By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
GCSE & A-Level Maths
"Mastering percentage increase and decrease lets you tackle real-life money problems—salary raises, discounts, inflation—and secures 5-10 marks in your GCSE/A-Level exam. One wrong step here could cost you a grade, but follow this guide, and you’ll solve them in under 60 seconds."
Formula: New Value = Original Value × (1 + Percentage Increase as a Decimal) Variables: - Original Value = Starting amount. - Percentage Increase = % added (e.g., 15% = 0.15). - New Value = Result after increase.
New Value = Original Value × (1 + Percentage Increase as a Decimal)
MEMORISE THIS – Not given on exam sheets.
Formula: New Value = Original Value × (1 – Percentage Decrease as a Decimal) Variables: - Original Value = Starting amount. - Percentage Decrease = % removed (e.g., 10% = 0.10). - New Value = Result after decrease.
New Value = Original Value × (1 – Percentage Decrease as a Decimal)
Formula: Percentage Change = [(New Value – Original Value) / Original Value] × 100 Variables: - Original Value = Starting amount. - New Value = Amount after change. - Percentage Change = % increase or decrease.
Percentage Change = [(New Value – Original Value) / Original Value] × 100
GIVEN ON EXAM SHEET (but memorise for speed).
Formula: Original Value = New Value / (1 ± Percentage Change as a Decimal) - Use + if it was an increase. - Use – if it was a decrease.
Original Value = New Value / (1 ± Percentage Change as a Decimal)
Question: A laptop costs £600. Its price increases by 15%. What is the new price?
Solution: 1. Increase → Use 1 + 0.15 = 1.15. 2. Multiply: £600 × 1.15 = £690.
1 + 0.15 = 1.15
Answer: £690.
What we did and why: - We converted 15% to 0.15 and added it to 1 to get the multiplier (1.15). - Multiplying by 1.15 gives the new value after a 15% increase.
Question: A jacket is reduced by 30% in a sale. It now costs £56. What was the original price?
Solution: 1. Decrease → Use 1 – 0.30 = 0.70. 2. Reverse percentage: Original = £56 ÷ 0.70 = £80.
1 – 0.30 = 0.70
Answer: £80.
What we did and why: - We converted 30% to 0.30 and subtracted from 1 to get the multiplier (0.70). - Since £56 is after the decrease, we divided by 0.70 to find the original price.
Question: A phone’s value decreases by 20% in the first year and then by 10% in the second year. If it’s worth £360 after 2 years, what was its original price?
Solution: 1. First decrease (20%): Multiplier = 1 – 0.20 = 0.80. 2. Second decrease (10%): Multiplier = 1 – 0.10 = 0.90. 3. Combined multiplier: 0.80 × 0.90 = 0.72. 4. Reverse percentage: Original = £360 ÷ 0.72 = £500.
Answer: £500.
What we did and why: - We multiplied the multipliers (0.80 × 0.90) to find the total change over 2 years. - Then, we divided the final value by the combined multiplier to find the original price.
"Here’s the fastest way to solve percentage increase/decrease problems: 1. For increases: Multiply by (1 + decimal) (e.g., 15% = 1.15). 2. For decreases: Multiply by (1 – decimal) (e.g., 10% = 0.90). 3. For reverse %: Divide by the multiplier (e.g., new price ÷ 0.80 for a 20% decrease). 4. For multi-step %: Multiply the multipliers (e.g., 20% then 10% = 0.80 × 0.90). 5. Always check: Does the answer make sense? A decrease should be smaller, an increase larger.
(1 + decimal)
(1 – decimal)
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