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Study Guide: IB Physics How to Solve: IB Physics – Waves & Oscillations (Standing Waves, Doppler, Interference)
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IB Physics How to Solve: IB Physics – Waves & Oscillations (Standing Waves, Doppler, Interference)

By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.

⏱️ ~6 min read

How to Solve: IB Physics – Waves & Oscillations (Standing Waves, Doppler, Interference)

Complete Guide


Introduction

"Master standing waves, Doppler shifts, and interference, and you’ll unlock 15–20% of your IB Physics Paper 2—plus real-world applications like ultrasound imaging, musical instruments, and even how bats hunt in the dark."


WHAT YOU NEED TO KNOW FIRST

  1. Wave basics: Amplitude, wavelength, frequency, speed, and the wave equation v = fλ.
  2. Superposition principle: When two waves meet, their displacements add algebraically.
  3. Phase difference: Measured in degrees or radians; determines constructive/destructive interference.

KEY TERMS & FORMULAS

Standing Waves

Term Definition
Node Point of zero displacement (destructive interference).
Antinode Point of maximum displacement (constructive interference).
Fundamental frequency (f₁) Lowest frequency at which a standing wave forms.
Harmonic Integer multiple of the fundamental frequency (e.g., 2f₁, 3f₁).

Formulas: 1. Standing wave on a string (fixed ends):
L = n(λ/2) (n = 1, 2, 3…)
- L = length of string (m)
- λ = wavelength (m)
- n = harmonic number (1 = fundamental, 2 = 1st overtone, etc.)
- MEMORISE THIS

  1. Frequency of nth harmonic:
    fₙ = n(v/2L)
  2. fₙ = frequency of nth harmonic (Hz)
  3. v = wave speed on string (m/s)
  4. L = length of string (m)
  5. MEMORISE THIS

  6. Wave speed on a string:
    v = √(T/μ)

  7. T = tension in string (N)
  8. μ = linear mass density (kg/m) (μ = mass/length)
  9. MEMORISE THIS

Doppler Effect

Term Definition
Doppler shift Change in observed frequency due to relative motion between source and observer.
Redshift Increase in wavelength (decrease in frequency) when source moves away.
Blueshift Decrease in wavelength (increase in frequency) when source moves toward.

Formula: f′ = f(v ± vₒ)/(v ∓ vₛ) - f′ = observed frequency (Hz) - f = emitted frequency (Hz) - v = speed of wave in medium (m/s) (e.g., 340 m/s for sound in air) - vₒ = speed of observer (m/s) (+ if moving toward source, – if moving away) - vₛ = speed of source (m/s) (– if moving toward observer, + if moving away) - GIVEN ON EXAM SHEET (but you must know how to apply signs!)


Interference

Term Definition
Path difference (Δx) Difference in distance traveled by two waves from their sources to a point.
Constructive interference Waves in phase → amplitudes add (Δx = nλ).
Destructive interference Waves out of phase → amplitudes cancel (Δx = (n + ½)λ).

Formulas: 1. Path difference for constructive interference:
Δx = nλ (n = 0, 1, 2…)
- MEMORISE THIS

  1. Path difference for destructive interference:
    Δx = (n + ½)λ (n = 0, 1, 2…)
  2. MEMORISE THIS

  3. Double-slit interference (maxima):
    d sinθ = nλ

  4. d = slit separation (m)
  5. θ = angle to nth maximum
  6. n = order of maximum (0, 1, 2…)
  7. GIVEN ON EXAM SHEET

  8. Double-slit interference (minima):
    d sinθ = (n + ½)λ

  9. GIVEN ON EXAM SHEET

STEP-BY-STEP METHOD

Standing Waves (Fixed Ends)

  1. Identify the harmonic number (n):
  2. Count the number of loops (half-wavelengths) in the diagram.
  3. Example: 1 loop = n=1 (fundamental), 2 loops = n=2 (1st overtone).

  4. Write the standing wave equation:

  5. L = n(λ/2)

  6. Solve for wavelength (λ):

  7. Rearrange: λ = 2L/n

  8. Find frequency (f) using wave speed (v):

  9. f = v/λ (or use fₙ = n(v/2L) for harmonics)

  10. Check units and reasonableness:

  11. Higher harmonics → shorter λ → higher f.

Doppler Effect

  1. Draw a diagram:
  2. Label source (S), observer (O), and their velocities.
  3. Use arrows to show direction of motion.

  4. Assign signs to vₒ and vₛ:

  5. Observer moving toward source: +vₒ
  6. Observer moving away: –vₒ
  7. Source moving toward observer: –vₛ (reduces denominator)
  8. Source moving away: +vₛ (increases denominator)

  9. Plug into Doppler formula:

  10. f′ = f(v ± vₒ)/(v ∓ vₛ)

  11. Simplify and solve for f′.

  12. Check if answer makes sense:

  13. Moving toward → higher f (blueshift).
  14. Moving away → lower f (redshift).

Interference (Double-Slit)

  1. Identify given values:
  2. Slit separation (d), wavelength (λ), order (n), distance to screen (D), fringe spacing (Δy).

  3. Determine if it’s a maximum or minimum:

  4. Maxima: d sinθ = nλ
  5. Minima: d sinθ = (n + ½)λ

  6. For small angles (θ < 10°), use:

  7. sinθ ≈ tanθ = Δy/D
  8. So, d(Δy/D) = nλΔy = nλD/d

  9. Solve for unknown (Δy, d, λ, etc.).

  10. Check units and reasonableness:

  11. Larger d → smaller fringe spacing (Δy).
  12. Larger λ → larger fringe spacing.

WORKED EXAMPLES

Example 1 – Standing Waves (Basic)

A guitar string of length 0.65 m vibrates at its 3rd harmonic. The wave speed on the string is 260 m/s. Calculate the wavelength and frequency of this harmonic.

