By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Completing the square is a technique used to rewrite a quadratic equation in vertex form, which reveals the vertex of the parabola. This topic appears in exams because it tests your ability to manipulate algebraic expressions and understand the geometric properties of quadratic functions. Typical questions involve converting a quadratic equation from standard form to vertex form and identifying the vertex.
This topic is tested in various math exams, including SAT, ACT, and high school algebra and precalculus courses. It frequently appears and can carry significant marks. Mastering this skill demonstrates your ability to handle algebraic manipulation and understand the relationship between algebraic equations and geometric shapes.
To complete the square, follow these steps: 1. Start with the quadratic equation in standard form: ( ax^2 + bx + c ).2. Move the constant term ( c ) to the other side of the equation.3. Divide the entire equation by ( a ) (if ( a \neq 1 )).4. Take half of the coefficient of ( x ), square it, and add it to both sides.5. Rewrite the left side as a perfect square trinomial.6. Simplify the right side to get the vertex form.
Think of completing the square as "filling in the missing piece" to form a perfect square trinomial.
Intermediate
Question: Convert ( x^2 + 6x + 8 ) to vertex form.1. Move the constant term: ( x^2 + 6x = -8 ) 2. Take half of 6, square it: ( \left(\frac{6}{2}\right)^2 = 9 ) 3. Add 9 to both sides: ( x^2 + 6x + 9 = -8 + 9 ) 4. Rewrite as a perfect square: ( (x + 3)^2 = 1 ) 5. Vertex form: ( y = (x + 3)^2 - 1 )
Answer: ( y = (x + 3)^2 - 1 )
Question: Convert ( 2x^2 - 4x + 1 ) to vertex form.1. Move the constant term: ( 2x^2 - 4x = -1 ) 2. Divide by 2: ( x^2 - 2x = -\frac{1}{2} ) 3. Take half of -2, square it: ( \left(\frac{-2}{2}\right)^2 = 1 ) 4. Add 1 to both sides: ( x^2 - 2x + 1 = -\frac{1}{2} + 1 ) 5. Rewrite as a perfect square: ( (x - 1)^2 = \frac{1}{2} ) 6. Multiply by 2: ( 2(x - 1)^2 = 1 )
Answer: ( y = 2(x - 1)^2 + 1 )
Question: Convert ( 3x^2 + 12x - 5 ) to vertex form.1. Move the constant term: ( 3x^2 + 12x = 5 ) 2. Divide by 3: ( x^2 + 4x = \frac{5}{3} ) 3. Take half of 4, square it: ( \left(\frac{4}{2}\right)^2 = 4 ) 4. Add 4 to both sides: ( x^2 + 4x + 4 = \frac{5}{3} + 4 ) 5. Rewrite as a perfect square: ( (x + 2)^2 = \frac{17}{3} ) 6. Multiply by 3: ( 3(x + 2)^2 = 17 )
Answer: ( y = 3(x + 2)^2 - 17 )
Correct Approach: Divide by 2 first.
Not Adding to Both Sides: Ensure you add the square of half the coefficient of ( x ) to both sides.
Correct Approach: Add 9 to both sides.
Incorrect Perfect Square: Ensure the perfect square trinomial is correctly formed.
Correct Approach: ( (x + 3)^2 = 1 )
Misidentifying the Vertex: The vertex is ((h, k)) in ( y = a(x - h)^2 + k ).
Favored by: SAT, ACT
Identify the Vertex: Asks for the vertex of a parabola given in standard form.
Favored by: High school algebra exams
Graphing Parabolas: Asks to graph a parabola given in standard form by first converting to vertex form.
Convert ( x^2 + 8x + 12 ) to vertex form.- A: ( y = (x + 4)^2 - 4 ) - B: ( y = (x + 4)^2 + 4 ) - C: ( y = (x + 4)^2 - 12 ) - D: ( y = (x + 4)^2 + 12 )
Correct Answer: A Explanation: Move the constant term, add ( \left(\frac{8}{2}\right)^2 = 16 ) to both sides, rewrite as ( (x + 4)^2 = 4 ).Why the Distractors Are Tempting: B and D incorrectly handle the constant term; C miscalculates the perfect square.
Find the vertex of ( 2x^2 - 8x + 7 ).- A: ( (2, -1) ) - B: ( (2, 1) ) - C: ( (4, -1) ) - D: ( (4, 1) )
Correct Answer: B Explanation: Divide by 2, complete the square, vertex is ( (2, 1) ).Why the Distractors Are Tempting: A and C misidentify the vertex; D incorrectly calculates the vertex.
Convert ( 3x^2 + 18x - 9 ) to vertex form.- A: ( y = 3(x + 3)^2 - 36 ) - B: ( y = 3(x + 3)^2 - 27 ) - C: ( y = 3(x + 3)^2 - 18 ) - D: ( y = 3(x + 3)^2 - 9 )
Correct Answer: A Explanation: Divide by 3, complete the square, multiply by 3.Why the Distractors Are Tempting: B, C, and D incorrectly handle the constant term.
What is the vertex of ( 4x^2 - 16x + 15 )? - A: ( (2, -1) ) - B: ( (2, 1) ) - C: ( (4, -1) ) - D: ( (4, 1) )
Correct Answer: A Explanation: Divide by 4, complete the square, vertex is ( (2, -1) ).Why the Distractors Are Tempting: B and D misidentify the vertex; C incorrectly calculates the vertex.
Convert ( 5x^2 + 20x - 25 ) to vertex form.- A: ( y = 5(x + 2)^2 - 45 ) - B: ( y = 5(x + 2)^2 - 35 ) - C: ( y = 5(x + 2)^2 - 25 ) - D: ( y = 5(x + 2)^2 - 15 )
Correct Answer: A Explanation: Divide by 5, complete the square, multiply by 5.Why the Distractors Are Tempting: B, C, and D incorrectly handle the constant term.
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