By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Linear Equations in Context: Word Problems — Setting Up Variables involves translating real-world scenarios into mathematical equations to solve for unknown quantities. This topic tests your ability to interpret word problems, assign variables, and formulate equations.
Exams often include questions that require you to set up and solve linear equations based on word problems. These questions test your logical reasoning, problem-solving skills, and understanding of algebraic principles.
This topic is frequently tested in standardized exams like the SAT, ACT, GRE, and various high school and college-level math exams. It typically carries moderate to high marks and tests your ability to apply algebraic concepts to practical situations. Mastering this skill is crucial for both academic success and real-world problem-solving.
Without these foundations, you may struggle to set up and solve the equations correctly.
Translate the word problem into a linear equation by assigning a variable to the unknown quantity and converting key phrases into mathematical expressions.
2x
x + y
x + y + z
Think of the problem as a balance scale:
Unknown Quantity = Known Quantity + Relationships
Intermediate
Question: John has 5 more apples than Jane. Together, they have 20 apples. How many apples does Jane have?
J
J + 5
J + (J + 5) = 20
2J + 5 = 20
2J = 15
J = 7.5
Answer: Jane has 7.5 apples.
Question: A book costs $10 more than a pencil. Together, the book and pencil cost $25. How much does the pencil cost?
P
P + 10
P + (P + 10) = 25
2P + 10 = 25
2P = 15
P = 7.5
Answer: The pencil costs $7.50.
Question: Three times a number increased by 7 is equal to 31. Find the number.
N
3N + 7
3N + 7 = 31
3N = 24
N = 8
Answer: The number is 8.
Correct Approach: Carefully read and translate each phrase.
Incorrect Variable Assignment: Assigning the wrong variable to the unknown.
Correct Approach: Clearly define what each variable represents.
Ignoring Negative Solutions: Assuming all answers must be positive.
Correct Approach: Consider all possible solutions.
Forgetting to Check: Not verifying the solution in the context of the problem.
Exams: SAT, ACT
Multiplication/Division:
Exams: GRE, College Math
Complex Relationships:
Question: Mary has 3 times as many books as Peter. Together, they have 28 books. How many books does Peter have? - A: 5 - B: 7 - C: 9 - D: 11
Correct Answer: B Explanation: Let P be the number of books Peter has. Mary has 3P books. Together, P + 3P = 28. Solving, 4P = 28, P = 7.Why the Distractors Are Tempting: - A: Confuses the total number of books.- C: Misinterprets the multiplication factor.- D: Overestimates Peter's share.
3P
P + 3P = 28
4P = 28
P = 7
Question: A car travels 20 miles per hour faster than a bike. Together, they travel 150 miles in the same amount of time. How fast is the bike? - A: 30 mph - B: 40 mph - C: 50 mph - D: 60 mph
Correct Answer: C Explanation: Let B be the speed of the bike. The car travels at B + 20 mph. Together, B + (B + 20) = 150. Solving, 2B + 20 = 150, 2B = 130, B = 65.Why the Distractors Are Tempting: - A: Underestimates the bike's speed.- B: Miscalculates the total speed.- D: Overestimates the bike's speed.
B
B + 20
B + (B + 20) = 150
2B + 20 = 150
2B = 130
B = 65
Question: The sum of two numbers is 40. One number is 8 more than the other. What is the smaller number? - A: 12 - B: 16 - C: 18 - D: 20
Correct Answer: A Explanation: Let S be the smaller number. The larger number is S + 8. Together, S + (S + 8) = 40. Solving, 2S + 8 = 40, 2S = 32, S = 16.Why the Distractors Are Tempting: - B: Confuses the sum of the numbers.- C: Misinterprets the difference.- D: Overestimates the smaller number.
S
S + 8
S + (S + 8) = 40
2S + 8 = 40
2S = 32
S = 16
Question: A rectangle's length is 5 meters more than its width. The perimeter is 40 meters. What is the width? - A: 5 m - B: 6 m - C: 7 m - D: 8 m
Correct Answer: B Explanation: Let W be the width. The length is W + 5. The perimeter is 2(W + W + 5) = 40. Solving, 2(2W + 5) = 40, 4W + 10 = 40, 4W = 30, W = 7.5.Why the Distractors Are Tempting: - A: Underestimates the width.- C: Miscalculates the perimeter.- D: Overestimates the width.
W
W + 5
2(W + W + 5) = 40
2(2W + 5) = 40
4W + 10 = 40
4W = 30
W = 7.5
Question: A number increased by 6 is equal to twice another number. The sum of the two numbers is 30. What is the first number? - A: 8 - B: 10 - C: 12 - D: 14
Correct Answer: D Explanation: Let N be the first number and M be the second number. N + 6 = 2M and N + M = 30. Solving, N + 6 = 2(30 - N), N + 6 = 60 - 2N, 3N = 54, N = 18.Why the Distractors Are Tempting: - A: Underestimates the first number.- B: Misinterprets the relationship.- C: Overestimates the second number.
M
N + 6 = 2M
N + M = 30
N + 6 = 2(30 - N)
N + 6 = 60 - 2N
3N = 54
N = 18
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