By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
By an Elite GRE Instructor (320+ Scorer Guarantee)
Triangles appear in ~15% of all GRE Quant questions—often disguised as word problems, coordinate geometry, or data sufficiency. Mastering them means 3–5 extra points on test day. The GRE tests three core triangle concepts: 1. Pythagorean Theorem (right triangles) 2. Special Right Triangles (30-60-90, 45-45-90) 3. Similar Triangles (proportional sides, angle matching)
Real GRE-Style Example:In the figure above, triangle ABC is a right triangle with legs of length 6 and 8. Point D lies on hypotenuse AC such that BD is perpendicular to AC. What is the length of BD? (Answer: 4.8 — but you’ll learn how to solve this in 30 seconds by the end of this guide.)
What it is: In a right triangle, (a^2 + b^2 = c^2), where (c) is the hypotenuse.When to use it:- Any right triangle with two sides given (solve for the third).- Coordinate geometry (distance between two points).- Word problems involving ladders, diagonals, or shadows.
What they are: Common right-triangle side ratios that always satisfy (a^2 + b^2 = c^2).When to use them:- Instant recognition saves time (no need to calculate).- Eliminate wrong answers in QC or multiple-choice questions.Key Triples:- 3-4-5 (and multiples: 6-8-10, 9-12-15, etc.) - 5-12-13 (and multiples: 10-24-26) - 7-24-25 (less common but tested) - 8-15-17 (rare but appears in harder questions)
What it is: Isosceles right triangle with sides in ratio (1 : 1 : \sqrt{2}).When to use it:- Square diagonals (diagonal = side × (\sqrt{2})).- Any isosceles right triangle (two equal sides, one right angle).- Coordinate geometry (e.g., points forming a 45° angle).
What it is: Right triangle with sides in ratio (1 : \sqrt{3} : 2) (short leg : long leg : hypotenuse).When to use it:- Equilateral triangle bisection (cut in half → 30-60-90).- Hexagon problems (internal triangles are 30-60-90).- Word problems with "height" or "shadow" (e.g., 30° angle of elevation).
What it is: Triangles with identical angles and proportional sides.When to use it:- Parallel lines cutting a triangle (creates similar triangles).- Shadow/height problems (e.g., "A 6-ft man casts a 4-ft shadow; how tall is a tree casting a 10-ft shadow?").- Overlapping triangles (look for shared angles).
Key Similarity Tests (AA, SAS, SSS):- AA (Angle-Angle): Two angles match → triangles are similar.- SAS (Side-Angle-Side): Two sides proportional + included angle equal → similar.- SSS (Side-Side-Side): All three sides proportional → similar.
What they are:- Area of a right triangle: (\frac{1}{2} \times \text{leg}_1 \times \text{leg}_2).- Perimeter: Sum of all sides (but hypotenuse is often the trap).When to use them:- QC questions comparing area vs. perimeter.- Word problems asking for "total fencing" or "paint needed."
Question:In the figure above, triangle ABC is a right triangle with legs AB = 6 and BC = 8. Point D lies on hypotenuse AC such that BD is perpendicular to AC. What is the length of BD?
Step 1: Identify the Triangle Type- Triangle ABC is a right triangle (given).- BD is perpendicular to AC → two right triangles inside ABC (ABD and BDC).
Step 2: Label All Given Information- AB = 6, BC = 8.- Angle B = 90°.- BD ⊥ AC → Angle BDA = Angle BDC = 90°.
Step 3: Apply the Correct Formula- First, find AC (hypotenuse of ABC) using Pythagorean Theorem: (AC = \sqrt{AB^2 + BC^2} = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10).- Now, triangles ABD and BDC are similar to ABC (all have a right angle + share another angle).- Proportion for BD (height): In right triangles, the height to the hypotenuse relates to the legs by: (BD = \frac{AB \times BC}{AC} = \frac{6 \times 8}{10} = \frac{48}{10} = 4.8).
Step 4: Solve for BD- (BD = 4.8).
Step 5: Check for Traps- Trap: Forgetting to find AC first.- Trap: Assuming BD is the average of AB and BC (wrong!).- Correct: Using the height formula for right triangles.
Answer: 4.8
Why it happens: Students rush and plug numbers into (a^2 + b^2 = c^2) without identifying (c) as the hypotenuse.Correct approach:- Always label the hypotenuse first (longest side, opposite the right angle).-Example: If sides are 5 and 12, hypotenuse is 13 (not 5 or 12).
Why it happens: Students leave answers like (\sqrt{50}) instead of (5\sqrt{2}), leading to wrong answer choices.Correct approach:- Simplify all radicals (e.g., (\sqrt{72} = 6\sqrt{2})).- Memorize common simplifications (e.g., (\sqrt{12} = 2\sqrt{3})).
Why it happens: Students see two triangles and assume they’re similar because they "look" alike.Correct approach:- Prove similarity using AA, SAS, or SSS.-Example: If two angles match, the triangles are similar (AA).
Why it happens: Students mix up the order of sides ((1 : \sqrt{3} : 2)).Correct approach:- Short leg (opposite 30°) = (x).- Long leg (opposite 60°) = (x\sqrt{3}).- Hypotenuse = (2x).-Example: If hypotenuse = 10, short leg = 5, long leg = (5\sqrt{3}).
Why it happens: Students miss right triangles in coordinate geometry or word problems.Correct approach:- Look for perpendicular lines (e.g., x-axis and y-axis).-Example: Distance between (1,2) and (4,6) → right triangle with legs 3 and 4 → hypotenuse = 5.
What it is: ETS gives sides that almost fit a Pythagorean triple but don’t (e.g., 5, 11, 12).How to avoid it:- Always verify (a^2 + b^2 = c^2) before assuming a triple.-Example: 5-11-12 → (25 + 121 = 146 \neq 144) → not a right triangle.
What it is: ETS draws two triangles that look similar but aren’t (e.g., same angles but sides not proportional).How to avoid it:- Check side ratios (e.g., (\frac{AB}{DE} = \frac{BC}{EF} = \frac{AC}{DF})).-Example: If (\frac{3}{6} \neq \frac{4}{7}), triangles are not similar.
What it is: Questions ask for the height of a triangle but don’t give enough info—until you realize it’s a 30-60-90 or 45-45-90.How to avoid it:- Look for hidden special triangles (e.g., equilateral triangle cut in half → 30-60-90).
In a 30-60-90 triangle, the hypotenuse is 12. What is the length of the side opposite the 60° angle? Answer: (6\sqrt{3}) Solution: Hypotenuse = (2x = 12) → (x = 6) → side opposite 60° = (x\sqrt{3} = 6\sqrt{3}).
Triangles ABC and DEF are similar. AB = 4, BC = 6, DE = 8. What is EF? Answer: 12 Solution: (\frac{AB}{DE} = \frac{BC}{EF}) → (\frac{4}{8} = \frac{6}{EF}) → (EF = 12).
Final Tip: On test day, draw every triangle—even if it’s given in the problem. Labeling sides and angles eliminates 90% of mistakes. Now go crush those Quant questions! ?
Join 4M+ learners. Unlock unlimited quizzes, wrong-answer tracking, flashcards + reminders, study guides, and 1-on-1 challenges.