Fatskills
Practice. Master. Repeat.
Study Guide: SAT / PSAT: SAT PSAT Math Advanced Math Nonlinear Functions Exponential Growth and Decay yabx
Source: https://www.fatskills.com/sat/chapter/sat-psat-sat-psat-math-advanced-math-nonlinear-functions-exponential-growth-and-decay-yabx

SAT / PSAT: SAT PSAT Math Advanced Math Nonlinear Functions Exponential Growth and Decay yabx

By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.

⏱️ ~5 min read

What Is This?

Exponential growth and decay describe processes where a quantity increases or decreases at a rate proportional to its current value. This topic appears in exams to test your understanding of nonlinear functions and their applications in real-world scenarios like population growth, radioactive decay, and financial compounding.

Why It Matters

Exponential functions are tested in various exams, including: - SAT Math Level 2
- AP Calculus
- ACT Math
- GRE Quantitative

They frequently appear and can carry significant marks, testing your ability to understand and apply nonlinear relationships.

Core Concepts

  1. Exponential Growth: A quantity increases at a constant rate relative to its current size.
  2. Exponential Decay: A quantity decreases at a constant rate relative to its current size.
  3. Formula: The general form is ( y = ab^x ), where ( a ) is the initial amount, ( b ) is the growth or decay factor, and ( x ) is the time or input variable.
  4. Base Distinctions: Understand the difference between ( b > 1 ) (growth) and ( 0 < b < 1 ) (decay).
  5. Graph Behavior: Exponential growth curves upward, while decay curves downward.

Prerequisites

  1. Understanding of Linear Functions: Know the basics of linear growth and decay.
  2. Basic Algebra: Be comfortable with manipulating equations and solving for variables.
  3. Graph Interpretation: Be able to read and interpret basic graphs.

The Rule-Book (How It Works)

  • Primary Rule: ( y = ab^x )
  • ( a ): Initial amount
  • ( b ): Growth or decay factor
  • ( x ): Time or input variable
  • Sub-rules:
  • For growth, ( b > 1 )
  • For decay, ( 0 < b < 1 )
  • Visual Pattern: Think of a curve that either steeply rises (growth) or flattens out (decay).

Exam / Job / Audit Weighting

  • Frequency: Moderate to High
  • Difficulty Rating: Intermediate
  • Question Type: Multiple choice, short answer, or problem-solving

Difficulty Level

Intermediate

Must-Know Rules, Formulas, Standards, or Principles

  1. Exponential Growth Formula: ( y = ab^x ) where ( b > 1 )
  2. Exponential Decay Formula: ( y = ab^x ) where ( 0 < b < 1 )
  3. Half-Life Formula: For decay, ( t_{1/2} = \frac{\ln(2)}{\ln(b)} )

Worked Examples (Step-by-Step)


Easy

Question: If a population grows according to the formula ( P = 100 \times 2^t ), where ( t ) is in years, what is the population after 3 years? 1. Identify ( a = 100 ), ( b = 2 ), and ( t = 3 ).
2. Substitute into the formula: ( P = 100 \times 2^3 ).
3. Calculate: ( P = 100 \times 8 = 800 ).

Answer: 800

Medium

Question: A radioactive substance decays according to the formula ( N = N_0 \times 0.5^t ), where ( t ) is in hours. If the initial amount ( N_0 ) is 1000 grams, how much remains after 4 hours? 1. Identify ( N_0 = 1000 ), ( b = 0.5 ), and ( t = 4 ).
2. Substitute into the formula: ( N = 1000 \times 0.5^4 ).
3. Calculate: ( N = 1000 \times 0.0625 = 62.5 ) grams.

Answer: 62.5 grams

Hard

Question: If a substance decays with a half-life of 2 years, what percentage of the original amount remains after 6 years? 1. Identify the half-life ( t_{1/2} = 2 ) years.
2. Use the half-life formula: ( b = e^{\frac{\ln(0.5)}{2}} ).
3. Calculate ( b ): ( b = e^{-0.3466} \approx 0.7071 ).
4. Substitute into the decay formula: ( N = N_0 \times 0.7071^6 ).
5. Calculate: ( N = N_0 \times 0.1111 ).
6. Convert to percentage: ( 0.1111 \times 100 = 11.11\% ).

