By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Electric charge is the fundamental property of matter that causes it to experience a force when placed in an electric field. Coulomb’s Law quantifies the force between two point charges, forming the foundation for understanding electric fields, circuits, and even atomic structure. This topic appears on ~10-15% of the AP Physics exam (both multiple-choice and FRQs), often paired with electric fields or potential energy. Real-world example: Static cling in laundry (opposite charges attract) or the spark when you touch a doorknob after shuffling your feet (charge transfer via friction).
Example: Two +3 µC charges are 0.5 m apart. What’s the force on one charge? - ( q_1 = q_2 = 3 \times 10^{-6} ) C - ( r = 0.5 ) m - ( F = (8.99 \times 10^9) \frac{(3 \times 10^{-6})^2}{(0.5)^2} = 0.324 ) N (repulsive).
Mistake: Forgetting to convert microcoulombs (µC) to coulombs (C). Correction: 1 µC = 1 × 10 C. Always convert before plugging into formulas.
Mistake: Ignoring vector directions (e.g., adding forces as scalars). Correction: Forces are vectors! Draw arrows and use trigonometry for angles.
Mistake: Using the wrong sign for charges in Coulomb’s Law. Correction: The formula uses absolute values for magnitude. Direction is determined by charge signs (like repels like).
Mistake: Confusing electric field (E) with force (F). Correction: ( E = \frac{F}{q} ). Field is force per unit charge; force depends on the test charge.
Mistake: Assuming charges are point charges when they’re not (e.g., charged spheres with radius). Correction: For spheres, use the center-to-center distance (r) if charges are uniformly distributed.
MCQ: Two identical charges are 0.2 m apart. If the distance is increased to 0.4 m, the force between them: (A) Doubles (B) Halves (C) Decreases to 1/4 (D) Increases by 4× Answer: (C) Decreases to 1/4 (inverse-square law: ( F \propto \frac{1}{r^2} )).
FRQ: A +5 µC charge is 0.3 m from a -2 µC charge. Calculate the force on the -2 µC charge. Answer: ( F = (8.99 \times 10^9) \frac{(5 \times 10^{-6})(2 \times 10^{-6})}{(0.3)^2} = 0.999 ) N, attractive (toward the +5 µC charge).
MCQ: Which of the following will not change the electric force between two charges? (A) Doubling both charges (B) Halving the distance (C) Placing the charges in water (dielectric) (D) Changing the sign of one charge Answer: (D) Changing the sign (magnitude of force stays the same; only direction changes).
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