By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
This topic covers how electric charge flows through materials, what resists that flow, and the simple rule (Ohm’s Law) that ties them together. On the AP exam, you’ll see circuit problems, experimental design questions, and conceptual reasoning about real-world devices like light bulbs, resistors, and power lines. A famous historical example: Thomas Edison and George Westinghouse’s "War of the Currents" (late 1800s) pitted direct current (DC) against alternating current (AC) for powering cities—highlighting how resistance and power loss shape technology.
Example: A 12 V battery powers two resistors (3-and 6 ?) in series. - Total resistance: R_total = 3 + 6 = 9 ? - Current: I = V/R = 12/9 = 1.33 A - Voltage drop across 3-resistor: V = I×R = 1.33 × 3 = 4 V
Mistake: Assuming all materials obey Ohm’s Law. Correction: Ohm’s Law only works for ohmic materials (e.g., metals at constant temperature). Non-ohmic devices (e.g., diodes) have R that changes with V.
Mistake: Mixing up series and parallel rules. Correction:
Parallel: Voltage same, current divides.
Mistake: Forgetting units (e.g., using k? instead of-in calculations). Correction: Always convert to base units (e.g., 5 k? = 5000 ?).
Mistake: Ignoring internal resistance of batteries. Correction: Real batteries have small resistance (r); terminal voltage = V =-– I×r (where ? = emf).
Mistake: Misapplying power formulas. Correction: Use P = I²R for heat loss in resistors, P = IV for general power.
Conceptual reasoning: Why does a light bulb’s resistance increase when it’s on? (Temperature dependence of resistivity.)
Multiple-choice traps:
Parallel vs. series: "What happens to total resistance if you add a resistor in parallel?" (It decreases.)
Tricky distinction:
Multiple Choice: A 6-resistor and a 3-resistor are connected in parallel to a 9 V battery. What is the current through the 3-resistor? (A) 1 A (B) 2 A (C) 3 A (D) 6 A Answer: (C) 3 A. Voltage across parallel resistors is the same (9 V), so I = V/R = 9/3 = 3 A.
Short FRQ: A student measures the current through a resistor as 0.5 A when the voltage is 6 V. Is the resistor ohmic? Justify your answer. Answer: Yes, because R = V/I = 6/0.5 = 12 ? is constant (Ohm’s Law holds).
Multiple Choice: Which of the following changes would decrease the resistance of a wire? (A) Increasing its length (B) Increasing its temperature (C) Increasing its cross-sectional area (D) Using a material with higher resistivity Answer: (C) Increasing its cross-sectional area. R = ?L/A; larger A-smaller R.
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