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Mass spectrometry (MS) is a lab technique that measures the mass-to-charge ratio (m/z) of ions to identify isotopes, determine atomic/molecular masses, and analyze chemical composition. On the AP exam, you’ll need to interpret mass spectra, calculate average atomic masses, and explain isotope abundance. Real-world example: Forensic scientists use MS to detect drugs or toxins in crime scenes, while archaeologists use it to date ancient artifacts (e.g., carbon-14 dating in Ötzi the Iceman).
Example: For methane (CH₄), M⁺ = 16 amu.
List all peaks and their m/z values:
Example: Chlorine (Cl₂) has peaks at 70, 72, and 74 amu (from ³⁵Cl-³⁵Cl, ³⁵Cl-³⁷Cl, and ³⁷Cl-³⁷Cl).
Determine isotope patterns:
Example: Bromine (⁷⁹Br and ⁸¹Br) shows two equal-height peaks 2 amu apart.
Calculate average atomic mass (if given % abundance):
Example: Copper has 69.15% ⁶³Cu (62.93 amu) and 30.85% ⁶⁵Cu (64.93 amu). Average mass = (0.6915 × 62.93) + (0.3085 × 64.93) = 63.55 amu
Explain fragmentation (for molecules):
Mistake: Confusing mass number (protons + neutrons) with atomic mass (weighted average). Correction: Mass number is an integer (e.g., ¹²C = 12), while atomic mass is a decimal (e.g., carbon = 12.01 amu).
Mistake: Assuming the tallest peak is always the molecular ion. Correction: The molecular ion is the highest m/z peak, but it may not be the tallest (e.g., in alcohols, the M⁺ peak is often weak).
Mistake: Forgetting that diatomic elements (e.g., Cl₂, Br₂) show multiple peaks due to isotope combinations. Correction: For Cl₂, peaks at 70 (³⁵Cl-³⁵Cl), 72 (³⁵Cl-³⁷Cl), and 74 (³⁷Cl-³⁷Cl) appear in a 1:2:1 ratio.
Mistake: Miscalculating average atomic mass by using percentages directly (e.g., 69.15% → 69.15 instead of 0.6915). Correction: Always convert percentages to decimals (divide by 100) before multiplying.
Mistake: Ignoring fragmentation when interpreting spectra. Correction: Smaller peaks often represent broken pieces of the molecule (e.g., loss of H₂O or CH₃ groups).
Multiple Choice: A mass spectrum of chlorine gas (Cl₂) shows peaks at 70, 72, and 74 amu. What is the ratio of their relative intensities? A) 1:1:1 B) 1:2:1 C) 3:1:3 D) 9:6:1 Answer: B) 1:2:1 Explanation: Chlorine has two isotopes (³⁵Cl and ³⁷Cl) in a ~3:1 ratio, leading to Cl₂ peaks in a 1:2:1 ratio (³⁵Cl-³⁵Cl : ³⁵Cl-³⁷Cl : ³⁷Cl-³⁷Cl).
Short FRQ: The mass spectrum of an element shows two peaks at 63 amu and 65 amu with relative intensities of 69.15% and 30.85%, respectively. Calculate the average atomic mass of the element. Answer: 63.55 amu Explanation: (0.6915 × 63) + (0.3085 × 65) = 63.55 amu.
Multiple Choice: In the mass spectrum of ethanol (CH₃CH₂OH), a peak appears at 31 amu. Which fragment is most likely responsible? A) CH₃⁺ B) CH₂OH⁺ C) C₂H₅⁺ D) OH⁺ Answer: B) CH₂OH⁺ Explanation: CH₂OH⁺ has a mass of 31 amu (12 + 2 + 16 + 1).
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