By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Work, power, and the work-energy theorem connect force, motion, and energy—core ideas in physics. The work-energy theorem states that the work done on an object equals its change in kinetic energy, linking force and motion mathematically. This topic appears in ~15% of AP Physics 1 multiple-choice questions and is a frequent FRQ topic (e.g., analyzing a car’s braking distance or a roller coaster’s speed). Real-world example: When a pitcher throws a baseball, the work done by their arm muscles increases the ball’s kinetic energy, determining how fast it flies.
Example: Pushing a box horizontally does work; carrying it at constant height does not (force and displacement are perpendicular, cos90° = 0).
Kinetic Energy (KE): Energy of motion. Formula: KE = ½mv² (where m = mass, v = velocity). Unit: Joule (J).
Example: A 2 kg ball moving at 3 m/s has KE = ½(2)(3)² = 9 J.
Work-Energy Theorem: The net work done on an object equals its change in kinetic energy. Formula: W_net = ?KE = KE_f – KE_i.
Key idea: Work changes an object’s speed, not just its position.
Power (P): Rate of doing work. Formula: P = W/t (where W = work, t = time). Unit: Watt (W) or J/s.
Example: A 100 W lightbulb uses 100 J of energy per second.
Conservative vs. Nonconservative Forces:
Nonconservative forces (e.g., friction, air resistance) dissipate energy; work done depends on path.
Potential Energy (PE): Stored energy due to position. Gravitational PE: PE_g = mgh (where h = height). Spring PE: PE_s = ½kx² (where k = spring constant, x = displacement).
Example: A book on a shelf has gravitational PE; a stretched spring has elastic PE.
Mechanical Energy (ME): Sum of kinetic and potential energy. Formula: ME = KE + PE.
Conservation of ME: If only conservative forces act, ME is constant.
Efficiency: Ratio of useful work output to total work input. Formula: Efficiency = (W_out / W_in) × 100%.
Draw a free-body diagram. Label conservative (e.g., gravity) and nonconservative (e.g., friction) forces.
Calculate work done by each force:
For variable forces (e.g., springs): Use W = ?F·dx (AP Physics 1 rarely requires calculus; use W = ½kx² for springs).
Apply the work-energy theorem:
W_net = ?KE. If nonconservative forces act, W_nc = ?ME (change in mechanical energy).
Solve for the unknown:
Rearrange equations to find velocity, force, or displacement. Check units! (J = kg·m²/s²).
Check for energy conservation:
Example: A 5 kg block slides 10 m down a 30° incline with ?_k = 0.2. Find its speed at the bottom. - Step 1: Forces: gravity (conservative), friction (nonconservative). - Step 2: W_gravity = mgh = mgd·sin? = (5)(9.8)(10·sin30°) = 245 J. W_friction = -F_f·d = -?mg·cos?·d = -(0.2)(5)(9.8)(cos30°)(10)--84.9 J. - Step 3: W_net = 245 J – 84.9 J = 160.1 J = ?KE. - Step 4: 160.1 = ½(5)v²-v-8.0 m/s.
Correction: Work depends on the component of force parallel to displacement. If force and displacement are perpendicular (? = 90°), W = 0.
Mistake: Confusing work and power.
Correction: Work is energy transferred (Joules); power is the rate of energy transfer (Watts). A sprinter does the same work as a jogger to cover 100 m, but the sprinter has higher power because they do it faster.
Mistake: Ignoring nonconservative forces in energy problems.
Correction: If friction or air resistance acts, mechanical energy is not conserved. Use W_nc = ?ME.
Mistake: Misapplying the work-energy theorem to potential energy.
Correction: The theorem relates net work to ?KE, not ?PE. For PE changes, use W = -?PE (e.g., lifting an object increases PE, so work done by gravity is negative).
Mistake: Assuming all forces do work.
Power in context: A common FRQ asks for the power output of a motor lifting an object at constant speed (P = F·v).
Multiple-Choice Traps:
Units: AP loves to mix kW and W or J and kJ. Convert everything to base units (e.g., 1 kW = 1000 W).
Tricky Distinctions:
Conservative vs. Nonconservative: Conservative forces (e.g., gravity) have PE; nonconservative forces (e.g., friction) do not.
Experimental Design:
(D) 235 W Answer: (C) 59 W. P = F·v = mg·v = (2)(9.8)(3)-59 W.
Short FRQ: A 1000 kg car accelerates from rest to 20 m/s in 5 s. What is the average power output of the engine? Assume no friction. Answer: P = W/t = ?KE/t = (½mv²)/t = (½·1000·20²)/5 = 40,000 W = 40 kW.
Multiple Choice: A block slides down a frictionless incline. Which of the following remains constant?
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