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Study Guide: CUET UG Physics Mechanics Work Energy Power Conservation Laws Collisions
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CUET UG Physics Mechanics Work Energy Power Conservation Laws Collisions

By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.

⏱️ ~5 min read

Must‑Know

  • Work done by a constant force is ( W = \vec{F} \cdot \vec{s} = Fs\cos\theta ); for example, when a force of 10 N displaces an object by 5 m at 60°, ( W = 10 \times 5 \times \cos60^\circ = 25 \text{ J} ).
  • Work done is zero when displacement is perpendicular to force; e.g., centripetal force does no work in uniform circular motion.
  • Kinetic energy ( K = \frac{1}{2}mv^2 ); a 2 kg object moving at 3 m/s has ( K = \frac{1}{2} \times 2 \times 9 = 9 \text{ J} ).
  • Work-Energy Theorem: ( W_{\text{net}} = \Delta K ); if a net work of 50 J is done on a body, its kinetic energy increases by 50 J.
  • Conservative forces conserve mechanical energy; e.g., gravitational force is conservative, friction is non-conservative.
  • Potential energy for gravity near Earth’s surface: ( U = mgh ); a 1 kg mass at 10 m height has ( U = 1 \times 9.8 \times 10 = 98 \text{ J} ).
  • For a spring, ( U = \frac{1}{2}kx^2 ); a spring of ( k = 200 \text{ N/m} ) compressed by 0.1 m stores ( U = \frac{1}{2} \times 200 \times (0.1)^2 = 1 \text{ J} ).
  • Power ( P = \frac{W}{t} = \vec{F} \cdot \vec{v} ); a force of 10 N acting on a body moving at 4 m/s delivers ( P = 10 \times 4 = 40 \text{ W} ).
  • 1 horsepower = 746 W; used in vehicle engine ratings.
  • In elastic collisions, both momentum and kinetic energy are conserved; e.g., two identical balls colliding head-on exchange velocities.
  • In inelastic collisions, momentum is conserved but kinetic energy is not; e.g., a bullet embedding in a block.
  • Perfectly inelastic collision: maximum kinetic energy loss; objects stick together after collision.
  • Coefficient of restitution ( e = \frac{v_2 - v_1}{u_1 - u_2} ); for perfectly elastic collision, ( e = 1 ); for perfectly inelastic, ( e = 0 ).
  • In one-dimensional elastic collision between two masses ( m_1 ) and ( m_2 ), final velocities are:
    ( v_1 = \frac{(m_1 - m_2)u_1 + 2m_2u_2}{m_1 + m_2} ),
    ( v_2 = \frac{(m_2 - m_1)u_2 + 2m_1u_1}{m_1 + m_2} ).
  • If ( m_1 = m_2 ) and ( u_2 = 0 ), then ( v_1 = 0 ), ( v_2 = u_1 ) (velocity exchange).
  • In two-dimensional elastic collision, momentum is conserved along both x and y axes; kinetic energy is also conserved.
  • For an isolated system, total momentum is conserved in all collisions; verified from NCERT.
  • Mechanical energy is conserved only in the absence of non-conservative forces like friction.
  • The area under a force-displacement graph gives work done; e.g., constant force of 10 N over 5 m gives area = 50 J.
  • Negative work occurs when force opposes displacement; e.g., kinetic friction always does negative work.

Difficulty Level

Intermediate — requires understanding of vector dot products, conservation laws, and ability to apply formulas in collision problems.

Common CUET Traps

  • Trap: Assuming kinetic energy is conserved in all collisions. Avoid: Remember kinetic energy is conserved only in elastic collisions.
  • Trap: Using ( W = F s ) without considering angle ( \theta ). Avoid: Always use ( W = F s \cos\theta ), especially when force and displacement are not aligned.
  • Trap: Confusing power with energy. Avoid: Power is rate of doing work (( P = W/t )), not total work.

