By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Introduction "Mastering straight-line graphs unlocks 5–10% of your GCSE Physics, Chemistry, or Biology exam—questions on reaction rates, motion, and enzyme kinetics all rely on y=mx+c. Get this right, and you’ll spot trends, calculate gradients, and predict values in seconds."
Formula: y = mx + c - m = gradient (slope) → MEMORISE THIS - c = y-intercept (where the line crosses the y-axis) → MEMORISE THIS - x and y = coordinates of any point on the line
Formula: m = (change in y) / (change in x) = (y₂ – y₁) / (x₂ – x₁) - Given two points (x₁, y₁) and (x₂, y₂), plug into the formula. - MEMORISE THIS – Examiners won’t always give it.
Formula: m₁ × m₂ = –1 (if two lines are perpendicular) - If Line 1 has gradient m₁, then Line 2 (perpendicular) has gradient m₂ = –1/m₁. - MEMORISE THIS – A common exam trap.
Example: y = 2x + 5 - m = 2 (gradient) - c = 5 (y-intercept)
Step 1: Identify m and c. - m = 3 (gradient) - c = –2 (y-intercept)
Step 2: Plot y-intercept at (0, –2).
Step 3: Use gradient m = 3 = 3/1 (rise/run). - From (0, –2), move up 3, right 1 → (1, 1).
Step 4: Draw the line through (0, –2) and (1, 1).
What we did and why: - We used y = mx + c to find key points. - Gradient told us how steep the line is. - Y-intercept gave us the starting point.
Points: (2, 5) and (4, 11)
Step 1: Find gradient (m). - m = (11 – 5) / (4 – 2) = 6 / 2 = 3
Step 2: Use y = mx + c and one point to find c. - Plug in (2, 5): 5 = 3(2) + c → 5 = 6 + c → c = –1
Step 3: Write the equation. - y = 3x – 1
What we did and why: - We calculated gradient first because it’s needed for the equation. - Used one point to solve for c. - Final equation matches both points.
Question: A line has equation y = 4x + 1. Find the equation of a line perpendicular to it passing through (0, 3).
Step 1: Find gradient of given line (m₁ = 4).
Step 2: Find perpendicular gradient (m₂). - m₁ × m₂ = –1 → 4 × m₂ = –1 → m₂ = –1/4
Step 3: Use point (0, 3) to find c. - y = mx + c → 3 = (–1/4)(0) + c → c = 3
Step 4: Write the equation. - y = –1/4 x + 3
What we did and why: - Used the perpendicular rule (m₁ × m₂ = –1). - Plugged in the point to find c. - Final equation is perpendicular and passes through (0, 3).
CORRECT APPROACH: Always write y = mx + c first. m is with x, c is alone.
MISTAKE: Calculating gradient as run / rise instead of rise / run.
CORRECT APPROACH: Gradient = (change in y) / (change in x).
MISTAKE: Forgetting the negative sign in perpendicular gradients.
CORRECT APPROACH: Always check: m₁ × m₂ = –1 for perpendicular lines.
MISTAKE: Plotting the y-intercept at (c, 0) instead of (0, c).
CORRECT APPROACH: Y-intercept is always on the y-axis → (0, c).
MISTAKE: Not simplifying the gradient fraction.
HOW TO AVOID IT: Always label points as (x₁, y₁) and (x₂, y₂) before calculating.
TRAP: Asking for a line parallel to 2y = 4x + 6 (not in y = mx + c form).
HOW TO AVOID IT: Rearrange to y = mx + c first (y = 2x + 3).
TRAP: Perpendicular line questions with a negative gradient.
"Here’s the night-before cheat sheet: 1. Equation: y = mx + c → m = gradient, c = y-intercept. 2. Gradient: m = (y₂ – y₁) / (x₂ – x₁). Rise over run. 3. Parallel lines: Same m. 4. Perpendicular lines: m₁ × m₂ = –1. Flip the fraction and change the sign. 5. Plotting: Start at (0, c), then use m to find the next point. 6. Exam traps: Watch for unsimplified equations, wrong point order, and negative gradients. You’ve got this—go ace that graph question!"
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