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Data Sufficiency (DS) questions test your ability to determine whether given information is enough to answer a question—not to compute the answer itself. On the GMAT Focus Edition, DS appears exclusively in the Data Insights section (20 questions, 45 minutes). These questions often involve arithmetic (percentages, ratios, averages) and algebra (equations, inequalities, word problems). Mastering DS setups is critical because: - ~30% of Data Insights questions are DS (6–7 per test).- Wrong answers cost double: A misstep here hurts your score more than a single Quant or Verbal error.- Time pressure is extreme: You have ~2 minutes per question, so efficiency is non-negotiable.
Example GMAT-Style Question:If x and y are positive integers, is x/y > 1? 1. x > y 2. y = 5
Why this matters: This question tests inequality manipulation and sufficiency logic—core skills for DS. Many students waste time solving for x and y instead of asking: "Do I have enough info to answer the question?"
Example: If the question asks "Is x > 5?" and Statement 1 says "x > 3," it’s insufficient (x could be 4 or 6).
Variable Isolation
Example: For "Is x/y > 1?", rewrite as "Is x > y?" (since y is positive).
Plugging in Numbers (PIN)
Example: For "Is x² > 4?" and Statement 1: "x > -3," test x = -2 (yes) and x = 0 (no) → insufficient.
Rate × Time = Distance (RTD) Table
Example: | | Rate | Time | Work | |----------|------|------|-------| | Pipe A | 2 | t | 2t | | Pipe B | 3 | t | 3t | | Total| - | - | 5t |
Ratio Box
Example: | | Boys | Girls | Total | |--------|------|-------|-------| | Ratio | 3 | 4 | 7 | | Actual | 3x | 4x | 7x |
Inequality Manipulation Rules
Example: If x > y and y < 0, then x/y < 1 (because dividing by a negative flips the inequality).
Absolute Value Cases
Example: For "Is |x - 3| > 2?", split into:
Quadratic Identities
Follow this 4-step process for every DS question:
Identify the unknowns and what you’re solving for.
Analyze Statement 1 Alone
If no → Insufficient (eliminate A, D).
Analyze Statement 2 Alone
If insufficient → C or E.
Combine Statements (If Needed)
Question:If x and y are integers, is x > y? 1. x + y = 10 2. x² = y² + 20
Step 1: Understand the Question- We need to determine if x > y for integer x and y.
Step 2: Analyze Statement 1 Alone- x + y = 10 → x = 10 - y.- Possible pairs: (5,5), (6,4), (4,6), (7,3), (3,7), ... - For (6,4): x > y (yes).- For (4,6): x < y (no).- Insufficient (eliminate A, D).
Step 3: Analyze Statement 2 Alone- x² = y² + 20 → x² - y² = 20 → (x - y)(x + y) = 20.- Possible integer pairs: - (x - y, x + y) = (2, 10) → x = 6, y = 4 → x > y (yes). - (x - y, x + y) = (-2, -10) → x = -6, y = -4 → x < y (no).- Insufficient (eliminate B).
Step 4: Combine Statements- From Statement 1: x + y = 10.- From Statement 2: (x - y)(10) = 20 → x - y = 2.- Solve the system: - x + y = 10 - x - y = 2 - Add: 2x = 12 → x = 6, y = 4.- x > y is always true → Sufficient.- Answer: C.
Correct approach: Ask "Do I have enough info?" before solving.
Mistake: Forgetting to test edge cases (e.g., 0, negatives, fractions).
Correct approach: Always test x = 0, 1, -1, 0.5 when statements allow it.
Mistake: Assuming variables are positive unless stated.
Correct approach: Check if the question or statements restrict signs (e.g., "x and y are positive integers").
Mistake: Combining statements too early.
Correct approach: Always evaluate Statement 1 alone first, then Statement 2 alone, before combining.
Mistake: Misapplying inequality rules (e.g., forgetting to flip the sign when multiplying by a negative).
How to avoid: For yes/no, sufficiency means always yes or always no. For value, sufficiency means exactly one value.
Trap: Hidden Constraints
How to avoid: Read the question twice to catch all constraints.
Trap: Overlapping Statements
How to avoid: Treat each statement as independent until combining.
Timing:
Question:If x is a positive integer, is x divisible by 6? 1. x is divisible by 3. 2. x is divisible by 4.
Answer: CExplanation: Statement 1 alone is insufficient (e.g., x = 3 → no; x = 6 → yes). Statement 2 alone is insufficient (e.g., x = 4 → no; x = 12 → yes). Combined, x is divisible by both 3 and 4 → divisible by 12 → divisible by 6.
⚠️ Trap: If a statement seems sufficient but has one counterexample, it’s insufficient.
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