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Newton’s Three Laws of Motion are the foundation of classical mechanics—they explain how and why objects move (or don’t move). These laws appear everywhere on the AP Physics exam, from multiple-choice questions to full free-response problems (FRQs). They’re essential for understanding forces, acceleration, and interactions between objects. Real-world example: When a car suddenly stops, your body lurches forward because of inertia (Newton’s 1st Law). The seatbelt applies a force to stop you (2nd Law), and your body pushes back on the seatbelt with equal force (3rd Law).
Equilibrium: When net force = 0 (object is at rest or moving at constant velocity).
Newton’s Second Law (F = ma): "The acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass."
Key idea: Force causes acceleration, not motion. A net force is needed to change velocity.
Newton’s Third Law (Action-Reaction): "For every action, there is an equal and opposite reaction."
Important: The two forces act on different objects (so they don’t cancel out).
Free-Body Diagram (FBD): A sketch showing all forces acting on a single object (e.g., gravity, normal force, friction, tension).
Rules:
Net Force (?F): The vector sum of all forces acting on an object.
If ?F-0-object accelerates in the direction of the net force.
Weight (F?): The force of gravity on an object: F? = mg (where g = 9.8 m/s² on Earth).
Weight-mass! Mass is constant; weight changes with gravity (e.g., you weigh less on the Moon).
Normal Force (F?): The perpendicular force a surface exerts to support an object.
Not always equal to weight! (e.g., on an incline or in an elevator accelerating upward).
Tension (F?): The pulling force exerted by a rope, string, or cable.
Assumption: Massless, unstretchable ropes-tension is the same throughout.
Friction (F_f): A force that opposes motion between two surfaces in contact.
Follow this exam-proof method for any force problem:
Label forces with variables (e.g., F?, F?, F?).
Choose a Coordinate System:
Break forces into x and y components if needed (e.g., F? on an incline = mg sin?).
Write Newton’s Second Law Equations:
Example:
Solve for Unknowns:
Pro tip: If stuck, check if you missed a force (e.g., friction, normal force).
Check Units & Reasonableness:
Correction: Always sum all forces first (?F) before plugging into F = ma.
Mistake: Assuming the normal force always equals weight.
Correction: F? = mg only on a flat surface with no vertical acceleration. On an incline or in an accelerating elevator, F?-mg.
Mistake: Mixing up action-reaction pairs (e.g., thinking they cancel out).
Correction: Action-reaction forces act on different objects, so they don’t cancel. Example: Earth pulls you down (gravity), you pull Earth up (but Earth’s mass is huge, so its acceleration is negligible).
Mistake: Ignoring friction when it’s present.
Correction: Always check if the problem mentions a surface (e.g., "rough floor" = friction is involved).
Mistake: Using F = ma for circular motion (e.g., centripetal force).
Third Law pairs: Multiple-choice questions love asking which forces are action-reaction pairs (e.g., "Is the normal force the reaction to gravity?" No! They act on the same object.)
Tricky Distinctions:
Net Force vs. Individual Forces: A net force causes acceleration, but individual forces (like tension) can be larger than the net force.
FRQ Tips:
A 5 kg block is pushed with a 20 N force on a frictionless surface. What is its acceleration? (A) 0.25 m/s² (B) 4 m/s² (C) 100 m/s² (D) 5 m/s²
Answer: (B) 4 m/s² Explanation: Use F = ma-a = F/m = 20 N / 5 kg = 4 m/s².
A 10 kg box rests on a horizontal surface. A 30 N horizontal force is applied, but the box does not move. (a) Draw a free-body diagram for the box. (b) What is the magnitude of the static friction force acting on the box?
Answer: (a) FBD should show: - Downward arrow: F? = mg = 98 N - Upward arrow: F? = 98 N - Right arrow: F_applied = 30 N - Left arrow: F_f (static) = 30 N
(b) 30 N (since the box isn’t moving, static friction balances the applied force).
A book rests on a table. Which of the following is an action-reaction pair according to Newton’s Third Law? (A) The weight of the book and the normal force from the table. (B) The force of the book on the table and the force of the table on the book. (C) The weight of the book and the force of the Earth on the book. (D) The normal force from the table and the force of the Earth on the table.
Answer: (B) Explanation: Action-reaction pairs act on different objects (book on table, table on book). (A) and (C) act on the same object, and (D) is unrelated.
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