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Study Guide: How to Solve: Simple Interest Problems
Source: https://www.fatskills.com/reasoning-for-competitive-exams/chapter/how-to-solve-simple-interest-problems

How to Solve: Simple Interest Problems

By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.

⏱️ ~4 min read

How to Solve: Simple Interest Problems

(Complete Guide for SSC / Bank / Railway Exams)


Introduction

"Master simple interest, and you’ll crack 3–5 marks in every SSC, Bank, or Railway exam—money in the bank, literally! (Simple interest questions appear in Quantitative Aptitude sections. Missing them means losing easy marks. This guide ensures you never skip a question again.)


What You Need To Know First

Before diving in, ensure you understand: 1. Percentage basics (e.g., 5% of 200 = 10). 2. Time conversions (e.g., 3 months = 0.25 years). 3. Basic algebra (solving for one variable).


Key Vocabulary

Term Plain-English Definition Quick Example
Principal (P) The initial amount of money borrowed or invested. If you take a loan of ₹5,000, P = ₹5,000.
Interest (I) Extra money paid for borrowing or earned on investment. If you earn ₹200 extra, I = ₹200.
Rate (R) Percentage charged/earned per year. 5% per year means R = 5.
Time (T) Duration for which money is borrowed/invested. 2 years means T = 2.
Amount (A) Total money after interest (Principal + Interest). A = P + I.
Per Annum "Per year" (used for rate). 6% per annum = 6% per year.

Formulas To Know

1. Simple Interest (I)

Formula: I = (P × R × T) / 100 - P = Principal (₹) - R = Rate (% per annum) - T = Time (years) MEMORISE THIS – Not given in most exam sheets!

2. Amount (A)

Formula: A = P + I or A = P (1 + (R × T)/100) MEMORISE THIS – Useful for direct questions.

3. Time in Months/Days

  • If time is in months: T = (Months) / 12
  • If time is in days: T = (Days) / 365 (or 366 for leap year) Given on exam sheet (but know how to use it).

Step-by-Step Method

Follow these exact steps for every simple interest problem:

  1. Read the question carefully. Underline:
  2. Principal (P)
  3. Rate (R)
  4. Time (T)
  5. What is asked (Interest? Amount? Principal? Rate? Time?)

  6. Convert time to years if given in months/days.

  7. Example: 6 months → T = 6/12 = 0.5 years.

  8. Write down the formula you need (I = P×R×T/100 or A = P + I).

  9. Plug in the values and solve.

  10. If a variable is missing (e.g., P is unknown), rearrange the formula.

  11. Check units (₹, %, years). Ensure no mismatches.

  12. Verify your answer by plugging it back into the formula.


Worked Example (Using Steps Above)

Question: Find the simple interest on ₹8,000 at 6% per annum for 9 months.

Step 1: Underline key info. - P = ₹8,000 - R = 6% per annum - T = 9 months - Asked: Simple Interest (I)

Step 2: Convert time to years. - T = 9/12 = 0.75 years

Step 3: Write formula. - I = (P × R × T) / 100

Step 4: Plug in values. - I = (8,000 × 6 × 0.75) / 100 - I = (8,000 × 4.5) / 100 - I = 36,000 / 100 - I = ₹360

Step 5: Check units. - ₹, %, years → Correct.

Step 6: Verify. - (8,000 × 6 × 0.75) / 100 = 360 ✔

Answer: ₹360


Worked Examples

Example 1 – Basic

Question: What is the simple interest on ₹5,000 at 8% per annum for 3 years?

Solution: 1. P = ₹5,000, R = 8%, T = 3 years. 2. T is already in years. 3. I = (P × R × T) / 100 4. I = (5,000 × 8 × 3) / 100 = 1,200 Answer: ₹1,200

What we did and why: - Direct formula application. No conversions needed.


Example 2 – Medium

Question: A sum becomes ₹9,200 in 2 years at 10% simple interest. Find the principal.

Solution: 1. A = ₹9,200, R = 10%, T = 2 years. 2. A = P + I → 9,200 = P + (P × 10 × 2)/100 3. 9,200 = P + (20P)/100 → 9,200 = P + 0.2P 4. 9,200 = 1.2P → P = 9,200 / 1.2 = ₹7,666.67 Answer: ₹7,666.67

What we did and why: - Used A = P + I and rearranged to find P. - Combined terms to solve for one variable.


Example 3 – Exam-Style

Question: A man invests ₹12,000 at 5% simple interest. After how many years will it amount to ₹13,800?

Solution: 1. P = ₹12,000, A = ₹13,800, R = 5%. 2. I = A – P = 13,800 – 12,000 = ₹1,800 3. I = (P × R × T) / 100 → 1,800 = (12,000 × 5 × T) / 100 4. 1,800 = 600T → T = 1,800 / 600 = 3 years Answer: 3 years

What we did and why: - Found I first, then used the formula to solve for T. - Common trick: Amount is given, not interest.


Common Mistakes

Mistake Why it Happens Correct Approach
Ignoring time units Using months/days directly in the formula. Convert time to years first.
Mixing up P and A Using Amount (A) instead of Principal (P). Read carefully: Is it asking for P or A?
Forgetting to divide by 100 Rate is in %, but formula needs decimal. Always divide by 100 in the formula.
Wrong formula for A Using I = P×R×T/100 for Amount. A = P + I, not just I.
Rounding errors Rounding too early (e.g., 0.75 → 0.8). Keep decimals until the final answer.

Exam Traps

Trap How to Spot it How to Avoid it
"Per month" rate given Rate is 2% per month, not per annum. Convert to per annum: 2% × 12 = 24% p.a.
Time in days Question says "90 days" instead of years. T = 90/365 (or 366 for leap year).
Disguised questions "Difference between SI and CI" (but asks only for SI). Focus only on what’s asked.

1-Minute Recap

(Spoken naturally, as if to a student the night before the exam.)

"Listen up—simple interest is your free marks in the exam. Here’s the deal:

  1. Formula: I = P×R×T/100. Memorise it.
  2. Time must be in years. 6 months? 6/12 = 0.5 years. 90 days? 90/365.
  3. Amount = Principal + Interest. If they give you Amount, subtract Principal to get Interest.
  4. Watch for traps: "Per month" rate? Multiply by 12. "Days"? Divide by 365.
  5. Double-check units. ₹, %, years—no mismatches!

That’s it. Do 5 problems tonight, and you’ll own this topic tomorrow. Go crush it!




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