By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Exponential growth and decay describe processes where a quantity increases or decreases at a rate proportional to its current value. This topic appears in exams to test your understanding of nonlinear functions and their applications in real-world scenarios like population growth, radioactive decay, and financial compounding.
Exponential functions are tested in various exams, including: - SAT Math Level 2- AP Calculus- ACT Math- GRE Quantitative
They frequently appear and can carry significant marks, testing your ability to understand and apply nonlinear relationships.
Intermediate
Question: If a population grows according to the formula ( P = 100 \times 2^t ), where ( t ) is in years, what is the population after 3 years? 1. Identify ( a = 100 ), ( b = 2 ), and ( t = 3 ).2. Substitute into the formula: ( P = 100 \times 2^3 ).3. Calculate: ( P = 100 \times 8 = 800 ).
Answer: 800
Question: A radioactive substance decays according to the formula ( N = N_0 \times 0.5^t ), where ( t ) is in hours. If the initial amount ( N_0 ) is 1000 grams, how much remains after 4 hours? 1. Identify ( N_0 = 1000 ), ( b = 0.5 ), and ( t = 4 ).2. Substitute into the formula: ( N = 1000 \times 0.5^4 ).3. Calculate: ( N = 1000 \times 0.0625 = 62.5 ) grams.
Answer: 62.5 grams
Question: If a substance decays with a half-life of 2 years, what percentage of the original amount remains after 6 years? 1. Identify the half-life ( t_{1/2} = 2 ) years.2. Use the half-life formula: ( b = e^{\frac{\ln(0.5)}{2}} ).3. Calculate ( b ): ( b = e^{-0.3466} \approx 0.7071 ).4. Substitute into the decay formula: ( N = N_0 \times 0.7071^6 ).5. Calculate: ( N = N_0 \times 0.1111 ).6. Convert to percentage: ( 0.1111 \times 100 = 11.11\% ).
Answer: 11.11%
Question: If a population grows according to ( P = 50 \times 3^t ), what is the population after 2 years? - A: 150 - B: 450 - C: 900 - D: 1350
Correct Answer: B Explanation: ( P = 50 \times 3^2 = 50 \times 9 = 450 ) Why the Distractors Are Tempting: - A: Confuses the exponent.- C: Miscalculates the multiplication.- D: Incorrectly applies the growth factor.
Question: A substance decays according to ( N = 200 \times 0.8^t ). How much remains after 3 hours? - A: 102.4 - B: 128 - C: 160 - D: 256
Correct Answer: B Explanation: ( N = 200 \times 0.8^3 = 200 \times 0.512 = 102.4 ) Why the Distractors Are Tempting: - A: Miscalculates the decay.- C: Confuses the decay factor.- D: Incorrectly applies the formula.
Question: If a substance has a half-life of 3 years, what percentage remains after 9 years? - A: 12.5% - B: 25% - C: 50% - D: 75%
Correct Answer: A Explanation: ( b = e^{\frac{\ln(0.5)}{3}} \approx 0.7937 ), ( N = N_0 \times 0.7937^9 \approx 0.125 \times N_0 ) Why the Distractors Are Tempting: - B: Misinterprets the half-life.- C: Confuses the decay rate.- D: Incorrectly calculates the remaining amount.
Question: Which of the following is an exponential growth function? - A: ( y = 2x + 3 ) - B: ( y = 5 \times 0.9^x ) - C: ( y = 10 \times 1.2^x ) - D: ( y = 7 \times 0.5^x )
Correct Answer: C Explanation: ( b = 1.2 > 1 ) indicates growth.Why the Distractors Are Tempting: - A: Is a linear function.- B: Is exponential decay.- D: Is exponential decay.
Question: If ( y = 3 \times 4^x ), what is the value of ( y ) when ( x = 0 )? - A: 0 - B: 3 - C: 4 - D: 12
Correct Answer: B Explanation: ( y = 3 \times 4^0 = 3 \times 1 = 3 ) Why the Distractors Are Tempting: - A: Misinterprets the exponent.- C: Confuses the base.- D: Incorrectly applies the formula.
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