By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
GCSE / A-Level Maths
"Mastering these trig identities doesn’t just get you marks—it unlocks the hardest A-Level questions, like proving identities worth 6+ marks or solving equations where others get stuck. On the Edexcel A-Level, this topic alone can add 10-15% to your final grade. Let’s break it down so you never lose a mark again."
Problem: Prove that cosec²θ – cot²θ = 1.
Step 1: Identify – This is a proof, so we’ll rewrite everything in terms of sin/cos. Step 2: No radians needed here. Step 3: Rewrite cosec and cot: - cosec²θ = 1/sin²θ - cot²θ = cos²θ/sin²θ Step 4: Substitute: - 1/sin²θ – cos²θ/sin²θ = (1 – cos²θ)/sin²θ Step 5: Simplify numerator using Pythagorean identity: - 1 – cos²θ = sin²θ - So, (sin²θ)/sin²θ = 1 Step 6: No exact values needed. Step 7: Both sides equal 1, so the identity is proven. Step 8: Verify with θ = 30°: - cosec²(30°) = 4, cot²(30°) = 3 → 4 – 3 = 1 ✔️
What we did and why: We rewrote everything in terms of sin/cos to use the Pythagorean identity. This is the standard approach for proving trig identities—simplify one side to match the other.
Step 1: Rewrite secθ as 1/cosθ. - 1/cosθ = 2 → cosθ = 1/2 Step 2: Solve cosθ = 1/2 in the given range. - θ = π/3, 5π/3 (60°, 300°) What we did and why: We used the reciprocal identity to convert secθ to cosθ, then solved the basic equation.
Step 1: Use the compound angle formula for sin(A ± B). - sin(θ + π/6) = sinθ cos(π/6) + cosθ sin(π/6) - sin(θ – π/6) = sinθ cos(π/6) – cosθ sin(π/6) Step 2: Add them: - sinθ cos(π/6) + cosθ sin(π/6) + sinθ cos(π/6) – cosθ sin(π/6) = 2 sinθ cos(π/6) Step 3: Substitute exact values: - cos(π/6) = √3/2 → 2 sinθ (√3/2) = √3 sinθ What we did and why: We expanded using compound angles, then simplified by combining like terms. This is a common exam question—always expand first!
Step 1: Rewrite in R-form. - R = √(3² + 4²) = 5 - tanα = 4/3 → α = 0.927 radians (53.1°) - So, 3sinθ + 4cosθ = 5sin(θ + 0.927) Step 2: Set equal to 2: - 5sin(θ + 0.927) = 2 → sin(θ + 0.927) = 0.4 Step 3: Solve sin(x) = 0.4 (where x = θ + 0.927). - x = 0.412, π – 0.412 = 2.730 Step 4: Subtract α to find θ: - θ + 0.927 = 0.412 → θ = -0.515 (not in range) - θ + 0.927 = 2.730 → θ = 1.803 - Also, add 2π to the first solution: θ + 0.927 = 0.412 + 2π → θ = 5.769 Step 5: Check range: θ = 1.803, 5.769 (radians) What we did and why: We used R-form to convert the equation into a single sine function, making it easier to solve. This is a must-know technique for A-Level exams.
"Right, listen up—this is your last-minute checklist for trig identities. First, memorise the key formulas: reciprocal identities (sec = 1/cos, etc.), compound angles (sin(A±B)), and double angles (sin2θ = 2sinθcosθ). For R-form, always find R first (√(a² + b²)), then the phase shift (tanα = b/a). If the question says ‘θ is small,’ switch to radians immediately and use sinθ ≈ θ. When proving identities, start with the messier side and simplify. For equations, always check the range—don’t lose marks by missing solutions. And if you see sec, cosec, or cot, rewrite them in terms of sin/cos straight away. You’ve got this—go smash that exam!
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