By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Complete Guide For GCSE/A-Level Physics, Chemistry, Biology
"Mastering percentage increase and decrease lets you calculate drug dosages in medicine, energy efficiency in physics, and reaction yields in chemistry—worth up to 6 marks in a single GCSE exam question!"
Variables:
Calculating New Value After Increase/Decrease [ \text{New Value} = \text{Original Value} \times \left(1 + \frac{\text{Percentage Change}}{100}\right) ]
Example: A 20% increase on 50 → (50 \times (1 + 0.20) = 60).
Reverse Percentage (Finding Original Value) [ \text{Original Value} = \frac{\text{New Value}}{1 + \frac{\text{Percentage Change}}{100}} ]
Question: A plant grows from 30 cm to 36 cm. What is the percentage increase?
Step 1: Identify what’s given. - Original Value = 30 cm - New Value = 36 cm
Step 2: Use the Percentage Change formula. [ \text{Percentage Increase} = \left( \frac{36 - 30}{30} \right) \times 100 ]
Step 3: Calculate. [ = \left( \frac{6}{30} \right) \times 100 = 0.2 \times 100 = 20\% ]
What we did and why: - We used the Percentage Change formula because we had both the original and new values. - The answer is 20%, meaning the plant grew by 20% of its original height.
Question: After a 15% increase, a chemical’s mass is 230 g. What was its original mass?
Step 1: Identify what’s given. - New Value = 230 g - Percentage Increase = 15%
Step 2: Use the Reverse Percentage formula. [ \text{Original Value} = \frac{230}{1 + \frac{15}{100}} = \frac{230}{1.15} ]
Step 3: Calculate. [ = 200 \text{ g} ]
What we did and why: - We used reverse percentage because we knew the new value and the percentage change. - The original mass was 200 g before the 15% increase.
Question: A battery’s voltage drops from 9V to 7.2V. What is the percentage decrease? (3 marks)
Step 1: Identify what’s given. - Original Value = 9V - New Value = 7.2V
Step 2: Use the Percentage Change formula. [ \text{Percentage Decrease} = \left( \frac{9 - 7.2}{9} \right) \times 100 ]
Step 3: Calculate. [ = \left( \frac{1.8}{9} \right) \times 100 = 0.2 \times 100 = 20\% ]
What we did and why: - The question disguised the percentage decrease by not explicitly asking for it. - We recognised it was a percentage change problem and applied the formula. - The answer is 20% decrease.
"Right, listen up—this is your last-minute cheat sheet for percentage increase and decrease. First, memorise the two key formulas: 1. Percentage Change = (New - Original) / Original × 100 2. New Value = Original × (1 ± % change as a decimal)
If you’re given the new value and need the original, use reverse percentage—divide by (1 + % increase) or (1 - % decrease).
Common mistakes? Dividing by the wrong number, forgetting to convert % to decimal, or mixing up increase and decrease. Always check: Does your answer make sense? A 50% increase on 100 should be 150, not 50!
Exam traps? Watch for two-step changes (e.g., first increase, then decrease) and reverse percentage questions. Don’t assume they cancel out—calculate each step!
Now go smash those questions!"
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