By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
GCSE/A-Level (Physics, Chemistry, Biology) – Complete Guide
"Mastering mean, median, mode, and range doesn’t just get you marks—it unlocks real-world data analysis in medicine, sports science, and environmental studies. In your GCSE/A-Level exams, this topic appears in at least 2-3 questions per paper, often worth 4-6 marks total. Miss it, and you’re leaving easy marks on the table."
Before diving in, ensure you understand: 1. Ordering numbers – How to arrange data from smallest to largest. 2. Basic arithmetic – Addition, division, and subtraction. 3. Frequency tables – How to read and interpret data in tables.
MEMORISE THIS – Not always given in exams.
Median
MEMORISE THIS – Examiners expect you to know this.
Mode
No formula – Just count frequencies.
Range [ \text{Range} = \text{Maximum value} - \text{Minimum value} ]
Data: 5, 2, 8, 2, 6, 1, 4
1, 2, 2, 4, 5, 6, 8
Sum = 1 + 2 + 2 + 4 + 5 + 6 + 8 = 28 Number of values = 7 Mean = 28 ÷ 7 = 4
7 numbers → odd → 4th number = 4
"2" appears twice (most frequent) → 2
Largest = 8, Smallest = 1 Range = 8 – 1 = 7
Answer: Mean = 4, Median = 4, Mode = 2, Range = 7
What we did and why: - Ordered data first to make median and mode easier. - Mean required adding all numbers before dividing. - Mode was found by counting frequencies.
Data:
3, 3, 5, 5, 5, 5, 7, 7, 7
Sum = (3×2) + (5×4) + (7×3) = 6 + 20 + 21 = 47 Number of values = 2 + 4 + 3 = 9 Mean = 47 ÷ 9 ≈ 5.22
9 numbers → odd → 5th number = 5
"5" appears 4 times (most frequent) → 5
Largest = 7, Smallest = 3 Range = 7 – 3 = 4
Answer: Mean ≈ 5.22, Median = 5, Mode = 5, Range = 4
What we did and why: - Used frequency to expand the list. - Mean required multiplying each number by its frequency. - Mode was clear because one number had the highest frequency.
Question: A biologist records the number of eggs in 10 bird nests: 3, 5, 2, 6, 3, 4, 5, 2, 6, 4 Calculate the mean, median, mode, and range.
2, 2, 3, 3, 4, 4, 5, 5, 6, 6
Sum = 2+2+3+3+4+4+5+5+6+6 = 40 Number of values = 10 Mean = 40 ÷ 10 = 4
10 numbers → even → Mean of 5th and 6th numbers = (4 + 4) ÷ 2 = 4
"2, 3, 4, 5, 6" all appear twice → No unique mode (or list all: 2, 3, 4, 5, 6)
Largest = 6, Smallest = 2 Range = 6 – 2 = 4
Answer: Mean = 4, Median = 4, Mode = No unique mode (or 2, 3, 4, 5, 6), Range = 4
What we did and why: - Ordered data to find median easily. - Mean required careful addition. - Mode had multiple answers—examiners expect you to recognise this.
"Night before the exam? Here’s what you need to remember: 1. Mean = Sum ÷ Number of values. Add them all, then divide. 2. Median = Middle number. Order first, then find the middle. 3. Mode = Most frequent. Count how many times each number appears. 4. Range = Biggest – Smallest. Simple subtraction. Common traps? Forgetting to order data, miscounting for mean, and not checking for multiple modes. Double-check your work—examiners love to test these! You’ve got this!"
Join 4M+ learners. Unlock unlimited quizzes, wrong-answer tracking, flashcards + reminders, study guides, and 1-on-1 challenges.