By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
(For the 320+ Scorer)
Probability and counting methods appear in ~15% of GRE Quant questions—often as standalone problems or embedded in Data Interpretation sets. Mastering these concepts lets you solve 2–3 extra questions per test, directly boosting your score. The GRE tests basic rules (AND/OR), counting principles (permutations/combinations), and conditional probability—but with tricky wording to disguise simple math.
Real GRE-Style Example:A box contains 5 red marbles and 3 blue marbles. If two marbles are drawn at random without replacement, what is the probability that both are red? (A) 5/14 (B) 5/8 (C) 25/64 (D) 5/16 (E) 3/28
Why it’s tested: The GRE rewards structured thinking over memorization. Probability questions test whether you can: 1. Translate words into math (e.g., "without replacement" → dependent events).2. Choose the right counting method (combinations vs. permutations).3. Avoid traps (e.g., misapplying "OR" vs. "AND" rules).
Example: Probability both marbles are red = (5/8) × (4/7) = 20/56 = 5/14.
OR (Addition Rule):
"Given that"? → Conditional probability.
List total possible outcomes:
For counting: Use FCP, permutations, or combinations.
List favorable outcomes:
Break into cases if needed (e.g., "exactly one red marble" = red then blue + blue then red).
Apply the correct formula:
Write out the formula before plugging in numbers to avoid mistakes.
Simplify and eliminate:
Compare answer choices to your result (e.g., if you get 5/14, eliminate choices like 5/8).
Check for traps:
Question:A committee of 4 is to be selected from 6 women and 3 men. What is the probability that the committee includes exactly 2 women?
Step 1: Identify the type.- Order doesn’t matter → combinations.- Probability of a specific group → favorable outcomes / total outcomes.
Step 2: Total possible outcomes.- Total ways to choose 4 people from 9: C(9, 4) = 126.
Step 3: Favorable outcomes.- Choose 2 women from 6: C(6, 2) = 15.- Choose 2 men from 3: C(3, 2) = 3.- Total favorable = 15 × 3 = 45.
Step 4: Apply probability formula.- P(exactly 2 women) = 45 / 126 = 5/14.
Step 5: Match to answer choices.- (A) 5/14 → Correct.
Step 6: Check for traps.- Did you use permutations? No (order doesn’t matter).- Did you miscount? C(6, 2) is 15, not 30.- Did you forget to multiply? 15 × 3 = 45, not 18.
Correct approach: Ask: "Does swapping two items create a new outcome?" If yes → permutations. If no → combinations.
Mistake: Ignoring "without replacement" in probability.
Correct approach: For sequential events without replacement, adjust the denominator (e.g., drawing two marbles: first draw = 8 total, second draw = 7 total).
Mistake: Adding probabilities for non-mutually exclusive events without subtracting overlap.
Correct approach: If events can occur together (e.g., drawing a red card or a king), subtract the overlap (red kings).
Mistake: Misapplying complementary probability.
Correct approach: For "at least one" problems, always use the complement (e.g., P(at least one head in 3 flips) = 1 – P(all tails)).
Mistake: Overcounting in combinations.
Avoid: Calculating "at least" when the question asks for "exactly."
Replacement vs. No Replacement:
Avoid: Assuming independence when events are dependent.
Order Matters vs. Doesn’t Matter:
Avoid: Using P(n, k) for a committee (order irrelevant).
Conditional Probability Misinterpretation:
Answer: (A) 1/3 Solution: P(Yellow and Yellow) = (6/10) × (5/9) = 30/90 = 1/3.
Answer: (C) 24 Solution: Order matters → permutations: P(4, 3) = 4 × 3 × 2 = 24.
⚠️ Memorize these distinctions:- P(A and B) vs. P(A or B).- Permutations vs. combinations.- Dependent vs. independent events.- C(n, k) vs. P(n, k).
Final Tip: On test day, write out the formula first before plugging in numbers. This prevents careless errors!
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