By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Score Impact: "Number Properties questions appear 4-6 times per GRE Quant section and 3-5 times per GMAT Quant section—mastering them can boost your score by 50+ points, moving you from the 60th to the 80th percentile."
The GRE/GMAT doesn’t test advanced math—it tests logical reasoning under constraints. Number Properties questions probe: 1. Precision in applying definitions (e.g., prime, integer, even/odd, factors/multiples) without overcomplicating. 2. Pattern recognition—spotting hidden relationships (e.g., divisibility rules, consecutive integers, remainders). 3. Elimination efficiency—using answer choices to reverse-engineer the solution when algebra stalls.
Trap: Students waste time on complex algebra when simple number substitution or divisibility rules would suffice.
Question: If x is an integer greater than 1, which of the following must be true? I. x² – x is even II. x³ + 1 is divisible by 3 III. x² + 1 is prime
(A) I only (B) II only (C) I and II only (D) I and III only (E) I, II, and III
Run this process for every Number Properties question:
Example: Here, x is an integer > 1.
Test small numbers first.
Why? Small numbers reveal patterns faster than algebra.
Evaluate each statement separately.
If a statement fails for any value, eliminate it.
Eliminate answer choices.
Example: If II fails for x = 2, eliminate (B), (C), and (E).
Check edge cases.
Why? Some statements fail only at extremes.
Confirm the remaining choice.
Question: If n is a positive integer, which of the following must be true? I. n² + n is even II. n³ – n is divisible by 6 III. n² + 1 is odd
Step-by-Step: 1. Constraints: n is a positive integer. 2. Test n = 1, 2, 3: - I: 1² + 1 = 2 (even), 2² + 2 = 6 (even), 3² + 3 = 12 (even) → True. - II: 1³ – 1 = 0 (divisible by 6), 2³ – 2 = 6 (divisible by 6), 3³ – 3 = 24 (divisible by 6) → True. - III: 1² + 1 = 2 (even) → False (must be odd). 3. Eliminate: III is false → eliminate (D) and (E). 4. Check n = 4: - II: 4³ – 4 = 60 (divisible by 6) → still true. 5. Answer: (C) I and II only.
Question: If k is an integer and k² – 4k + 3 is odd, which of the following must be true? (A) k is even (B) k is odd (C) k is a multiple of 3 (D) k + 1 is even (E) k – 1 is odd
Trap: Students assume k must be odd because k² is odd. But k² – 4k + 3 is odd, not k² alone.
Step-by-Step: 1. Constraints: k is an integer; k² – 4k + 3 is odd. 2. Test k = 0, 1, 2, 3: - k = 0: 0 – 0 + 3 = 3 (odd) → k is even. - k = 1: 1 – 4 + 3 = 0 (even) → invalid. - k = 2: 4 – 8 + 3 = –1 (odd) → k is even. - k = 3: 9 – 12 + 3 = 0 (even) → invalid. 3. Pattern: Only even k values work. 4. Check k = –2: 4 + 8 + 3 = 15 (odd) → k is even. 5. Eliminate: - (B) k is odd → false. - (C) k is a multiple of 3 → false (k = 2 works). - (D) k + 1 is even → k = 0 → 1 (odd) → false. - (E) k – 1 is odd → k = 2 → 1 (odd) → True, but k = 0 → –1 (odd) → True. - Wait: (A) k is even → True for all valid k. 6. Answer: (A) k is even.
Why (E) is wrong: It’s sometimes true, but the question asks for must be true.
Question: If p is a prime number greater than 3, which of the following must be divisible by 12? (A) p² – 1 (B) p² + 1 (C) p³ – p (D) p⁴ – 1 (E) p⁴ + p²
Step-by-Step: 1. Constraints: p is prime > 3 → p is odd and not divisible by 3. 2. Test p = 5, 7: - A: 5² – 1 = 24 (divisible by 12), 7² – 1 = 48 (divisible by 12). - B: 5² + 1 = 26 (not divisible by 12). - C: 5³ – 5 = 120 (divisible by 12), 7³ – 7 = 336 (divisible by 12). - D: 5⁴ – 1 = 624 (divisible by 12), 7⁴ – 1 = 2400 (divisible by 12). - E: 5⁴ + 5² = 625 + 25 = 650 (not divisible by 12). 3. Eliminate: (B) and (E) are out. 4. Check divisibility by 3 and 4 (since 12 = 3 × 4): - A: p² – 1 = (p – 1)(p + 1). - p is odd → p – 1 and p + 1 are consecutive even numbers → one is divisible by 4. - p is prime > 3 → p is not divisible by 3 → either p – 1 or p + 1 is divisible by 3. - Thus, p² – 1 is divisible by 12. - C: p³ – p = p(p² – 1). - p² – 1 is divisible by 12 (from A), and p is odd → total divisibility by 12. - D: p⁴ – 1 = (p² – 1)(p² + 1). - p² – 1 is divisible by 12 (from A), and p² + 1 is even → total divisibility by 24. 5. Narrow down: (A), (C), and (D) work. But the question asks for must be divisible by 12. - (A) is the simplest expression that always satisfies this. 6. Answer: (A).
Why it’s wrong: "Must be true" means all valid numbers, not "most."
The Overcomplication Trap
Why it’s wrong: The GMAT/GRE favors simple patterns (e.g., n(n + 1) is always even).
The Reverse Logic Error
Why it’s wrong: Only the second statement is always true.
The "Too Specific" Answer
Correct approach: Check the stem for constraints (e.g., "positive integer" vs. "integer").
Mistake: Skipping number substitution.
Correct approach: Test n = 1, 2, 3 first—it’s faster than factoring.
Mistake: Misapplying divisibility rules.
Correct approach: A number is divisible by 6 only if it’s divisible by both 2 and 3.
Mistake: Ignoring Roman numeral questions.
Correct approach: Evaluate each statement independently before looking at answer choices.
Mistake: Forgetting to test edge cases.
Example: If II fails for n = 2, eliminate all choices containing II.
Use divisibility shortcuts:
A number is divisible by 9 if the sum of its digits is divisible by 9.
Even/odd rules:
Even × Any = Even
Prime number shortcuts:
p² – 1 is always divisible by 24 for primes > 3.
Consecutive integers:
"Here’s the exact process to crush Number Properties questions in under 2 minutes:
Remember: The GMAT/GRE doesn’t test math—it tests your ability to spot patterns under pressure. Master this framework, and you’ll gain 50+ points."
Final Tip: Drill 10–15 Number Properties questions daily for 2 weeks. Focus on speed + elimination, not perfection. You’ve got this!
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