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Study Guide: How to Solve: Linear Equations in One Variable
Source: https://www.fatskills.com/reasoning-for-competitive-exams/chapter/how-to-solve-linear-equations-in-one-variable

How to Solve: Linear Equations in One Variable

By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.

⏱️ ~6 min read

How to Solve: Linear Equations in One Variable

(For SSC, Bank, Railway Exams – 1200+ words)


Introduction

"Master linear equations in one variable, and you unlock 5–10 marks in every SSC, Bank, or Railway exam—questions that test your speed, accuracy, and problem-solving under pressure."

(On camera: Hold up a past paper with a highlighted linear equation question.) "This one question type appears in every section—Quantitative Aptitude, Reasoning, even Data Interpretation. If you solve it fast and error-free, you’re already ahead of 80% of test-takers."


What You Need To Know First

Before diving in, ensure you’re comfortable with: 1. Basic arithmetic operations (addition, subtraction, multiplication, division). 2. Balancing equations (whatever you do to one side, you must do to the other). 3. Simplifying expressions (combining like terms, expanding brackets).

(On camera: Point to a whiteboard with these 3 points.) "If any of these feel shaky, pause here and review them first. Linear equations are just these skills in action."


Key Vocabulary

Term Plain-English Definition Quick Example
Linear Equation An equation where the variable (like x) has no exponents (e.g., no ). 3x + 5 = 11 is linear. x² + 2 = 6 is not.
Variable A letter (usually x, y) that stands for an unknown number. In 2x = 10, x is the variable.
Coefficient The number multiplied by the variable. In 4x, 4 is the coefficient.
Constant A plain number (no variable) in the equation. In 5x + 3 = 7, 3 and 7 are constants.
Solution The value of the variable that makes the equation true. For x + 2 = 5, the solution is x = 3.
Transposition Moving a term from one side of the equation to the other (by changing its sign). x + 3 = 7x = 7 – 3.

(On camera: Read each term aloud, then ask:) "Which term do you find most confusing? Let’s clarify it now."


Formulas To Know

(For linear equations in one variable, you don’t need complex formulas—just these rules.)

  1. General Form of a Linear Equation
    ax + b = 0
  2. a = coefficient of x (must not be zero).
  3. b = constant term.
  4. MEMORISE THIS: This is the standard form you’ll see in exams.

  5. Solution Formula
    x = –b/a

  6. Only use this if the equation is in ax + b = 0 form.
  7. MEMORISE THIS: It’s a shortcut for simple equations.

(On camera: Write both formulas on the board.) "You won’t always see ax + b = 0 directly, but if you rearrange any linear equation, it’ll fit this form. The solution is just –b/a."


Step-by-Step Method

(Follow these 5 steps for every linear equation, no matter how complex.)

  1. Simplify Both Sides
  2. Remove brackets (using distributive property: a(b + c) = ab + ac).
  3. Combine like terms (e.g., 3x + 2x = 5x).

  4. Move Variable Terms to One Side, Constants to the Other

  5. Use addition/subtraction to "transpose" terms.
  6. Golden Rule: Change the sign when moving across the equals sign.

  7. Combine Like Terms Again

  8. Simplify both sides until you have ax = b or x = number.

  9. Solve for the Variable

  10. If ax = b, divide both sides by a to get x = b/a.
  11. If x = number, you’re done!

  12. Verify Your Answer

  13. Plug the value back into the original equation.
  14. If both sides are equal, your solution is correct.

(On camera: Demonstrate each step with hand motions—e.g., "move this term to the left" with a sweeping gesture.)


Worked Example Using the Steps

Equation: 3(x + 2) – 4 = 2x + 5

  1. Simplify Both Sides
  2. Expand brackets: 3x + 6 – 4 = 2x + 5
  3. Combine constants: 3x + 2 = 2x + 5

  4. Move Variable Terms to One Side, Constants to the Other

  5. Subtract 2x from both sides: 3x – 2x + 2 = 5x + 2 = 5
  6. Subtract 2 from both sides: x = 5 – 2

  7. Combine Like Terms

  8. x = 3

  9. Solve for the Variable

  10. Already solved: x = 3

  11. Verify

  12. Plug x = 3 into original equation:
    3(3 + 2) – 4 = 2(3) + 53(5) – 4 = 6 + 515 – 4 = 1111 = 11

(On camera: Write each step slowly, narrating aloud.) "See how we followed the exact same 5 steps? No shortcuts—just methodical work."


