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Photoelectron Spectroscopy (PES) is a lab technique that measures the ionization energies of electrons in an atom or molecule by blasting them with high-energy light (usually X-rays or UV rays) and detecting the speed of the ejected electrons. This reveals the electron configuration and relative energies of orbitals, helping chemists understand bonding, reactivity, and atomic structure. On the AP exam, PES is tested in multiple-choice questions and free-response questions (FRQs)—often as a graph you must interpret to identify elements or compare orbital energies.
Real-world example: PES was used to confirm the electron configuration of superheavy elements (like element 118, Oganesson) when they were first synthesized. It also helps in materials science to study surfaces of catalysts or semiconductors.
Equation: E = hν = KE + BE
Binding Energy (BE): The energy required to remove an electron from an atom. Higher BE = electron is closer to the nucleus (lower energy orbital).
Example: 1s electrons have higher BE than 2s electrons.
Kinetic Energy (KE) of Ejected Electrons: The leftover energy after the electron is ejected. KE = hν – BE.
Key idea: Electrons with higher KE were less tightly bound (lower BE).
PES Spectrum: A graph of electron count (y-axis) vs. binding energy (x-axis). Peaks represent subshells (e.g., 1s, 2s, 2p).
Example: A peak at 1300 eV = 1s electrons; a peak at 100 eV = 2s electrons.
Intensity of Peaks: The height of a peak corresponds to the number of electrons in that subshell.
Example: A 2p peak with 3× the height of a 2s peak means there are 6 electrons in 2p (vs. 2 in 2s).
Orbital Energy Order: In multi-electron atoms, s < p < d < f in energy (for the same n). PES confirms this experimentally.
Exception: In hydrogen (1-electron), all orbitals with the same n have the same energy.
Koopmans’ Theorem: The binding energy of an electron ≈ its orbital energy (ignoring relaxation effects). Useful for interpreting PES data.
Work Function (Φ): The minimum energy needed to remove an electron from a metal surface (not the same as BE for atoms).
Example: In solar panels, light must exceed the work function to eject electrons (photoelectric effect).
X-ray PES (XPS) vs. UV PES (UPS):
UPS: Uses UV light (lower energy) → ejects valence electrons (e.g., 2p, 3s).
Spin-Orbit Coupling: In PES, some peaks split due to electron spin interacting with orbital motion (e.g., p orbitals split into p₁/₂ and p₃/₂).
Problem: Given a PES spectrum, identify the element and explain the peaks.
y-axis: Relative number of electrons (intensity).
Identify the peaks:
Next peaks = 2s, 2p, 3s, 3p, etc. (follow the Aufbau principle).
Count electrons per peak:
Example: A 2p peak with 3× the height of 2s → 6 electrons in 2p (vs. 2 in 2s).
Match to electron configuration:
Example: Peaks at 1s² 2s² 2p⁶ 3s² 3p² → 14 electrons → Silicon (Si).
Compare orbital energies:
Example: In Na (1s² 2s² 2p⁶ 3s¹), the 3s peak has lower BE than 2p.
Check for anomalies:
Correction: BE is the energy to remove an electron; KE is the leftover energy after ejection. KE = hν – BE.
Mistake: Assuming peak height = energy level.
Correction: Peak height = number of electrons; x-axis position = energy (BE).
Mistake: Forgetting that PES measures ionization energy, not electron affinity.
Correction: PES gives ionization energies (energy to remove an electron), not the energy change when an electron is added.
Mistake: Misordering subshells (e.g., thinking 3d has lower BE than 4s).
Correction: In multi-electron atoms, 4s has lower BE than 3d (but fills first in Aufbau). PES confirms this experimentally.
Mistake: Ignoring spin-orbit splitting (e.g., treating p peaks as single peaks).
Explain why peaks have different heights (e.g., “Why is the 2p peak taller than 2s?”).
Multiple-choice traps:
Core vs. valence electrons: XPS (X-ray PES) ejects core electrons; UPS (UV PES) ejects valence electrons.
Tricky distinction:
Ionization energy (IE) vs. binding energy (BE):
Experimental context:
The PES spectrum of an element shows peaks at the following binding energies (in MJ/mol): - 2.37 (small peak) - 0.15 (large peak) - 0.08 (medium peak)
Which element is this most likely to be? (A) Carbon (C) (B) Sodium (Na) (C) Magnesium (Mg) (D) Aluminum (Al)
✅ Answer: (B) Sodium (Na)Explanation: The peaks correspond to 1s² (2.37 MJ/mol), 2s² 2p⁶ (0.15 MJ/mol), and 3s¹ (0.08 MJ/mol)—matching Na’s electron configuration (1s² 2s² 2p⁶ 3s¹).
A PES spectrum for an unknown element has three peaks with relative intensities (heights) in a ratio of 1:2:3. The binding energies of the peaks are 500 eV, 40 eV, and 20 eV.
(a) Identify the element.(b) Explain why the peak at 20 eV is the tallest.
✅ Answer:(a) Nitrogen (N)- Peaks: 1s² (500 eV), 2s² (40 eV), 2p³ (20 eV) → total electrons = 7 → N.(b) The 20 eV peak is tallest because it represents the 2p subshell, which has 3 electrons (vs. 2 in 2s and 2 in 1s). Peak height corresponds to the number of electrons in that subshell.
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