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Study Guide: How to Solve: Percentage Increase and Decrease
Source: https://www.fatskills.com/gcse-math/chapter/how-to-solve-percentage-increase-and-decrease

How to Solve: Percentage Increase and Decrease

By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.

⏱️ ~4 min read

How to Solve: Percentage Increase and Decrease

GCSE & A-Level Maths


Introduction

"Mastering percentage increase and decrease lets you tackle real-life money problems—salary raises, discounts, inflation—and secures 5-10 marks in your GCSE/A-Level exam. One wrong step here could cost you a grade, but follow this guide, and you’ll solve them in under 60 seconds."


What You Need To Know First

  1. Basic percentages – How to find 10%, 50%, etc., of a number.
  2. Decimal multiplication – Converting percentages to decimals (e.g., 20% = 0.2).
  3. Reverse percentages – Finding the original value after a change (covered later).

Key Vocabulary

Term Plain-English Definition Quick Example
Original Value The starting amount before any change. £50 before a discount.
New Value The amount after the increase or decrease. £40 after a 20% discount.
Percentage Change The % by which the original value increases/decreases. 20% increase = original + 20%.
Multiplier A decimal that multiplies the original to get the new value. 1.20 for a 20% increase.
Reverse Percentage Finding the original value when given the new value. If £40 is after a 20% decrease, original = £50.

Formulas To Know

1. Percentage Increase

Formula: New Value = Original Value × (1 + Percentage Increase as a Decimal) Variables: - Original Value = Starting amount. - Percentage Increase = % added (e.g., 15% = 0.15). - New Value = Result after increase.

MEMORISE THIS – Not given on exam sheets.


2. Percentage Decrease

Formula: New Value = Original Value × (1 – Percentage Decrease as a Decimal) Variables: - Original Value = Starting amount. - Percentage Decrease = % removed (e.g., 10% = 0.10). - New Value = Result after decrease.

MEMORISE THIS – Not given on exam sheets.


3. Finding the Percentage Change

Formula: Percentage Change = [(New Value – Original Value) / Original Value] × 100 Variables: - Original Value = Starting amount. - New Value = Amount after change. - Percentage Change = % increase or decrease.

GIVEN ON EXAM SHEET (but memorise for speed).


4. Reverse Percentage (Finding Original Value)

Formula: Original Value = New Value / (1 ± Percentage Change as a Decimal) - Use + if it was an increase. - Use if it was a decrease.

MEMORISE THIS – Not given on exam sheets.


Step-by-Step Method

For Percentage Increase/Decrease Problems:

  1. Identify if it’s an increase or decrease.
  2. Convert the percentage to a decimal (e.g., 25% → 0.25).
  3. Adjust the decimal:
  4. Increase: Add to 1 (e.g., 1 + 0.25 = 1.25).
  5. Decrease: Subtract from 1 (e.g., 1 – 0.25 = 0.75).
  6. Multiply the original value by the adjusted decimal to get the new value.
  7. Check your answer makes sense (e.g., a decrease should be smaller).

For Reverse Percentage Problems:

  1. Identify if the change was an increase or decrease.
  2. Convert the percentage to a decimal.
  3. Adjust the decimal:
  4. Increase: 1 + decimal (e.g., 1.20 for 20% increase).
  5. Decrease: 1 – decimal (e.g., 0.80 for 20% decrease).
  6. Divide the new value by the adjusted decimal to find the original.
  7. Verify by recalculating the change.

Worked Examples

Example 1 – Basic (Percentage Increase)

Question: A laptop costs £600. Its price increases by 15%. What is the new price?

Solution: 1. Increase → Use 1 + 0.15 = 1.15. 2. Multiply: £600 × 1.15 = £690.

Answer: £690.

What we did and why: - We converted 15% to 0.15 and added it to 1 to get the multiplier (1.15). - Multiplying by 1.15 gives the new value after a 15% increase.


Example 2 – Medium (Percentage Decrease)

Question: A jacket is reduced by 30% in a sale. It now costs £56. What was the original price?

Solution: 1. Decrease → Use 1 – 0.30 = 0.70. 2. Reverse percentage: Original = £56 ÷ 0.70 = £80.

Answer: £80.

What we did and why: - We converted 30% to 0.30 and subtracted from 1 to get the multiplier (0.70). - Since £56 is after the decrease, we divided by 0.70 to find the original price.


Example 3 – Exam-Style (Disguised Problem)

Question: A phone’s value decreases by 20% in the first year and then by 10% in the second year. If it’s worth £360 after 2 years, what was its original price?

Solution: 1. First decrease (20%): Multiplier = 1 – 0.20 = 0.80. 2. Second decrease (10%): Multiplier = 1 – 0.10 = 0.90. 3. Combined multiplier: 0.80 × 0.90 = 0.72. 4. Reverse percentage: Original = £360 ÷ 0.72 = £500.

Answer: £500.

What we did and why: - We multiplied the multipliers (0.80 × 0.90) to find the total change over 2 years. - Then, we divided the final value by the combined multiplier to find the original price.


Common Mistakes

Mistake Why it Happens Correct Approach
Adding/subtracting % directly Confusing % with raw numbers. Convert % to a decimal first (e.g., 20% → 0.20).
Using the wrong multiplier Forgetting to add/subtract from 1. Increase: 1 + decimal. Decrease: 1 – decimal.
Dividing instead of multiplying Mixing up increase/decrease steps. Increase: Multiply. Decrease: Multiply. Reverse: Divide.
Ignoring order in multi-step % Applying % changes in the wrong sequence. Always multiply multipliers in order (e.g., 20% then 10% = 0.80 × 0.90).
Misreading "increase by" vs. "to" Confusing "increased by 20%" with "increased to 120%". "Increased by 20%" = ×1.20. "Increased to 120%" = ×1.20 (same here, but watch wording!).

Exam Traps

Trap How to Spot it How to Avoid it
"Successive % changes" Question mentions two or more % changes. Multiply the multipliers (e.g., 10% then 20% = 1.10 × 1.20).
"Reverse % with a twist" Gives new value and asks for original, but adds extra steps. Work backwards step-by-step (e.g., if price increased then decreased, reverse the last change first).
"Non-standard wording" Uses phrases like "reduced to 80%" instead of "reduced by 20%". "Reduced to 80%" = 80% of original = ×0.80. "Reduced by 20%" = ×0.80 (same here, but be careful!).

1-Minute Recap

"Here’s the fastest way to solve percentage increase/decrease problems: 1. For increases: Multiply by (1 + decimal) (e.g., 15% = 1.15). 2. For decreases: Multiply by (1 – decimal) (e.g., 10% = 0.90). 3. For reverse %: Divide by the multiplier (e.g., new price ÷ 0.80 for a 20% decrease). 4. For multi-step %: Multiply the multipliers (e.g., 20% then 10% = 0.80 × 0.90). 5. Always check: Does the answer make sense? A decrease should be smaller, an increase larger.

Now go crush those exam questions!