By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
"Absolute value questions appear 4-6 times on every GRE and 3-5 times on the GMAT—master them, and you’ll gain 20+ points by avoiding careless traps and solving them in under 60 seconds."
The GRE/GMAT doesn’t test your ability to compute absolute values—it tests: 1. Logical reasoning under constraints – Can you handle cases where a variable could be positive or negative? 2. Precision in algebra – Do you avoid sign errors when squaring or taking square roots? 3. Efficiency in elimination – Can you spot and discard wrong answers without solving every case?
|x + 3| = 5
|2y - 1| ≤ 7
GRE-Style: If |3x - 4| = 8, which of the following could be the value of x? A) -4/3 B) 0 C) 4/3 D) 2 E) 4
GMAT-Style: If |2k + 5| > 7, which of the following must be true? A) k > 1 B) k < -6 C) k > 1 or k < -6 D) -6 < k < 1 E) k > -6
|A| = B
|A| > B
|A| < B
A > B
A < -B
-B < A < B
>
≥
<
≤
A = B
A = -B
B ≥ 0
Question: If |x - 2| = 5, what is the value of x? A) -7 B) -3 C) 3 D) 7 E) 3 or -3
Step-by-Step Solution: 1. Split into two cases: - x - 2 = 5 → x = 7 - x - 2 = -5 → x = -3 2. Check for extraneous solutions: Both are valid (5 ≥ 0). 3. Match to answer choices: Only D (7) and B (-3) are options, but the question asks for "the value of x" (singular). Since both are possible, the correct answer is E (3 or -3).
x - 2 = 5
x = 7
x - 2 = -5
x = -3
Elimination Logic: - A (-7) and C (3) don’t match either solution. - D (7) is correct but incomplete (misses -3). - E is the only option that includes both solutions.
Question: If |3y + 1| ≤ 10, which of the following must be true? A) y ≤ 3 B) y ≥ -11/3 C) -11/3 ≤ y ≤ 3 D) y ≤ -11/3 or y ≥ 3 E) y ≥ 3
Step-by-Step Solution: 1. Rewrite the inequality: -10 ≤ 3y + 1 ≤ 10 2. Solve for y: - Subtract 1: -11 ≤ 3y ≤ 9 - Divide by 3: -11/3 ≤ y ≤ 3 3. Match to answer choices: - A (y ≤ 3) is partially correct but misses the lower bound. - B (y ≥ -11/3) is partially correct but misses the upper bound. - C is fully correct. - D and E are wrong (D is the "or" version of the inequality, which is incorrect here).
-10 ≤ 3y + 1 ≤ 10
-11 ≤ 3y ≤ 9
-11/3 ≤ y ≤ 3
Elimination Logic: - A and B are half-truths (common traps). - D is the opposite of what we need (it’s for |A| ≥ B). - E is too restrictive.
|A| ≥ B
Question: If |x² - 4| = 5, which of the following could be the value of x? A) -3 B) -1 C) 0 D) 1 E) 3
Step-by-Step Solution: 1. Split into two cases: - x² - 4 = 5 → x² = 9 → x = 3 or x = -3 - x² - 4 = -5 → x² = -1 → No real solutions (discard this case). 2. Check answer choices: - A (-3) and E (3) are valid. - B (-1), C (0), and D (1) are invalid. 3. Since the question asks for "could be," either A or E is correct. But only A (-3) is an option here.
x² - 4 = 5
x² = 9
x = 3
x² - 4 = -5
x² = -1
Elimination Logic: - The trap is ignoring the second case (which has no solution) and picking a wrong answer. - Another trap is assuming x² = -1 has solutions (it doesn’t in real numbers).
B
A < B
|x| = 3
x = ±3
x > 0
and
or
|x - 2| = 3
x = 5
|x| = -2
x = ±2
|x - 2| = 5
|-3 - 2| = 5
B < 0
|x - 1| < 3
-2 < x < 4
"Here’s the exact process to solve any absolute value question in under 60 seconds:
Inequality (|A| > B) → Rewrite as A > B or A < -B.
Solve each case separately.
For inequalities, combine the results (use "or" for >/≥).
Apply constraints (e.g., "x is positive") and eliminate wrong answers.
If it says "must be," ensure the answer covers all cases.
Watch for traps:
That’s it. No extra steps, no overcomplicating. Split, solve, eliminate, and move on."
By following this framework, you’ll consistently solve absolute value questions correctly and quickly, boosting your score by 20+ points.
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