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Periodic trends explain how atomic properties (size, energy to remove electrons, attraction for electrons) change predictably across the periodic table. These trends are foundational for predicting chemical behavior—why sodium explodes in water but magnesium doesn’t, or why fluorine is the most reactive nonmetal. On the AP exam, you’ll use these trends to explain reactivity, bonding, and even spectroscopy. Real-world example: The Hindenburg disaster (1937)—hydrogen gas (small atomic radius, low ionization energy) ignited explosively, while helium (larger radius, higher ionization energy) is inert and safe for blimps.
Exception: Noble gases have slightly larger radii than halogens due to electron-electron repulsion.
Effective nuclear charge (Zeff): The net positive charge experienced by an electron in a multi-electron atom. Formula: Zeff = Z – S (Z = atomic number, S = shielding constant).
Example: Sodium (Z=11) has Zeff-+1 for its valence electron because inner electrons shield most of the nuclear charge.
Ionization energy (IE): Energy required to remove an electron from a gaseous atom. Trend: Increases left-to-right (higher Zeff) and decreases down a group (electrons farther from nucleus).
Exceptions: Oxygen’s IE < Nitrogen’s (due to electron pairing in p-orbitals).
Electronegativity (EN): Ability of an atom to attract shared electrons in a bond. Trend: Increases left-to-right and decreases down a group (fluorine is the most electronegative).
Scale: Pauling scale (0–4); noble gases have no EN values (they don’t form bonds).
Electron affinity (EA): Energy change when an electron is added to a gaseous atom. Trend: Becomes more negative (more exothermic) left-to-right (except noble gases, which have positive EA).
Example: Chlorine has a highly negative EA (releases energy when gaining an electron), making it very reactive.
Shielding effect: Inner electrons block the nuclear charge from outer electrons. Key idea: More inner electrons = weaker attraction for valence electrons.
Example: Cesium (Cs) has a low IE because its valence electron is shielded by 54 inner electrons.
Isoelectronic series: Atoms/ions with the same electron configuration (e.g., O2–, F–, Ne, Na+). Trend: Radius decreases as nuclear charge increases (e.g., O2– > F– > Ne > Na+).
Metallic character: How readily an atom loses electrons. Trend: Increases down a group and decreases left-to-right (metals on the left, nonmetals on the right).
Draw a mental periodic table and label arrows for:
Compare elements by position:
For atomic radius: Ask, “Which has more electron shells?” (down a group) or “Which has a higher Zeff?” (across a period).
Explain exceptions:
EA exceptions: Group 2 (e.g., Be) and Group 15 (e.g., N) have less negative EA than expected due to half-filled/stable configurations.
Apply to ions:
Example: Rank O, O–, O2– by size: O < O– < O2–.
Use trends to predict reactivity:
Correction: Noble gases have larger radii than halogens due to electron-electron repulsion in filled orbitals.
Mistake: Confusing ionization energy and electronegativity.
Correction: IE is about removing an electron; EN is about attracting shared electrons in a bond.
Mistake: Forgetting that second IE is always higher than first IE.
Correction: Removing an electron from a cation (e.g., Na+-Na2+) requires more energy because the remaining electrons are held tighter.
Mistake: Ignoring isoelectronic series when comparing ion sizes.
Correction: For ions with the same electron configuration (e.g., O2–, F–, Ne), nuclear charge determines size (higher Z = smaller radius).
Mistake: Thinking electron affinity is always negative.
Predict reactivity (e.g., “Why is potassium more reactive than sodium?”-lower IE).
Multiple-choice traps:
Electronegativity of noble gases: They have no EN values (don’t form bonds).
Lab-based questions:
Periodic trends in melting points (e.g., carbon’s high melting point vs. silicon’s lower one).
Tricky distinction:
Which of the following has the largest atomic radius? (A) Na (B) Mg (C) Al (D) Si Answer: (A) Na. Atomic radius decreases left-to-right across a period due to increasing Zeff.
Explain why the first ionization energy of oxygen is less than that of nitrogen. Answer: Oxygen’s p-orbitals have paired electrons, which repel each other, making it easier to remove an electron compared to nitrogen’s half-filled, stable p-orbitals.
Rank the following in order of increasing electronegativity: F, Cl, Br, I. Answer: I < Br < Cl < F. Electronegativity decreases down a group as atomic size increases.
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