By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Intermediate — requires understanding of discriminant, root relationships, and algebraic manipulation, but no advanced theorems.
Question: What is the nature of roots of ( 2x^2 - 4x + 3 = 0 )? A) Real and equal B) Real and distinct C) Complex D) Rational Answer: C Explanation: ( D = (-4)^2 - 4(2)(3) = 16 - 24 = -8 < 0 ), so roots are complex. Why others fail: Option B is tempting if student miscalculates discriminant as positive.
Question: If the sum of roots of a quadratic equation is 5 and product is 6, what is the equation? A) ( x^2 + 5x + 6 = 0 ) B) ( x^2 - 5x + 6 = 0 ) C) ( x^2 - 6x + 5 = 0 ) D) ( x^2 + 6x + 5 = 0 ) Answer: B Explanation: Equation is ( x^2 - (\text{sum})x + \text{product} = x^2 - 5x + 6 = 0 ). Why others fail: Option A is tempting if student forgets sign of sum.
Question: If one root of ( 3x^2 - 9x + k = 0 ) is 2, what is the value of ( k )? A) 3 B) 6 C) 9 D) 12 Answer: B Explanation: Substituting ( x = 2 ): ( 3(4) - 9(2) + k = 0 \Rightarrow 12 - 18 + k = 0 \Rightarrow k = 6 ). Why others fail: Option C is tempting if student miscalculates ( 3(4) = 12 ) but adds instead of subtracts.
Question: For what value of ( p ) does the equation ( x^2 - 2px + 16 = 0 ) have equal roots? A) 2 B) 4 C) 8 D) 16 Answer: B Explanation: For equal roots, ( D = 0 \Rightarrow (-2p)^2 - 4(1)(16) = 0 \Rightarrow 4p^2 = 64 \Rightarrow p^2 = 16 \Rightarrow p = \pm 4 ), so ( p = 4 ) is valid. Why others fail: Option C is tempting if student sets ( 2p = 16 ) directly.
Question: If the roots of ( x^2 - 7x + 12 = 0 ) are ( \alpha ) and ( \beta ), what is ( \alpha^2 + \beta^2 )? A) 13 B) 24 C) 25 D) 49 Answer: C Explanation: ( \alpha + \beta = 7 ), ( \alpha\beta = 12 ), so ( \alpha^2 + \beta^2 = 7^2 - 2(12) = 49 - 24 = 25 ). Why others fail: Option D is tempting if student forgets to subtract ( 2\alpha\beta ).
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