By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
A free-body diagram (FBD) is a simple sketch that shows all the forces acting on a single object. The net force is the vector sum of those forces, and it determines the object’s acceleration (via Newton’s Second Law, F = ma). This topic is essential on the AP exam—you’ll see it in multiple-choice questions, FRQs, and even lab-based problems. Real-world example: When you push a stalled car, the forces acting on it (your push, friction, gravity, and the normal force from the road) combine to determine whether it moves. If the net force is zero, the car stays stuck; if not, it accelerates.
Label each force with its type (e.g., Fg, FN, Ff) and direction.
Choose a coordinate system.
For inclines: Align x parallel to the ramp and y perpendicular to it.
Resolve forces into components (if needed).
Break angled forces (e.g., tension at an angle) into x and y components using trigonometry (Fx = F·cos?, Fy = F·sin?).
Write equations for net force.
If the object is in equilibrium (a = 0), set ?F = 0 in both directions.
Solve for the unknown.
Check units: Forces in N, mass in kg, acceleration in m/s².
Interpret the result.
Mistake: Forgetting to include all forces in the FBD (e.g., omitting normal force or friction). Correction: Always ask: What is touching the object? (surfaces, ropes) and What forces act at a distance? (gravity, magnetism).
Mistake: Assuming FN = Fg in all cases (e.g., on an incline or in an accelerating elevator). Correction: FN only equals Fg on a flat, non-accelerating surface. On an incline, FN = m·g·cos?.
Mistake: Mixing up action-reaction pairs (Newton’s Third Law) with net force. Correction: Action-reaction pairs act on different objects (e.g., Earth pulls you down, you pull Earth up). Net force is the sum of forces on one object.
Mistake: Ignoring direction when adding forces (e.g., treating leftward and rightward forces as positive). Correction: Assign a sign convention (e.g., right/up = positive, left/down = negative) and stick to it.
Mistake: Using F = ma when Fnet = 0 (equilibrium). Correction: If Fnet = 0, a = 0 (object is at rest or moving at constant velocity).
Multiple Choice: A 5 kg block is at rest on a horizontal surface. What is the normal force acting on the block? A) 0 N B) 5 N C) 49 N D) 98 N Answer: C) 49 N. The normal force balances the weight (Fg = m·g = 5 kg × 9.8 m/s² = 49 N).
Short FRQ: A 10 kg box is pulled to the right with a force of 50 N, while a 20 N frictional force acts to the left. Draw a free-body diagram and calculate the acceleration of the box. Answer: Fnet = 50 N – 20 N = 30 N (right). a = Fnet/m = 30 N / 10 kg = 3 m/s² (right).
Multiple Choice: A 2 kg object is in free fall near Earth’s surface. What is the net force acting on it? A) 0 N B) 2 N C) 19.6 N D) 9.8 N Answer: C) 19.6 N. Only gravity acts (Fg = m·g = 2 kg × 9.8 m/s² = 19.6 N), so Fnet = Fg.
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