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Entropy (ΔS) and Gibbs Free Energy (ΔG) are the "decision-makers" of chemical reactions—they tell you whether a reaction will happen spontaneously (on its own) or not. Think of entropy as a measure of disorder (like a messy room getting messier over time), while Gibbs Free Energy combines entropy and enthalpy (heat energy) to predict spontaneity. On the AP exam, you’ll use these concepts to explain why some reactions occur naturally (e.g., ice melting at room temperature) while others need a push (e.g., photosynthesis requiring sunlight). Real-world example: A campfire burns spontaneously because the increase in entropy (gases spreading out) and release of heat (exothermic) make ΔG negative—nature "prefers" this outcome.
Tip: If ΔS is positive, the reaction becomes more spontaneous at higher T; if negative, less spontaneous at higher T.
Convert units to match:
ΔH is usually in kJ/mol; ΔS is in J/mol·K. Convert ΔS to kJ/mol·K (divide by 1000) or ΔH to J/mol.
Plug into ΔG = ΔH – TΔS:
Example: For H₂O(l) → H₂O(g) at 100°C (373 K): ΔH = +40.7 kJ/mol, ΔS = +118.9 J/mol·K = +0.1189 kJ/mol·K. ΔG = 40.7 – (373)(0.1189) = 40.7 – 44.3 = –3.6 kJ/mol → spontaneous (boiling occurs).
Interpret the sign of ΔG:
ΔG = 0: Equilibrium (e.g., phase changes at melting/boiling points).
Check temperature dependence:
If ΔH and ΔS have opposite signs, spontaneity is independent of T.
For multi-step reactions:
Mistake: Confusing ΔS_system with ΔS_universe. Correction: A reaction can have ΔS_system < 0 (e.g., water freezing) but still be spontaneous if ΔS_surroundings > 0 (e.g., heat released warms the surroundings, increasing their entropy).
Mistake: Forgetting to convert units (kJ vs. J). Correction: ΔH is in kJ/mol; ΔS is in J/mol·K. Convert ΔS to kJ/mol·K (divide by 1000) before plugging into ΔG = ΔH – TΔS.
Mistake: Assuming ΔG = 0 means no reaction occurs. Correction: ΔG = 0 means the system is at equilibrium (forward and reverse reactions occur at equal rates). Example: Ice and water coexist at 0°C.
Mistake: Ignoring temperature’s role in spontaneity. Correction: A reaction can be non-spontaneous at low T but spontaneous at high T (or vice versa). Always check the sign of ΔH and ΔS to predict T dependence.
Mistake: Thinking "spontaneous" means "fast." Correction: Spontaneity is about thermodynamics (energy), not kinetics (speed). A reaction can be spontaneous but slow (e.g., rusting of iron).
AP Trap: A reaction with ΔG° > 0 can still have ΔG < 0 if Q is very small (e.g., products are removed, shifting equilibrium right).
Frequent FRQ Type: "Explain Spontaneity"
You’ll be given ΔH and ΔS (or asked to calculate them) and must:
Multiple-Choice Traps:
Trap: "Entropy always increases in a spontaneous process." False! ΔS_system can decrease if ΔS_surroundings increases more (e.g., water freezing).
Coupled Reactions:
Answer: (B) 1,750 K. Explanation: At equilibrium, ΔG = 0 = ΔH – TΔS. Solve for T: T = ΔH/ΔS = (–572,000 J/mol) / (–327 J/mol·K) ≈ 1,750 K.
Answer: a) ΔG is negative (spontaneous) at 25°C. Although ΔH > 0, the large positive ΔS makes –TΔS dominate, so ΔG = ΔH – TΔS < 0. b) Increasing temperature makes the process more spontaneous because ΔS > 0, so –TΔS becomes more negative, decreasing ΔG further.
Answer: (B) 2H₂(g) + O₂(g) → 2H₂O(g). Explanation: 3 moles of gas → 2 moles of gas, so disorder decreases (ΔS < 0). The other options increase disorder (ΔS > 0).
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