By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Roots are values that, when raised to a certain power, yield a given number. They are the inverse operation of exponentiation. This topic appears in exams because it tests your understanding of inverse operations and your ability to manipulate numbers and equations. Questions typically involve finding the root of a number, simplifying radical expressions, and solving equations involving roots.
Roots are tested in various mathematics exams, including the SAT, ACT, and high school algebra and geometry tests. They frequently appear in questions related to solving equations, simplifying expressions, and understanding geometric relationships. These questions typically carry moderate to high marks and test your ability to apply inverse operations and understand number relationships.
The primary rule is that a root is a number that, when raised to a certain power, equals a given number. For example, if ( x^2 = 9 ), then ( x ) is the square root of 9.
Think of roots as "undoing" the power. For example, the square root "undoes" the square, and the cube root "undoes" the cube.
Intermediate
Question: Find the square root of 64.
Step-by-Step Solution: 1. Identify the number whose square is 64.2. Recognize that ( 8^2 = 64 ).3. Therefore, ( \sqrt{64} = 8 ).
Answer: 8
Question: Simplify ( \sqrt{75} ).
Step-by-Step Solution: 1. Factor 75 into its prime factors: ( 75 = 3 \times 5^2 ).2. Rewrite the square root: ( \sqrt{75} = \sqrt{3 \times 5^2} ).3. Simplify by taking the square root of the perfect square: ( \sqrt{75} = 5\sqrt{3} ).
Answer: ( 5\sqrt{3} )
Question: Solve for ( x ) in the equation ( \sqrt{x + 5} = 7 ).
Step-by-Step Solution: 1. Square both sides to eliminate the square root: ( (\sqrt{x + 5})^2 = 7^2 ).2. Simplify: ( x + 5 = 49 ).3. Solve for ( x ): ( x = 49 - 5 ).4. Therefore, ( x = 44 ).
Answer: 44
Correct Approach: Recognize that ( 7^2 = 49 ), so ( \sqrt{49} = 7 ).
Mistake: Treating ( \sqrt{-9} ) as -3.
Correct Approach: Use the imaginary unit ( i ), so ( \sqrt{-9} = 3i ).
Mistake: Simplifying ( \sqrt{x^2} ) to ( x ) without considering the absolute value.
Correct Approach: ( \sqrt{x^2} = |x| ), the nonnegative value.
Mistake: Adding sides directly in a right triangle instead of using the Pythagorean theorem.
Favored By: SAT, ACT
Short-Answer:
Favored By: High school algebra tests
Problem-Solving:
Question: What is ( \sqrt{144} )? - Options: - A) 11 - B) 12 - C) 13 - D) 14
Correct Answer: B) 12
Explanation: ( 12^2 = 144 ), so ( \sqrt{144} = 12 ).
Why the Distractors Are Tempting: - A) 11: Close to the correct answer but not a perfect square.- C) 13: Also close but not a perfect square.- D) 14: Slightly higher than the correct answer.
Question: Simplify ( \sqrt{50} ).- Options: - A) ( 5\sqrt{2} ) - B) ( 7\sqrt{2} ) - C) ( 5\sqrt{3} ) - D) ( 7\sqrt{3} )
Correct Answer: A) ( 5\sqrt{2} )
Explanation: ( 50 = 2 \times 5^2 ), so ( \sqrt{50} = 5\sqrt{2} ).
Why the Distractors Are Tempting: - B) ( 7\sqrt{2} ): Incorrect coefficient.- C) ( 5\sqrt{3} ): Incorrect radical.- D) ( 7\sqrt{3} ): Both incorrect coefficient and radical.
Question: Solve for ( x ) in ( \sqrt{x + 7} = 9 ).- Options: - A) 74 - B) 76 - C) 78 - D) 80
Correct Answer: A) 74
Explanation: Square both sides: ( x + 7 = 81 ), so ( x = 74 ).
Why the Distractors Are Tempting: - B) 76: Close but incorrect.- C) 78: Also close but incorrect.- D) 80: Slightly higher than the correct answer.
Question: What is ( \sqrt{-16} )? - Options: - A) -4 - B) 4i - C) -4i - D) 16i
Correct Answer: B) 4i
Explanation: ( \sqrt{-16} = 4i ) because ( (4i)^2 = -16 ).
Why the Distractors Are Tempting: - A) -4: Incorrect, not considering the imaginary unit.- C) -4i: Incorrect sign.- D) 16i: Incorrect coefficient.
Question: Simplify ( \sqrt{200} ).- Options: - A) ( 10\sqrt{2} ) - B) ( 12\sqrt{2} ) - C) ( 10\sqrt{3} ) - D) ( 12\sqrt{3} )
Correct Answer: A) ( 10\sqrt{2} )
Explanation: ( 200 = 2 \times 10^2 ), so ( \sqrt{200} = 10\sqrt{2} ).
Why the Distractors Are Tempting: - B) ( 12\sqrt{2} ): Incorrect coefficient.- C) ( 10\sqrt{3} ): Incorrect radical.- D) ( 12\sqrt{3} ): Both incorrect coefficient and radical.
Learn the basic concept of roots as the inverse of powers.
Core Rules:
Practice simplifying radicals.
Practice:
Work on problem-solving questions involving roots.
Timed Drills:
Practice under time constraints to improve speed and accuracy.
Mock Tests:
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