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A confidence interval for the difference of two proportions (p? – p?) estimates the true difference between two population proportions using sample data. This is essential on the AP exam because it allows us to compare two groups (e.g., treatment vs. control in a medical trial, success rates of two teaching methods, or defect rates in two factories). For example, a researcher might use this interval to determine if a new vaccine reduces infection rates more effectively than a placebo.
(z^*) = critical z-value (e.g., 1.96 for 95% confidence)
Pooled sample proportion (for hypothesis tests, not intervals): [ \hat{p}_c = \frac{X_1 + X_2}{n_1 + n_2} ]
(X_1, X_2) = number of successes in each sample
Conditions for inference (BINS):
SRS? Both samples are random (or treatments are randomly assigned).
Calculator command (TI-84): 2-PropZInt(x?, n?, x?, n?, C-Level)
2-PropZInt(x?, n?, x?, n?, C-Level)
(C-Level) = confidence level (e.g., 0.95 for 95%)
Interpretation of a confidence interval: "We are [C-Level]% confident that the true difference in proportions (p? – p?) is between [lower bound] and [upper bound]."
Hypotheses for a two-proportion z-test (not an interval, but related):
How to construct a confidence interval for p? – p? on an FRQ:
State the parameter and context: Define (p_1) and (p_2) (e.g., "Let (p_1) = proportion of patients cured with Drug A, (p_2) = proportion cured with Drug B").
Check conditions (BINS):
SRS? Samples are random (or treatments are randomly assigned).
Name the procedure: "We will construct a two-proportion z-interval for (p_1 - p_2)."
Compute the interval:
2-PropZInt
Example: 2-PropZInt(45, 100, 30, 100, 0.95)? (0.012, 0.288).
2-PropZInt(45, 100, 30, 100, 0.95)
Interpret the interval in context: "We are 95% confident that the true difference in cure rates (Drug A – Drug B) is between 1.2% and 28.8%."
Answer the question (if applicable): If the interval is entirely positive, conclude (p_1 > p_2); if entirely negative, (p_1 < p_2); if it includes 0, there’s no significant difference.
Mistake: Forgetting to check the Normal condition (e.g., (n\hat{p} \geq 10)). Correction: Always verify all four BINS conditions. The AP exam will deduct points for missing this.
Mistake: Using the pooled proportion ((\hat{p}_c)) in the confidence interval formula. Correction: (\hat{p}_c) is only for hypothesis tests, not intervals. Use the separate sample proportions ((\hat{p}_1, \hat{p}_2)) in the interval formula.
Mistake: Misinterpreting the interval as "the probability that (p_1 - p_2) is in the interval." Correction: The interval either contains (p_1 - p_2) or it doesn’t. The confidence level (e.g., 95%) refers to the method’s long-run success rate.
Mistake: Ignoring the order of subtraction (e.g., (p_1 - p_2) vs. (p_2 - p_1)). Correction: Define (p_1) and (p_2) clearly at the start. The interval’s sign depends on the order.
Mistake: Not using the correct critical value (e.g., using (t^) instead of (z^)). Correction: For proportions, always use (z^) (from invNorm on the TI-84). (t^) is for means.
invNorm
Answer: (B) Explanation: The interval is about the difference (p_1 - p_2), not probability. (C) is correct but less specific than (B).
Answer: - Conditions: Binary, independent samples, (n_1\hat{p}_1 = 80 \geq 10), (n_1(1-\hat{p}_1) = 20 \geq 10), (n_2\hat{p}_2 = 65 \geq 10), (n_2(1-\hat{p}_2) = 35 \geq 10), SRS assumed. - 2-PropZInt(80, 100, 65, 100, 0.95)? (0.015, 0.285). - Interpretation: We are 95% confident that the true difference in pass rates (Method A – Method B) is between 1.5% and 28.5%.
2-PropZInt(80, 100, 65, 100, 0.95)
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