By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
(Complete Guide for SSC / Bank / Railway Exams)
"Master simple interest, and you’ll crack 3–5 marks in every SSC, Bank, or Railway exam—money in the bank, literally! (Simple interest questions appear in Quantitative Aptitude sections. Missing them means losing easy marks. This guide ensures you never skip a question again.)
Before diving in, ensure you understand: 1. Percentage basics (e.g., 5% of 200 = 10). 2. Time conversions (e.g., 3 months = 0.25 years). 3. Basic algebra (solving for one variable).
Formula: I = (P × R × T) / 100 - P = Principal (₹) - R = Rate (% per annum) - T = Time (years) MEMORISE THIS – Not given in most exam sheets!
Formula: A = P + I or A = P (1 + (R × T)/100) MEMORISE THIS – Useful for direct questions.
Follow these exact steps for every simple interest problem:
What is asked (Interest? Amount? Principal? Rate? Time?)
Convert time to years if given in months/days.
Example: 6 months → T = 6/12 = 0.5 years.
Write down the formula you need (I = P×R×T/100 or A = P + I).
Plug in the values and solve.
If a variable is missing (e.g., P is unknown), rearrange the formula.
Check units (₹, %, years). Ensure no mismatches.
Verify your answer by plugging it back into the formula.
Question: Find the simple interest on ₹8,000 at 6% per annum for 9 months.
Step 1: Underline key info. - P = ₹8,000 - R = 6% per annum - T = 9 months - Asked: Simple Interest (I)
Step 2: Convert time to years. - T = 9/12 = 0.75 years
Step 3: Write formula. - I = (P × R × T) / 100
Step 4: Plug in values. - I = (8,000 × 6 × 0.75) / 100 - I = (8,000 × 4.5) / 100 - I = 36,000 / 100 - I = ₹360
Step 5: Check units. - ₹, %, years → Correct.
Step 6: Verify. - (8,000 × 6 × 0.75) / 100 = 360 ✔
Answer: ₹360
Question: What is the simple interest on ₹5,000 at 8% per annum for 3 years?
Solution: 1. P = ₹5,000, R = 8%, T = 3 years. 2. T is already in years. 3. I = (P × R × T) / 100 4. I = (5,000 × 8 × 3) / 100 = 1,200 Answer: ₹1,200
What we did and why: - Direct formula application. No conversions needed.
Question: A sum becomes ₹9,200 in 2 years at 10% simple interest. Find the principal.
Solution: 1. A = ₹9,200, R = 10%, T = 2 years. 2. A = P + I → 9,200 = P + (P × 10 × 2)/100 3. 9,200 = P + (20P)/100 → 9,200 = P + 0.2P 4. 9,200 = 1.2P → P = 9,200 / 1.2 = ₹7,666.67 Answer: ₹7,666.67
What we did and why: - Used A = P + I and rearranged to find P. - Combined terms to solve for one variable.
Question: A man invests ₹12,000 at 5% simple interest. After how many years will it amount to ₹13,800?
Solution: 1. P = ₹12,000, A = ₹13,800, R = 5%. 2. I = A – P = 13,800 – 12,000 = ₹1,800 3. I = (P × R × T) / 100 → 1,800 = (12,000 × 5 × T) / 100 4. 1,800 = 600T → T = 1,800 / 600 = 3 years Answer: 3 years
What we did and why: - Found I first, then used the formula to solve for T. - Common trick: Amount is given, not interest.
(Spoken naturally, as if to a student the night before the exam.)
"Listen up—simple interest is your free marks in the exam. Here’s the deal:
That’s it. Do 5 problems tonight, and you’ll own this topic tomorrow. Go crush it!
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