By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Complete Guide
"Master standing waves, Doppler shifts, and interference, and you’ll unlock 15–20% of your IB Physics Paper 2—plus real-world applications like ultrasound imaging, musical instruments, and even how bats hunt in the dark."
Formulas: 1. Standing wave on a string (fixed ends): L = n(λ/2) (n = 1, 2, 3…) - L = length of string (m) - λ = wavelength (m) - n = harmonic number (1 = fundamental, 2 = 1st overtone, etc.) - MEMORISE THIS
MEMORISE THIS
Wave speed on a string: v = √(T/μ)
Formula: f′ = f(v ± vₒ)/(v ∓ vₛ) - f′ = observed frequency (Hz) - f = emitted frequency (Hz) - v = speed of wave in medium (m/s) (e.g., 340 m/s for sound in air) - vₒ = speed of observer (m/s) (+ if moving toward source, – if moving away) - vₛ = speed of source (m/s) (– if moving toward observer, + if moving away) - GIVEN ON EXAM SHEET (but you must know how to apply signs!)
Formulas: 1. Path difference for constructive interference: Δx = nλ (n = 0, 1, 2…) - MEMORISE THIS
Double-slit interference (maxima): d sinθ = nλ
GIVEN ON EXAM SHEET
Double-slit interference (minima): d sinθ = (n + ½)λ
Example: 1 loop = n=1 (fundamental), 2 loops = n=2 (1st overtone).
Write the standing wave equation:
L = n(λ/2)
Solve for wavelength (λ):
Rearrange: λ = 2L/n
Find frequency (f) using wave speed (v):
f = v/λ (or use fₙ = n(v/2L) for harmonics)
Check units and reasonableness:
Use arrows to show direction of motion.
Assign signs to vₒ and vₛ:
Source moving away: +vₛ (increases denominator)
Plug into Doppler formula:
f′ = f(v ± vₒ)/(v ∓ vₛ)
Simplify and solve for f′.
Check if answer makes sense:
Slit separation (d), wavelength (λ), order (n), distance to screen (D), fringe spacing (Δy).
Determine if it’s a maximum or minimum:
Minima: d sinθ = (n + ½)λ
For small angles (θ < 10°), use:
So, d(Δy/D) = nλ → Δy = nλD/d
Solve for unknown (Δy, d, λ, etc.).
A guitar string of length 0.65 m vibrates at its 3rd harmonic. The wave speed on the string is 260 m/s. Calculate the wavelength and frequency of this harmonic.
Step-by-Step: 1. Harmonic number (n): 3rd harmonic → n = 3. 2. Standing wave equation: L = n(λ/2) - 0.65 = 3(λ/2) 3. Solve for λ: - λ = (2 × 0.65)/3 = 0.433 m 4. Find frequency (f): - f = v/λ = 260/0.433 = 600 Hz (or use fₙ = n(v/2L) = 3(260/(2×0.65)) = 600 Hz)
What we did and why: - Used L = n(λ/2) to find λ because the string has fixed ends. - Used f = v/λ to find frequency because wave speed is constant.
A police car emits a siren at 800 Hz while moving toward a stationary observer at 30 m/s. The speed of sound is 340 m/s. What frequency does the observer hear?
Step-by-Step: 1. Diagram: - Source (S) moving toward observer (O) at 30 m/s. - Observer is stationary → vₒ = 0. 2. Doppler formula: - f′ = f(v)/(v – vₛ) (source moving toward → –vₛ) - f′ = 800(340)/(340 – 30) 3. Calculate: - f′ = 800 × 340 / 310 = 877 Hz
What we did and why: - Used –vₛ because the source is moving toward the observer (reduces denominator). - Check: Moving toward → higher frequency (877 Hz > 800 Hz).
In a double-slit experiment, light of wavelength 500 nm passes through slits separated by 0.2 mm. The screen is 1.5 m away. Calculate the distance between the 2nd and 3rd bright fringes.
Step-by-Step: 1. Identify: - λ = 500 nm = 5 × 10⁻⁷ m - d = 0.2 mm = 2 × 10⁻⁴ m - D = 1.5 m - n = 2 and 3 (bright fringes) 2. Fringe spacing formula: - Δy = nλD/d 3. Calculate y₂ and y₃: - y₂ = 2 × 5 × 10⁻⁷ × 1.5 / 2 × 10⁻⁴ = 0.0075 m - y₃ = 3 × 5 × 10⁻⁷ × 1.5 / 2 × 10⁻⁴ = 0.01125 m 4. Distance between fringes: - Δy = y₃ – y₂ = 0.01125 – 0.0075 = 0.00375 m (3.75 mm)
What we did and why: - Used Δy = nλD/d because we’re dealing with small angles (θ < 10°). - Calculated positions of n=2 and n=3 separately, then found the difference.
MISTAKE: Forgetting to convert units (e.g., mm → m, nm → m). WHY IT HAPPENS: Students rush and overlook unit prefixes. CORRECT APPROACH: Always convert to meters before plugging into formulas.
MISTAKE: Mixing up signs in the Doppler formula. WHY IT HAPPENS: Confusion about whether to add or subtract vₒ/vₛ. CORRECT APPROACH: Draw a diagram and label directions. Toward = +vₒ or –vₛ.
MISTAKE: Using the wrong harmonic number (n). WHY IT HAPPENS: Misidentifying loops in a standing wave diagram. CORRECT APPROACH: Count half-wavelengths (loops) to find n.
MISTAKE: Assuming all interference is constructive. WHY IT HAPPENS: Forgetting that path difference determines interference type. CORRECT APPROACH: Check if Δx = nλ (constructive) or (n + ½)λ (destructive).
MISTAKE: Ignoring the wave speed formula for standing waves. WHY IT HAPPENS: Trying to solve for frequency without knowing v = √(T/μ). CORRECT APPROACH: If tension or mass density is given, calculate v first.
TRAP: Doppler effect with both source and observer moving. HOW TO SPOT IT: Question mentions "car moving toward a moving observer." HOW TO AVOID IT: Assign signs separately to vₒ and vₛ. Draw a diagram!
TRAP: Standing waves in open pipes (not fixed ends). HOW TO SPOT IT: Question says "open at both ends" or shows antinodes at both ends. HOW TO AVOID IT: Use L = n(λ/2) for both ends open (same as fixed ends), but L = (2n + 1)(λ/4) for one end open.
TRAP: Interference with white light (multiple wavelengths). HOW TO SPOT IT: Question mentions "colored fringes" or "central white fringe." HOW TO AVOID IT: Remember:
"Here’s your 60-second survival guide for Waves & Oscillations: 1. Standing waves: Count loops → n → L = n(λ/2) → f = n(v/2L). Memorize the harmonic formula! 2. Doppler effect: Draw a diagram, assign signs (+ for toward, – for away), plug into f′ = f(v ± vₒ)/(v ∓ vₛ). 3. Interference: Path difference = nλ (constructive) or (n + ½)λ (destructive). For double-slit, use d sinθ = nλ or Δy = nλD/d. 4. Units: Always convert to meters. Always. 5. Check your answer: Higher harmonic = higher frequency. Moving toward = higher pitch. Larger slit separation = smaller fringe spacing. You’ve got this. Now go ace that exam!
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