, x=79, s?=6). The 95% CI for – is (0.5, 5.5). Interpret this interval in context. Answer: We are 95% confident that the true mean math score for Sample 1 is between 0.5 and 5.5 points higher than for Sample 2.
MCQ: For a two-sample t-test, why is it important to check that the samples are independent?
2-SampTInt
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