Practice MCQs

  1. A force of 20 N acts on a body at an angle of 60° to displacement of 4 m. The work done is:
    A. 40 J
    B. 80 J
    C. 160 J
    D. 20 J
    Answer: A
    Explanation: ( W = Fs\cos\theta = 20 \times 4 \times \cos60^\circ = 80 \times 0.5 = 40 \text{ J} ).
    Why others fail: B ignores the cosine factor and uses ( W = Fs ) directly.

  2. A 2 kg block moves with speed 5 m/s. Its kinetic energy is:
    A. 10 J
    B. 25 J
    C. 50 J
    D. 100 J
    Answer: B
    Explanation: ( K = \frac{1}{2}mv^2 = \frac{1}{2} \times 2 \times 25 = 25 \text{ J} ).
    Why others fail: C results from forgetting the ( \frac{1}{2} ) in kinetic energy formula.

  3. In a perfectly inelastic collision between two objects of equal mass moving toward each other with equal speed, the final kinetic energy is:
    A. Equal to initial
    B. Half of initial
    C. Zero
    D. One-fourth of initial
    Answer: C
    Explanation: Objects stick together and come to rest due to equal and opposite momenta; total momentum is zero, so final velocity is zero.
    Why others fail: B is chosen by those who confuse with energy loss in general inelastic collisions.

  4. A ball falls from height ( h ) and rebounds to height ( 0.64h ). The coefficient of restitution is:
    A. 0.64
    B. 0.8
    C. 0.9
    D. 0.7
    Answer: B
    Explanation: ( e = \sqrt{\frac{h'}{h}} = \sqrt{0.64} = 0.8 ).
    Why others fail: A is chosen by those who use height ratio directly instead of square root.

  5. A 10 kg mass moving at 6 m/s collides elastically with a stationary 2 kg mass. The final velocity of the 2 kg mass is:
    A. 8 m/s
    B. 10 m/s
    C. 12 m/s
    D. 14 m/s
    Answer: B
    Explanation: Using ( v_2 = \frac{2m_1u_1}{m_1 + m_2} = \frac{2 \times 10 \times 6}{10 + 2} = \frac{120}{12} = 10 \text{ m/s} ).
    Why others fail: A results from incorrect application of momentum conservation without considering elastic collision formula.

Last‑Minute Revision

  • ⚠️ Work is scalar, but sign depends on angle between ( \vec{F} ) and ( \vec{s} ).
  • ⚠️ ( W = 0 ) if ( \theta = 90^\circ ) — e.g., Earth’s gravity does no work on satellite in circular orbit.
  • ⚠️ ( \Delta K = W_{\text{net}} ) — Work-Energy Theorem applies even with variable forces.
  • ⚠️ Conservative force: work path-independent; e.g., gravity.
  • ⚠️ Non-conservative force: work path-dependent; e.g., friction.
  • ⚠️ ( U_{\text{grav}} = mgh ) only near Earth’s surface.
  • ⚠️ ( U_{\text{spring}} = \frac{1}{2}kx^2 ) — x is displacement from equilibrium.
  • ⚠️ Power ( P = Fv\cos\theta ) — instantaneous power.
  • ⚠️ 1 hp = 746 W — standard conversion.
  • ⚠️ In elastic collision: ( \Delta K = 0 ), ( \Delta p = 0 ).
  • ⚠️ In inelastic collision: ( \Delta p = 0 ), ( \Delta K \neq 0 ).
  • ⚠️ Perfectly inelastic: ( e = 0 ), maximum KE loss.
  • ⚠️ ( e = \sqrt{\frac{h_{\text{rebound}}}{h_{\text{fall}}}} ) — for vertical bounce.
  • ⚠️ Head-on elastic collision: velocities exchange if masses equal and one initially at rest.
  • ⚠️ Momentum conserved in all isolated systems — key for collision problems.
  • ⚠️ 2D collision: conserve momentum separately in x and y.
  • ⚠️ Area under F-s graph = work done — true for all force types.
  • ⚠️ Negative work: force component opposite to displacement.
  • ⚠️ Spring force is conservative — mechanical energy conserved in spring-mass system.
  • ⚠️ Mnemonic: “Elastic – Energy Conserved; Inelastic – Stick Together” – helps recall collision types.


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