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Binomial Distribution is a discrete probability distribution that describes the number of successes in a fixed number of independent Bernoulli trials with the same probability of success. It appears in exams to test your understanding of probability, statistics, and your ability to apply formulas under time pressure. Typical questions involve calculating probabilities, means, and standard deviations.
Binomial Distribution is tested in various statistics and probability exams, including AP Statistics, GRE, and job interviews for data analyst roles. It frequently appears and can carry significant marks. This topic tests your ability to apply statistical formulas and understand probability concepts.
Primary Rule: The probability of getting exactly k successes in n trials is given by the formula: [ P(X = k) = \binom{n}{k} p^k q^{n-k} ] where (\binom{n}{k}) is the binomial coefficient, calculated as (\frac{n!}{k!(n-k)!}).
Sub-rules:
The distribution is symmetric when p = 0.5.
Mnemonic: Think of flipping a coin n times; p is the chance of heads, and q is the chance of tails.
Intermediate
Question: If a fair coin is tossed 5 times, what is the probability of getting exactly 3 heads?
Step-by-Step: 1. Identify parameters: n = 5, p = 0.5, q = 0.5, k = 3.2. Use the binomial probability formula: [ P(X = 3) = \binom{5}{3} (0.5)^3 (0.5)^{5-3} ] 3. Calculate (\binom{5}{3} = \frac{5!}{3!2!} = 10).4. Substitute and simplify: [ P(X = 3) = 10 * (0.5)^3 * (0.5)^2 = 10 * 0.03125 = 0.3125 ]
Answer: 0.3125
Question: A drug trial has a 70% success rate. If 10 patients are treated, what is the probability that exactly 6 will be successfully treated?
Step-by-Step: 1. Identify parameters: n = 10, p = 0.7, q = 0.3, k = 6.2. Use the binomial probability formula: [ P(X = 6) = \binom{10}{6} (0.7)^6 (0.3)^4 ] 3. Calculate (\binom{10}{6} = \frac{10!}{6!4!} = 210).4. Substitute and simplify: [ P(X = 6) = 210 * (0.7)^6 * (0.3)^4 = 210 * 0.0540225 = 0.23939625 ]
Answer: 0.23939625
Question: A factory produces light bulbs with a 5% defect rate. If a batch of 20 light bulbs is tested, what is the probability that exactly 2 are defective?
Step-by-Step: 1. Identify parameters: n = 20, p = 0.05, q = 0.95, k = 2.2. Use the binomial probability formula: [ P(X = 2) = \binom{20}{2} (0.05)^2 (0.95)^{18} ] 3. Calculate (\binom{20}{2} = \frac{20!}{2!18!} = 190).4. Substitute and simplify: [ P(X = 2) = 190 * (0.05)^2 * (0.95)^{18} = 190 * 0.0025 * 0.37739 = 0.17901125 ]
Answer: 0.17901125
Correct Approach: Always include (\binom{n}{k}).
Mistake: Confusing p and q.
Correct Approach: Remember q = 1 - p.
Mistake: Incorrectly calculating factorials.
Correct Approach: Use a calculator or double-check factorial calculations.
Mistake: Not recognizing when to use the binomial distribution.
Favored By: AP Statistics, GRE
Short Answer:
Favored By: University exams
Problem-Solving:
Question: If a fair coin is tossed 3 times, what is the probability of getting exactly 2 heads? Options: A) 0.25 B) 0.375 C) 0.5 D) 0.75
Correct Answer: B) 0.375 Explanation: Use the binomial probability formula: [ P(X = 2) = \binom{3}{2} (0.5)^2 (0.5)^1 = 3 * 0.125 = 0.375 ] Why the Distractors Are Tempting: - A) Looks like a common fraction.- C) Might seem reasonable without calculation.- D) Too high for a probability.
Question: A test has a 60% pass rate. If 5 students take the test, what is the probability that exactly 3 will pass? Options: A) 0.3456 B) 0.486 C) 0.512 D) 0.648
Correct Answer: A) 0.3456 Explanation: Use the binomial probability formula: [ P(X = 3) = \binom{5}{3} (0.6)^3 (0.4)^2 = 10 * 0.216 * 0.16 = 0.3456 ] Why the Distractors Are Tempting: - B) Close to the correct value.- C) Might seem plausible without calculation.- D) Too high for a probability.
Question: A machine produces defective items with a 2% defect rate. If 50 items are produced, what is the probability that exactly 1 is defective? Options: A) 0.2704 B) 0.308 C) 0.368 D) 0.408
Correct Answer: B) 0.308 Explanation: Use the binomial probability formula: [ P(X = 1) = \binom{50}{1} (0.02)^1 (0.98)^{49} = 50 * 0.02 * 0.603 = 0.308 ] Why the Distractors Are Tempting: - A) Close to the correct value.- C) Might seem plausible without calculation.- D) Too high for a probability.
Question: A drug has an 80% effectiveness rate. If 10 patients are treated, what is the probability that exactly 7 will be successfully treated? Options: A) 0.201 B) 0.230 C) 0.266 D) 0.301
Correct Answer: B) 0.230 Explanation: Use the binomial probability formula: [ P(X = 7) = \binom{10}{7} (0.8)^7 (0.2)^3 = 120 * 0.2097152 * 0.008 = 0.230 ] Why the Distractors Are Tempting: - A) Close to the correct value.- C) Might seem plausible without calculation.- D) Too high for a probability.
Question: A factory produces items with a 1% defect rate. If 100 items are produced, what is the probability that exactly 2 are defective? Options: A) 0.184 B) 0.202 C) 0.230 D) 0.260
Correct Answer: A) 0.184 Explanation: Use the binomial probability formula: [ P(X = 2) = \binom{100}{2} (0.01)^2 (0.99)^{98} = 4950 * 0.0001 * 0.371 = 0.184 ] Why the Distractors Are Tempting: - B) Close to the correct value.- C) Might seem plausible without calculation.- D) Too high for a probability.
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