By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Intermediate — Requires conceptual clarity on direction of emf and application of formulas in dynamic situations like motional emf, but direct numericals are common and formula-based.
Trap: Assuming induced emf depends on magnetic flux rather than rate of change of flux. Avoid: Emf is induced only when flux is changing, not when it's high or constant.
Trap: Using ( Blv ) for motional emf even when velocity is not perpendicular to B. Avoid: Use ( \varepsilon = Blv\sin\theta ), where θ is angle between ( \vec{v} ) and ( \vec{B} ); max emf at θ = 90°.
Trap: Taking induced current direction from Faraday’s law without applying Lenz’s law. Avoid: Always determine change in flux first, then apply Lenz’s law to find opposing current direction.
Q1. A 0.5 m long conductor moves perpendicular to a uniform magnetic field of 0.4 T with a speed of 3 m/s. What is the induced emf? A. 0.6 V B. 1.2 V C. 0.2 V D. 0.4 V Answer: A Explanation: ( \varepsilon = Blv = 0.4 \times 0.5 \times 3 = 0.6\,V ) Why others fail: B uses length as 1 m (misread), common calculation error.
Q2. According to Lenz’s law, the induced current in a coil will flow such that it: A. Increases the magnetic flux B. Opposes the source voltage C. Opposes the change in magnetic flux D. Supports the motion of magnet Answer: C Explanation: Lenz’s law states induced current opposes the change in flux. Why others fail: A is opposite; students confuse “opposes change” with “opposes flux”.
Q3. A rectangular loop moves into a uniform magnetic field perpendicular to its plane. The induced emf is: A. Zero throughout B. Constant during entry C. Increases linearly with time D. Present only during entry and exit Answer: D Explanation: Emf is induced only when flux is changing (during entry/exit). Why others fail: B assumes constant rate means constant emf, but emf is non-zero only during motion across boundary.
Q4. A metallic rod of length l rotates with angular velocity ω about one end in a uniform magnetic field B perpendicular to the plane of rotation. The emf induced between ends is: A. ( Bl\omega ) B. ( \frac{1}{2}Bl^2\omega ) C. ( Bl^2\omega ) D. ( \frac{1}{2}Bl\omega ) Answer: B Explanation: Derived from integration of ( d\varepsilon = Bv\,dr ); result is ( \varepsilon = \frac{1}{2}Bl^2\omega ). Why others fail: A is motional emf for linear motion; students misapply formula.
Q5. Two coils are placed near each other. The mutual inductance M depends on: A. Current in primary coil B. Rate of change of current in secondary C. Number of turns and relative position D. Material of wire Answer: C Explanation: M depends on geometry, number of turns, orientation, and distance — not on current or material. Why others fail: A is tempting because M relates to flux per unit current, but M itself is independent of current.
Join 4M+ learners. Unlock unlimited quizzes, wrong-answer tracking, flashcards + reminders, study guides, and 1-on-1 challenges.