By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Introduction Mastering angle problems unlocks 10-15% of your GCSE/A-Level Maths exam marks—think geometry proofs, multi-step circle questions, and real-world engineering designs where precision matters.
Question: In the diagram, AB is parallel to CD, and EF is a transversal. Angle BEF = 50°. Find angle DFE.
Step 1: Label the given angle (50°). Identify parallel lines (AB ∥ CD) and transversal (EF).
Step 2: BEF and DFE are alternate angles (they’re on opposite sides of the transversal and inside the parallel lines).
Step 3: Alternate angles are equal, so DFE = BEF = 50°.
Step 4: No hidden angles here—we’re done!
Step 5: Check: If AB ∥ CD, alternate angles must be equal. ✔️
Question: Lines l and m are parallel. Find angle x.
![Diagram: Two parallel lines cut by a transversal, with a 70° angle marked.]
Step 1: Label the 70° angle. l ∥ m.
Step 2: The angle marked x and 70° are co-interior angles (same side of the transversal, inside the parallel lines).
Step 3: Co-interior angles sum to 180°, so: x + 70 = 180 x = 110°
What we did and why: We used the co-interior angles rule because the lines are parallel. Always check the position of the angles relative to the transversal.
Question: A regular pentagon has an interior angle of x. Find x.
Step 1: A pentagon has n = 5 sides.
Step 2: Sum of interior angles = (n – 2) × 180° = (5 – 2) × 180° = 540°.
Step 3: For a regular pentagon, all interior angles are equal, so: x = 540° ÷ 5 = 108°
What we did and why: We used the polygon angle sum formula, then divided by the number of sides because the pentagon is regular (all angles equal).
Question: In the circle, O is the centre. Angle AOB = 80°. Find angle ACB.
![Diagram: Circle with centre O, points A, B, C on circumference, angle AOB = 80°.]
Step 1: Label angle AOB = 80°. O is the centre.
Step 2: AOB is the angle at the centre, and ACB is the angle at the circumference. Both subtend the same arc AB.
Step 3: Angle at centre = 2 × angle at circumference, so: 80° = 2 × ACB ACB = 40°
What we did and why: We applied the circle theorem that the angle at the centre is twice the angle at the circumference when both angles subtend the same arc.
"Right, listen up—this is your 60-second angle survival guide. First, parallel lines: corresponding angles are equal (think ‘F’), alternate angles are equal (think ‘Z’), co-interior sum to 180° (think ‘C’). Next, polygons: sum of interior angles is (n – 2) × 180°, exterior angles sum to 360°. For circles, remember: angle at centre = 2 × angle at circumference, opposite angles in a cyclic quadrilateral sum to 180°, and the tangent-chord angle equals the angle in the alternate segment. If you’re stuck, label everything, redraw the diagram, and ask: ‘What rule fits here?’ Don’t guess—prove it. Now go smash those angle questions!
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