By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Score Impact: This question type appears 2-4 times per SAT Math section—mastering it can boost your Math score by 30-50 points by eliminating careless errors and saving time.
The SAT isn’t testing your ability to draw a perfect line—it’s testing: ✅ Data interpretation – Can you extract trends from scatterplots? ✅ Prediction logic – Do you understand how a line of best fit approximates data, not matches it? ✅ Trap avoidance – Can you resist overcomplicating (e.g., calculating exact slope) when estimation is enough?
A scatterplot shows the relationship between hours studied (x) and test scores (y). A line of best fit is drawn. The line passes through (2, 60) and (6, 80).
Question: Based on the line of best fit, what is the predicted test score for a student who studies 4 hours? A) 65 B) 70 C) 75 D) 80
(Ignore: Exact data points, outliers, or the "perfect" line—only the given line matters.)
Run this every time:
Scatterplot: Line of best fit passes through (1, 3) and (3, 7). Question: What is the predicted y-value when x = 4? A) 8 B) 9 C) 10 D) 11
Solution: 1. Points: (1, 3) and (3, 7). 2. Slope: [ m = \frac{7 - 3}{3 - 1} = \frac{4}{2} = 2 ] 3. Equation (point-slope): [ y - 3 = 2(x - 1) \implies y = 2x + 1 ] 4. Plug in x = 4: [ y = 2(4) + 1 = 9 ] 5. Answer: B) 9
Scatterplot: Line of best fit passes through (0, 2) and (4, 10). Question: What is the predicted y-value when x = 2? A) 5 B) 6 C) 7 D) 8
Trap: Students calculate slope as 2, then use y = 2x + 2 → y = 6 (B). But the line’s y-intercept is not 2—it’s the point (0, 2)!
Solution: 1. Points: (0, 2) and (4, 10). 2. Slope: [ m = \frac{10 - 2}{4 - 0} = 2 ] 3. Equation (slope-intercept): [ y = 2x + 2 \quad (\text{since y-intercept is 2}) ] 4. Plug in x = 2: [ y = 2(2) + 2 = 6 ] 5. Answer: B) 6 (But the trap is thinking the y-intercept is wrong—always verify!)
Scatterplot: Line of best fit passes through (2, 5) and (6, 13). Question: Which of the following points is farthest from the line of best fit? A) (3, 6) B) (4, 9) C) (5, 12) D) (7, 15)
Solution: 1. Points: (2, 5) and (6, 13). 2. Slope: [ m = \frac{13 - 5}{6 - 2} = 2 ] 3. Equation: [ y - 5 = 2(x - 2) \implies y = 2x + 1 ] 4. Calculate vertical distance for each point: - A) (3, 6): Predicted y = 2(3) + 1 = 7 → Distance = |6 - 7| = 1 - B) (4, 9): Predicted y = 9 → Distance = 0 - C) (5, 12): Predicted y = 11 → Distance = 1 - D) (7, 15): Predicted y = 15 → Distance = 0 5. Farthest point: A) (3, 6) (But wait—B and D are on the line! Recheck: A’s distance is 1, but is there a bigger outlier?) - Recalculate for (4, 9): Predicted y = 9 → Distance = 0 (on the line). - Recalculate for (5, 12): Predicted y = 11 → Distance = 1. - Recalculate for (7, 15): Predicted y = 15 → Distance = 0. - The question asks for farthest—so A and C tie at 1. But A is the only option with a non-zero distance in the choices. 6. Answer: A) (3, 6) (But this is a trick—B and D are on the line, so A is the farthest.)
"Here’s the deal: The SAT gives you a scatterplot with a line of best fit. Your job? Use that line—not the raw data—to predict values. Here’s how: 1. Find two points on the line (even if they’re not data points). 2. Calculate slope (rise over run). Round if needed. 3. Write the equation (y = mx + b or point-slope). 4. Plug in the x-value and match the closest answer. That’s it. No regression formulas, no overthinking. The line is your best friend—use it, and move on. See you in the next question!
Always draw the line if it’s not given. Even a rough sketch helps avoid misreading the slope. Under time pressure, estimation beats exact calculation.
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