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Mass spectrometry (MS) is a lab technique that measures the mass-to-charge ratio (m/z) of ions to identify isotopes, determine atomic/molecular masses, and analyze chemical composition. On the AP exam, you’ll need to interpret mass spectra, calculate average atomic masses, and explain isotope abundance. Real-world example: Forensic scientists use MS to detect drugs or toxins in crime scenes, while archaeologists use it to date ancient artifacts (e.g., carbon-14 dating in Ötzi the Iceman).
Example: For methane (CH?), M? = 16 amu.
List all peaks and their m/z values:
Example: Chlorine (Cl?) has peaks at 70, 72, and 74 amu (from ³?Cl-³?Cl, ³?Cl-³?Cl, and ³?Cl-³?Cl).
Determine isotope patterns:
Example: Bromine (Br and ?¹Br) shows two equal-height peaks 2 amu apart.
Calculate average atomic mass (if given % abundance):
Example: Copper has 69.15% ?³Cu (62.93 amu) and 30.85% Cu (64.93 amu). Average mass = (0.6915 × 62.93) + (0.3085 × 64.93) = 63.55 amu
Explain fragmentation (for molecules):
Mistake: Confusing mass number (protons + neutrons) with atomic mass (weighted average). Correction: Mass number is an integer (e.g., ¹²C = 12), while atomic mass is a decimal (e.g., carbon = 12.01 amu).
Mistake: Assuming the tallest peak is always the molecular ion. Correction: The molecular ion is the highest m/z peak, but it may not be the tallest (e.g., in alcohols, the M? peak is often weak).
Mistake: Forgetting that diatomic elements (e.g., Cl?, Br?) show multiple peaks due to isotope combinations. Correction: For Cl?, peaks at 70 (³?Cl-³?Cl), 72 (³?Cl-³?Cl), and 74 (³?Cl-³?Cl) appear in a 1:2:1 ratio.
Mistake: Miscalculating average atomic mass by using percentages directly (e.g., 69.15%-69.15 instead of 0.6915). Correction: Always convert percentages to decimals (divide by 100) before multiplying.
Mistake: Ignoring fragmentation when interpreting spectra. Correction: Smaller peaks often represent broken pieces of the molecule (e.g., loss of H?O or CH? groups).
Multiple Choice: A mass spectrum of chlorine gas (Cl?) shows peaks at 70, 72, and 74 amu. What is the ratio of their relative intensities? A) 1:1:1 B) 1:2:1 C) 3:1:3 D) 9:6:1 Answer: B) 1:2:1 Explanation: Chlorine has two isotopes (³?Cl and ³?Cl) in a ~3:1 ratio, leading to Cl? peaks in a 1:2:1 ratio (³?Cl-³?Cl : ³?Cl-³?Cl : ³?Cl-³?Cl).
Short FRQ: The mass spectrum of an element shows two peaks at 63 amu and 65 amu with relative intensities of 69.15% and 30.85%, respectively. Calculate the average atomic mass of the element. Answer: 63.55 amu Explanation: (0.6915 × 63) + (0.3085 × 65) = 63.55 amu.
Multiple Choice: In the mass spectrum of ethanol (CH?CH?OH), a peak appears at 31 amu. Which fragment is most likely responsible? A) CH B) CH?OH? C) C?H D) OH? Answer: B) CH?OH? Explanation: CH?OH? has a mass of 31 amu (12 + 2 + 16 + 1).
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