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Intermediate — requires understanding of nomenclature rules, isomer types, and application of stability concepts, but no advanced theory beyond NCERT.
Q1. What is the correct IUPAC name of [Co(NH?)?Cl]Cl A. Pentamminechlorocobalt(III) chloride B. Chloropentamminecobalt(III) chloride C. Pentamminechloridocobalt(III) chloride D. Pentamminecobalt(III) chloride chloride
Answer: C Explanation: Ligands are named alphabetically as "chlorido" and "ammine", with "penta" prefix; "chlorido" comes before "ammine" alphabetically. Why others fail: Option A uses outdated "chloro" instead of "chlorido" and incorrect order.
Q2. Which type of isomerism is shown by [Cr(H?O)?]Cl? and [CrCl(H?O)?]Cl?·H?O? A. Ionization isomerism B. Linkage isomerism C. Hydrate isomerism D. Coordination isomerism
Answer: C Explanation: These are hydrate isomers because water molecules are either inside or outside the coordination sphere. Why others fail: Option A is tempting because ions differ, but the key difference is position of H?O, not counter ion exchange.
Q3. Which complex shows optical isomerism? A. [Co(NH?)?Cl?]? B. [Pt(NH?)?Cl?] C. [Co(en)?]³? D. [Cu(NH?)?]²?
Answer: C Explanation: [Co(en)?]³? has no plane of symmetry and exists as non-superimposable mirror images due to bidentate en ligands. Why others fail: Option A has geometrical isomers but is not chiral; students often confuse geometrical with optical isomerism.
Q4. The stability constant for [Cu(NH?)?]²? is 2.1 × 10¹³. What does this imply? A. The complex is highly unstable B. The complex formation is negligible C. The complex is very stable D. The value refers to dissociation
Answer: C Explanation: A high value (2.1 × 10¹³) indicates the complex is very stable in solution. Why others fail: Option D is tempting because students confuse stability constant with dissociation constant;-refers to formation.
Q5. Which pair represents linkage isomers? A. [Co(NH?)?NO?]²? and [Co(NH?)?ONO]²? B. [Co(NH?)?][Cr(CN)?] and [Cr(NH?)?][Co(CN)?] C. [Co(NH?)?Br]SO? and [Co(NH?)?SO?]Br D. [Pt(NH?)?Cl?] (cis) and (trans)
Answer: A Explanation: NO can bind via nitrogen (nitro) or oxygen (nitrito), forming linkage isomers. Why others fail: Option C shows ionization isomerism, which is structurally similar but involves different ions, not donor atoms.
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