Answer: 11.11%

Common Exam Traps & Mistakes

  1. Mistake: Confusing growth and decay factors.
  2. Wrong Answer: Using ( b > 1 ) for decay.
  3. Correct Approach: Ensure ( 0 < b < 1 ) for decay.
  4. Mistake: Incorrectly applying the half-life formula.
  5. Wrong Answer: Using ( t_{1/2} = \frac{\ln(2)}{b} ).
  6. Correct Approach: Use ( t_{1/2} = \frac{\ln(2)}{\ln(b)} ).
  7. Mistake: Forgetting to convert time units.
  8. Wrong Answer: Using years instead of hours.
  9. Correct Approach: Always check the units.
  10. Mistake: Misinterpreting the initial amount ( a ).
  11. Wrong Answer: Using a different initial value.
  12. Correct Approach: Ensure ( a ) is the starting quantity.

Shortcut Strategies & Exam Hacks

  • Memory Aid: Remember "Growth is greater than 1, Decay is less than 1."
  • Elimination Strategy: If a choice results in an impossible value (e.g., negative population), eliminate it.
  • Pattern Recognition: Look for exponential curves on graphs to quickly identify growth or decay.

Question-Type Taxonomy

  1. Multiple Choice: Choose the correct value or formula.
  2. Example: What is the population after 3 years if ( P = 100 \times 2^t )?
  3. Favored By: SAT, ACT
  4. Short Answer: Calculate and provide a numerical answer.
  5. Example: How much of a substance remains after 4 hours if ( N = 1000 \times 0.5^t )?
  6. Favored By: AP Calculus
  7. Problem-Solving: Apply the formula to a real-world scenario.
  8. Example: What percentage remains after 6 years with a half-life of 2 years?
  9. Favored By: GRE

Practice Set (MCQs)


Question 1

Question: If a population grows according to ( P = 50 \times 3^t ), what is the population after 2 years? - A: 150 - B: 450 - C: 900 - D: 1350

Correct Answer: B Explanation: ( P = 50 \times 3^2 = 50 \times 9 = 450 ) Why the Distractors Are Tempting: - A: Confuses the exponent.
- C: Miscalculates the multiplication.
- D: Incorrectly applies the growth factor.

Question 2

Question: A substance decays according to ( N = 200 \times 0.8^t ). How much remains after 3 hours? - A: 102.4 - B: 128 - C: 160 - D: 256

Correct Answer: B Explanation: ( N = 200 \times 0.8^3 = 200 \times 0.512 = 102.4 ) Why the Distractors Are Tempting: - A: Miscalculates the decay.
- C: Confuses the decay factor.
- D: Incorrectly applies the formula.

Question 3

Question: If a substance has a half-life of 3 years, what percentage remains after 9 years? - A: 12.5% - B: 25% - C: 50% - D: 75%

Correct Answer: A Explanation: ( b = e^{\frac{\ln(0.5)}{3}} \approx 0.7937 ), ( N = N_0 \times 0.7937^9 \approx 0.125 \times N_0 ) Why the Distractors Are Tempting: - B: Misinterprets the half-life.
- C: Confuses the decay rate.
- D: Incorrectly calculates the remaining amount.

Question 4

Question: Which of the following is an exponential growth function? - A: ( y = 2x + 3 ) - B: ( y = 5 \times 0.9^x ) - C: ( y = 10 \times 1.2^x ) - D: ( y = 7 \times 0.5^x )

Correct Answer: C Explanation: ( b = 1.2 > 1 ) indicates growth.
Why the Distractors Are Tempting: - A: Is a linear function.
- B: Is exponential decay.
- D: Is exponential decay.

Question 5

Question: If ( y = 3 \times 4^x ), what is the value of ( y ) when ( x = 0 )? - A: 0 - B: 3 - C: 4 - D: 12

Correct Answer: B Explanation: ( y = 3 \times 4^0 = 3 \times 1 = 3 ) Why the Distractors Are Tempting: - A: Misinterprets the exponent.
- C: Confuses the base.
- D: Incorrectly applies the formula.

30-Second Cheat Sheet

  • Exponential Growth: ( y = ab^x ) with ( b > 1 )
  • Exponential Decay: ( y = ab^x ) with ( 0 < b < 1 )
  • Half-Life Formula: ( t_{1/2} = \frac{\ln(2)}{\ln(b)} )
  • Growth Curve: Steeply rises
  • Decay Curve: Flattens out
  • Initial Amount: ( a ) is the starting value
  • Time Unit: Always check and convert if necessary

Learning Path

  1. Beginner Foundation: Review linear functions and basic algebra.
  2. Core Rules: Understand the exponential growth and decay formulas.
  3. Practice: Solve easy to medium difficulty problems.
  4. Timed Drills: Practice under exam conditions.
  5. Mock Tests: Take full-length practice exams.

Related Topics

  1. Logarithmic Functions: Often used to solve exponential equations.
  2. Compound Interest: Applies exponential growth in finance.
  3. Differential Equations: Used to model more complex growth and decay scenarios.


ADVERTISEMENT