Step-by-Step: 1. Harmonic number (n): 3rd harmonic → n = 3. 2. Standing wave equation: L = n(λ/2)
- 0.65 = 3(λ/2) 3. Solve for λ:
- λ = (2 × 0.65)/3 = 0.433 m 4. Find frequency (f):
- f = v/λ = 260/0.433 = 600 Hz
(or use fₙ = n(v/2L) = 3(260/(2×0.65)) = 600 Hz)

What we did and why: - Used L = n(λ/2) to find λ because the string has fixed ends. - Used f = v/λ to find frequency because wave speed is constant.


Example 2 – Doppler Effect (Medium)

A police car emits a siren at 800 Hz while moving toward a stationary observer at 30 m/s. The speed of sound is 340 m/s. What frequency does the observer hear?

Step-by-Step: 1. Diagram:
- Source (S) moving toward observer (O) at 30 m/s.
- Observer is stationary → vₒ = 0. 2. Doppler formula:
- f′ = f(v)/(v – vₛ) (source moving toward → –vₛ)
- f′ = 800(340)/(340 – 30) 3. Calculate:
- f′ = 800 × 340 / 310 = 877 Hz

What we did and why: - Used –vₛ because the source is moving toward the observer (reduces denominator). - Check: Moving toward → higher frequency (877 Hz > 800 Hz).


Example 3 – Interference (Exam-Style)

In a double-slit experiment, light of wavelength 500 nm passes through slits separated by 0.2 mm. The screen is 1.5 m away. Calculate the distance between the 2nd and 3rd bright fringes.

Step-by-Step: 1. Identify:
- λ = 500 nm = 5 × 10⁻⁷ m
- d = 0.2 mm = 2 × 10⁻⁴ m
- D = 1.5 m
- n = 2 and 3 (bright fringes) 2. Fringe spacing formula:
- Δy = nλD/d 3. Calculate y₂ and y₃:
- y₂ = 2 × 5 × 10⁻⁷ × 1.5 / 2 × 10⁻⁴ = 0.0075 m
- y₃ = 3 × 5 × 10⁻⁷ × 1.5 / 2 × 10⁻⁴ = 0.01125 m 4. Distance between fringes:
- Δy = y₃ – y₂ = 0.01125 – 0.0075 = 0.00375 m (3.75 mm)

What we did and why: - Used Δy = nλD/d because we’re dealing with small angles (θ < 10°). - Calculated positions of n=2 and n=3 separately, then found the difference.


COMMON MISTAKES

  1. MISTAKE: Forgetting to convert units (e.g., mm → m, nm → m).
    WHY IT HAPPENS: Students rush and overlook unit prefixes.
    CORRECT APPROACH: Always convert to meters before plugging into formulas.

  2. MISTAKE: Mixing up signs in the Doppler formula.
    WHY IT HAPPENS: Confusion about whether to add or subtract vₒ/vₛ.
    CORRECT APPROACH: Draw a diagram and label directions. Toward = +vₒ or –vₛ.

  3. MISTAKE: Using the wrong harmonic number (n).
    WHY IT HAPPENS: Misidentifying loops in a standing wave diagram.
    CORRECT APPROACH: Count half-wavelengths (loops) to find n.

  4. MISTAKE: Assuming all interference is constructive.
    WHY IT HAPPENS: Forgetting that path difference determines interference type.
    CORRECT APPROACH: Check if Δx = nλ (constructive) or (n + ½)λ (destructive).

  5. MISTAKE: Ignoring the wave speed formula for standing waves.
    WHY IT HAPPENS: Trying to solve for frequency without knowing v = √(T/μ).
    CORRECT APPROACH: If tension or mass density is given, calculate v first.


EXAM TRAPS

  1. TRAP: Doppler effect with both source and observer moving.
    HOW TO SPOT IT: Question mentions "car moving toward a moving observer."
    HOW TO AVOID IT: Assign signs separately to vₒ and vₛ. Draw a diagram!

  2. TRAP: Standing waves in open pipes (not fixed ends).
    HOW TO SPOT IT: Question says "open at both ends" or shows antinodes at both ends.
    HOW TO AVOID IT: Use L = n(λ/2) for both ends open (same as fixed ends), but L = (2n + 1)(λ/4) for one end open.

  3. TRAP: Interference with white light (multiple wavelengths).
    HOW TO SPOT IT: Question mentions "colored fringes" or "central white fringe."
    HOW TO AVOID IT: Remember:

  4. Central fringe (n=0) is white (all λ constructively interfere).
  5. Higher-order fringes show spectral separation (red farther out than blue).

1-MINUTE RECAP

"Here’s your 60-second survival guide for Waves & Oscillations: 1. Standing waves: Count loops → n → L = n(λ/2) → f = n(v/2L). Memorize the harmonic formula! 2. Doppler effect: Draw a diagram, assign signs (+ for toward, – for away), plug into f′ = f(v ± vₒ)/(v ∓ vₛ). 3. Interference: Path difference = nλ (constructive) or (n + ½)λ (destructive). For double-slit, use d sinθ = nλ or Δy = nλD/d. 4. Units: Always convert to meters. Always. 5. Check your answer: Higher harmonic = higher frequency. Moving toward = higher pitch. Larger slit separation = smaller fringe spacing. You’ve got this. Now go ace that exam!




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