Worked Examples

Example 1 – Basic

Equation: 5x – 3 = 2x + 9

  1. Subtract 2x from both sides: 3x – 3 = 9
  2. Add 3 to both sides: 3x = 12
  3. Divide by 3: x = 4

What we did and why: - Moved all x terms to the left and constants to the right. - Solved step-by-step to isolate x.


Example 2 – Medium

Equation: 2(3x – 1) + 4 = 5x + 7

  1. Expand brackets: 6x – 2 + 4 = 5x + 7
  2. Combine constants: 6x + 2 = 5x + 7
  3. Subtract 5x: x + 2 = 7
  4. Subtract 2: x = 5

What we did and why: - First simplified the left side by expanding and combining. - Then moved terms to isolate x.


Example 3 – Exam-Style

Question: If 4(x – 2) + 3 = 2(2x + 1), then x = ? (Options: A) 1, B) 2, C) 3, D) 4)

  1. Expand both sides: 4x – 8 + 3 = 4x + 2
  2. Combine constants: 4x – 5 = 4x + 2
  3. Subtract 4x from both sides: –5 = 2
  4. Wait! This is a contradiction—no solution exists.

What we did and why: - The equation simplifies to a false statement (–5 = 2), meaning there’s no solution. - Exam trap: The options might trick you into picking a number, but the answer is "no solution."

(On camera: Circle the contradiction and say:) "This is why verification is crucial! Always plug your answer back in."


Common Mistakes

Mistake Why it Happens Correct Approach
Forgetting to change signs when transposing. Rushes through steps without double-checking. Always flip the sign when moving terms across =.
Not expanding brackets fully. Misapplies distributive property (e.g., 3(x + 2) = 3x + 2). Multiply every term inside the bracket by the outside number.
Dividing before simplifying. Tries to divide ax + b = c directly to x + b/a = c/a. First, move all terms to one side to get ax = b.
Ignoring fractions/decimals. Avoids equations with fractions, leading to errors. Multiply every term by the denominator to eliminate fractions.
Skipping verification. Assumes the answer is correct without checking. Always plug the solution back into the original equation.

(On camera: Hold up a red pen and say:) "These mistakes cost marks. Circle them in your notes and watch out for them in practice."


Exam Traps

Trap How to Spot it How to Avoid it
Equations with no solution. Simplifies to a false statement (e.g., 5 = 2). If you get number = different number, write "no solution."
Equations with infinite solutions. Simplifies to a true statement (e.g., 3 = 3). If you get 0 = 0 or x = x, write "infinite solutions."
Disguised linear equations. Looks like a word problem or ratio (e.g., "The sum of a number and 5 is 12"). Translate words into x + 5 = 12 first.

(On camera: Show a past paper question with one of these traps.) "Examiners love these traps. Train yourself to spot them by practicing with mixed questions."


1-Minute Recap

"Okay, listen up. Linear equations in one variable are all about one thing: isolating x. Here’s how you do it, step by step: 1. Simplify both sides—expand brackets, combine like terms. 2. Move all x terms to one side, constants to the other. Flip the sign when you move anything across the equals sign. 3. Combine again if needed, then solve for x by dividing. 4. Verify by plugging your answer back in. If it doesn’t work, you made a mistake—go back!

Watch out for traps: No solution? Infinite solutions? Fractions? Don’t panic—just follow the steps. And if the equation looks weird, rewrite it in ax + b = 0 form first.

Pro tip: Time yourself. In exams, you’ve got 30–45 seconds per question. Practice until you can solve these in your sleep. You’ve got this!

(On camera: Point to the camera and smile.) "Now go solve 10 practice questions. See you in the top 1%!



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