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Study Guide: GCSE Maths Number - How to Solve: Percentage Increase and Decrease
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GCSE Maths Number - How to Solve: Percentage Increase and Decrease

By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.

⏱️ ~5 min read

How to Solve: Percentage Increase and Decrease

Complete Guide For GCSE/A-Level Physics, Chemistry, Biology


Introduction

"Mastering percentage increase and decrease lets you calculate drug dosages in medicine, energy efficiency in physics, and reaction yields in chemistry—worth up to 6 marks in a single GCSE exam question!"


WHAT YOU NEED TO KNOW FIRST

  1. Basic percentages – How to find 10% of a number (divide by 10).
  2. Decimal multiplication – Converting percentages to decimals (e.g., 25% = 0.25).
  3. Rearranging equations – Solving for an unknown in simple formulas.

KEY TERMS & FORMULAS

Key Terms

  • Original value – The starting number before any change.
  • New value – The number after the increase or decrease.
  • Percentage change – The amount of change expressed as a percentage of the original.

Formulas

  1. Percentage Increase/Decrease Formula
    [
    \text{Percentage Change} = \left( \frac{\text{New Value} - \text{Original Value}}{\text{Original Value}} \right) \times 100
    ]
  2. MEMORISE THIS – Used in almost every question.
  3. Variables:

    • New Value = Final amount after change.
    • Original Value = Starting amount.
  4. Calculating New Value After Increase/Decrease
    [
    \text{New Value} = \text{Original Value} \times \left(1 + \frac{\text{Percentage Change}}{100}\right)
    ]

  5. MEMORISE THIS – Use when given the original value and percentage change.
  6. Example: A 20% increase on 50 → (50 \times (1 + 0.20) = 60).

  7. Reverse Percentage (Finding Original Value)
    [
    \text{Original Value} = \frac{\text{New Value}}{1 + \frac{\text{Percentage Change}}{100}}
    ]

  8. Given on exam sheet (but practice using it!).
  9. Example: After a 25% increase, the new value is 125 → Original = ( \frac{125}{1.25} = 100 ).

STEP-BY-STEP METHOD

Step 1: Identify What You’re Given

  • Are you given the original value and percentage change? → Use New Value formula.
  • Are you given the new value and percentage change? → Use Reverse Percentage formula.
  • Are you given both values and asked for the percentage change? → Use Percentage Change formula.

Step 2: Convert Percentage to Decimal (If Needed)

  • Divide the percentage by 100.
  • Example: 15% → 0.15.

Step 3: Plug Values into the Correct Formula

  • Follow the formula exactly. No shortcuts!

Step 4: Calculate and Check Units

  • If the question asks for a percentage, add the % sign.
  • If it asks for a value, include units (e.g., grams, joules).

Step 5: Verify Your Answer

  • Does it make sense?
  • A 50% increase on 100 should give 150, not 50.
  • A 20% decrease on 80 should give 64, not 100.

WORKED EXAMPLES

Example 1 – Basic (Percentage Increase)

Question: A plant grows from 30 cm to 36 cm. What is the percentage increase?

Step 1: Identify what’s given. - Original Value = 30 cm - New Value = 36 cm

Step 2: Use the Percentage Change formula. [ \text{Percentage Increase} = \left( \frac{36 - 30}{30} \right) \times 100 ]

Step 3: Calculate. [ = \left( \frac{6}{30} \right) \times 100 = 0.2 \times 100 = 20\% ]

What we did and why: - We used the Percentage Change formula because we had both the original and new values. - The answer is 20%, meaning the plant grew by 20% of its original height.


Example 2 – Medium (Reverse Percentage)

Question: After a 15% increase, a chemical’s mass is 230 g. What was its original mass?

Step 1: Identify what’s given. - New Value = 230 g - Percentage Increase = 15%

Step 2: Use the Reverse Percentage formula. [ \text{Original Value} = \frac{230}{1 + \frac{15}{100}} = \frac{230}{1.15} ]

Step 3: Calculate. [ = 200 \text{ g} ]

What we did and why: - We used reverse percentage because we knew the new value and the percentage change. - The original mass was 200 g before the 15% increase.


Example 3 – Exam-Style (Disguised Question)

Question: A battery’s voltage drops from 9V to 7.2V. What is the percentage decrease? (3 marks)

Step 1: Identify what’s given. - Original Value = 9V - New Value = 7.2V

Step 2: Use the Percentage Change formula. [ \text{Percentage Decrease} = \left( \frac{9 - 7.2}{9} \right) \times 100 ]

Step 3: Calculate. [ = \left( \frac{1.8}{9} \right) \times 100 = 0.2 \times 100 = 20\% ]

What we did and why: - The question disguised the percentage decrease by not explicitly asking for it. - We recognised it was a percentage change problem and applied the formula. - The answer is 20% decrease.


COMMON MISTAKES

MISTAKE WHY IT HAPPENS CORRECT APPROACH
Dividing by the new value instead of the original Confusing which number is the "base" Always divide by the original value in the Percentage Change formula.
Forgetting to convert % to decimal Skipping Step 2 in the method Always divide the percentage by 100 before multiplying.
Mixing up increase and decrease Not reading the question carefully If the new value is smaller, it’s a decrease. If larger, it’s an increase.
Incorrectly rearranging reverse percentage Misapplying the formula Use Original = New / (1 + % change) for increases, Original = New / (1 - % change) for decreases.
Rounding too early Losing precision in calculations Keep at least 3 decimal places until the final answer.

EXAM TRAPS

TRAP HOW TO SPOT IT HOW TO AVOID IT
"After a 20% increase, the new value is…" The question gives the original value and percentage change Use New Value = Original × (1 + % change).
"What was the original price before a 15% discount?" The question gives the new value and percentage decrease Use Reverse Percentage formula.
"The mass decreased by 10%, then increased by 10%. What’s the final mass?" Two percentage changes in sequence Never assume they cancel out! Calculate step-by-step.

1-MINUTE RECAP

"Right, listen up—this is your last-minute cheat sheet for percentage increase and decrease. First, memorise the two key formulas: 1. Percentage Change = (New - Original) / Original × 100 2. New Value = Original × (1 ± % change as a decimal)

If you’re given the new value and need the original, use reverse percentage—divide by (1 + % increase) or (1 - % decrease).

Common mistakes? Dividing by the wrong number, forgetting to convert % to decimal, or mixing up increase and decrease. Always check: Does your answer make sense? A 50% increase on 100 should be 150, not 50!

Exam traps? Watch for two-step changes (e.g., first increase, then decrease) and reverse percentage questions. Don’t assume they cancel out—calculate each step!

Now go smash those questions!"