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Confidence Interval (CI) for One Mean is a range of values, derived from sample statistics, that estimates an unknown population mean with a certain level of confidence. It is expressed as x̄ ± t·(s/√n), where x̄ is the sample mean, t is the critical value from the t-distribution, s is the sample standard deviation, and n is the sample size.
This topic appears in exams to test your understanding of statistical inference and your ability to apply formulas under time pressure. Questions typically involve calculating the CI, interpreting its components, and understanding the assumptions behind it.
This topic is tested in statistics exams, particularly in introductory and intermediate-level courses. It frequently appears in questions worth 5-10 marks. The skill being tested is your ability to perform statistical inference and understand the reliability of sample data.
The primary rule is the formula for the Confidence Interval: x̄ ± t*·(s/√n).
Think of the CI as a target range around the sample mean, where the population mean is likely to be.
Intermediate
Question: A sample of 25 observations has a mean of 50 and a standard deviation of 10. Construct a 95% confidence interval for the population mean.
Step-by-Step: 1. Identify x̄ = 50, s = 10, n = 25.2. Calculate df = 25 - 1 = 24.3. Find t from the t-distribution table for 95% confidence and 24 df (approximately 2.064).4. Calculate the margin of error: 2.064 · (10/√25) = 4.128.5. Construct the CI: 50 ± 4.128*.
Answer: The 95% CI is (45.872, 54.128).
Question: A sample of 30 observations has a mean of 70 and a standard deviation of 15. Construct a 99% confidence interval for the population mean.
Step-by-Step: 1. Identify x̄ = 70, s = 15, n = 30.2. Calculate df = 30 - 1 = 29.3. Find t from the t-distribution table for 99% confidence and 29 df (approximately 2.756).4. Calculate the margin of error: 2.756 · (15/√30) = 6.65.5. Construct the CI: 70 ± 6.65*.
Answer: The 99% CI is (63.35, 76.65).
Question: A sample of 15 observations has a mean of 80 and a standard deviation of 20. Construct a 90% confidence interval for the population mean.
Step-by-Step: 1. Identify x̄ = 80, s = 20, n = 15.2. Calculate df = 15 - 1 = 14.3. Find t from the t-distribution table for 90% confidence and 14 df (approximately 1.761).4. Calculate the margin of error: 1.761 · (20/√15) = 9.23.5. Construct the CI: 80 ± 9.23*.
Answer: The 90% CI is (70.77, 89.23).
Correct Approach: Always use the t-distribution table for small samples.
Mistake: Incorrect degrees of freedom.
Correct Approach: Always calculate df = n - 1.
Mistake: Misinterpreting the confidence level.
Correct Approach: Understand that 95% confidence means 95% of such intervals will contain the population mean.
Mistake: Ignoring the sample size assumption.
Favored By: Introductory stats exams.
Interpretation Questions: Ask about the meaning of the CI components.
Favored By: Intermediate stats exams.
Multiple-Choice Questions: Provide options for the CI or its components.
Question: What is the critical value t for a 95% confidence interval with 20 degrees of freedom? Options*: A. 1.725 B. 2.086 C. 2.528 D. 2.845
Correct Answer: B. 2.086 Explanation: The t-distribution table gives t ≈ 2.086 for 95% confidence and 20 df.Why the Distractors Are Tempting*: Other values are for different confidence levels or df.
Question: A sample of 16 observations has a mean of 60 and a standard deviation of 12. What is the margin of error for a 90% confidence interval? Options: A. 5.88 B. 6.24 C. 7.02 D. 7.56
Correct Answer: A. 5.88 Explanation: t ≈ 1.746 for 90% confidence and 15 df. Margin of error = 1.746 · (12/√16) = 5.88.Why the Distractors Are Tempting*: Incorrect t-values or standard error calculations.
Question: What is the degrees of freedom for a sample size of 25? Options: A. 24 B. 25 C. 26 D. 23
Correct Answer: A. 24 Explanation: df = n - 1 = 25 - 1 = 24.Why the Distractors Are Tempting: Common miscalculations.
Question: A sample of 30 observations has a mean of 70 and a standard deviation of 15. What is the 95% confidence interval for the population mean? Options: A. (66.25, 73.75) B. (65.50, 74.50) C. (64.75, 75.25) D. (64.00, 76.00)
Correct Answer: B. (65.50, 74.50) Explanation: t ≈ 2.045 for 95% confidence and 29 df. CI = 70 ± 2.045 · (15/√30) = 70 ± 4.50.Why the Distractors Are Tempting*: Incorrect t-values or margin of error calculations.
Question: What assumption is necessary for constructing a confidence interval for a small sample size? Options: A. The population is normally distributed B. The sample size is large C. The standard deviation is known D. The mean is zero
Correct Answer: A. The population is normally distributed Explanation: For small samples, the population must be normally distributed.Why the Distractors Are Tempting: Other assumptions are for different scenarios.
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