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Intermediate — Requires understanding of ratios, crosses, and distinction between Mendelian and non-Mendelian patterns, but based entirely on NCERT examples.
Trap: Assuming the phenotypic ratio is always 3:1 in all monohybrid crosses. Avoid: Remember that in incomplete dominance, the phenotypic ratio is 1:2:1, same as genotypic ratio.
Trap: Believing the Law of Independent Assortment applies to all genes regardless of location. Avoid: It applies only to genes located on different (non-homologous) chromosomes or far apart on the same chromosome.
Trap: Confusing test cross with back cross. Avoid: A test cross is always with homozygous recessive; a back cross is with any parent, used in breeding programs.
In a monohybrid cross between two heterozygous tall pea plants (Tt), what proportion of the offspring is expected to be dwarf? A) 1/4 B) 1/2 C) 3/4 D) 1/8 Answer: A) 1/4 Explanation: The cross Tt × Tt gives 1 TT : 2 Tt : 1 tt; tt (dwarf) is 1/4. Why others fail: B) 1/2 is the proportion of heterozygotes, not dwarfs.
Which of the following correctly represents the F? phenotypic ratio in a dihybrid cross? A) 3:1 B) 1:2:1 C) 9:3:3:1 D) 1:1 Answer: C) 9:3:3:1 Explanation: This ratio results from independent assortment of two genes. Why others fail: A) 3:1 is monohybrid cross ratio; students may misapply it.
In a cross between red-flowered and white-flowered snapdragons, the F? progeny have pink flowers. What is the probability of getting red flowers in the F? generation? A) 100% B) 75% C) 50% D) 25% Answer: D) 25% Explanation: Incomplete dominance gives 1 red (RR) : 2 pink (Rr) : 1 white (rr), so red is 1/4. Why others fail: B) 75% is the dominant phenotype in complete dominance; not applicable here.
Which Mendelian law is verified by a test cross involving a single trait? A) Law of Dominance B) Law of Segregation C) Law of Independent Assortment D) Both A and B Answer: B) Law of Segregation Explanation: Test cross reveals segregation of alleles into gametes. Why others fail: D is tempting because dominance is observed, but segregation is being tested.
A plant with genotype RrYy is self-pollinated. How many types of genotypes are expected in the progeny? A) 4 B) 9 C) 16 D) 8 Answer: B) 9 Explanation: For two genes, number of genotypes = 3? = 3² = 9 (e.g., RRYY, RRYy, RRyy, RrYY, RrYy, Rryy, rrYY, rrYy, rryy). Why others fail: C) 16 is the number of possible zygotes (4×4), not distinct genotypes.
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