By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
"Master chemical bonding, and you’ll predict whether a substance is a gas, liquid, or solid—just by looking at its formula. That’s 5+ marks in your exam, guaranteed."
Before diving into bonding, ensure you understand: 1. Atomic structure – Protons, neutrons, electrons, and electron shells. 2. Electron configuration – How electrons fill shells (2, 8, 8 rule for the first 20 elements). 3. Valency – The number of electrons an atom gains, loses, or shares to achieve stability.
If any of these are unclear, pause and review them first.
Step 1: Identify the atoms involved. - Write the symbols (e.g., Na and Cl).
Step 2: Find their group numbers (from the periodic table). - Group 1 = +1 charge (loses 1 electron). - Group 2 = +2 charge. - Group 16 = -2 charge (gains 2 electrons). - Group 17 = -1 charge.
Step 3: Predict if the bond is ionic or covalent. - Metal + Nonmetal → Ionic (e.g., NaCl). - Nonmetal + Nonmetal → Covalent (e.g., CO₂). - Metal + Metal → Metallic (e.g., Cu-Zn alloy).
Step 4: For ionic bonds, show electron transfer. - Draw arrows from the metal to the nonmetal. - Write the charges (e.g., Na⁺ Cl⁻).
Step 5: For covalent bonds, draw Lewis structures. - Count total valence electrons. - Arrange atoms (central atom is usually the one with the highest valency). - Place electrons in pairs (bonds first, then lone pairs). - Check the octet rule (except H, which needs 2).
Step 6: Label bond polarity (if covalent). - Use δ⁺ and δ⁻ for polar bonds (e.g., Hδ⁺–Clδ⁻). - If ΔEN = 0, it’s nonpolar (e.g., O₂).
Step 7: Predict physical properties. - Ionic → High melting point, soluble in water, conducts electricity when molten/dissolved. - Covalent → Low melting point, insoluble in water (unless polar), doesn’t conduct. - Metallic → High melting point, conducts electricity as a solid, malleable.
Question: Predict the bond type in MgO and draw its structure.
Step 1: Atoms involved → Mg (magnesium) and O (oxygen). Step 2: Group numbers → Mg (Group 2, +2 charge), O (Group 16, -2 charge). Step 3: Metal + Nonmetal → Ionic bond. Step 4: Electron transfer → Mg loses 2 electrons, O gains 2. Step 5: Structure → Mg²⁺ O²⁻ (no sharing, just attraction). Step 6: Polarity → Not applicable (ionic). Step 7: Properties → High melting point, conducts electricity when molten.
What we did and why: - We used group numbers to predict charges. - Recognized MgO as ionic because it’s a metal + nonmetal. - Drew the structure by showing electron transfer, not sharing.
Question: Draw the Lewis structure for CO₂ and predict its bond type.
Step 1: Atoms → C (carbon) and O (oxygen). Step 2: Valence electrons → C (4), O (6 each). Total = 4 + 6 + 6 = 16 electrons. Step 3: Nonmetal + Nonmetal → Covalent. Step 4: Central atom → Carbon (higher valency). Step 5: Arrange bonds → C=O=C (double bonds to satisfy octet). Step 6: Check octet → C has 8, each O has 8. Step 7: Polarity → ΔEN (C-O) = 3.5 - 2.5 = 1.0 → Polar covalent. Step 8: Properties → Gas at room temp, low melting point, doesn’t conduct.
What we did and why: - Counted valence electrons first to know how many bonds to draw. - Used double bonds to satisfy the octet rule for all atoms. - Calculated ΔEN to confirm bond polarity.
Question: Draw NH₃ and explain why it’s polar.
Step 1: Atoms → N (nitrogen) and H (hydrogen). Step 2: Valence electrons → N (5), H (1 each). Total = 5 + 3(1) = 8 electrons. Step 3: Nonmetal + Nonmetal → Covalent. Step 4: Central atom → Nitrogen. Step 5: Arrange bonds → 3 N-H single bonds. Step 6: Add lone pairs → N has 1 lone pair (2 electrons). Step 7: Check octet → N has 8, H has 2 each. Step 8: Polarity → ΔEN (N-H) = 3.0 - 2.1 = 0.9 → Polar covalent. - Shape is trigonal pyramidal (lone pair repels bonds). - Asymmetric shape → Polar molecule. Step 9: Properties → Liquid at room temp, soluble in water, doesn’t conduct.
What we did and why: - Left a lone pair on nitrogen to satisfy the octet. - Recognized that lone pairs affect shape and polarity. - Calculated ΔEN and shape to confirm polarity.
Question: A student claims K₂S has covalent bonds. Is this correct? Justify your answer and predict its properties.
Step 1: Atoms → K (potassium) and S (sulfur). Step 2: Group numbers → K (Group 1, +1), S (Group 16, -2). Step 3: Metal + Nonmetal → Ionic bond (not covalent). Step 4: Electron transfer → 2 K atoms lose 1 electron each → 2 K⁺. - S gains 2 electrons → S²⁻. Step 5: Formula → K₂S (charges balance: +2 and -2). Step 6: Properties → High melting point, soluble in water, conducts electricity when dissolved.
What we did and why: - Corrected the student’s mistake by identifying K₂S as ionic. - Used group numbers to predict charges and balance the formula. - Linked bond type to physical properties for full marks.
"Okay, let’s lock this in—here’s what you need to remember for your exam:
Metallic = metal + metal (sea of electrons, e.g., copper).
For ionic bonds:
Swap and drop charges to write the formula (e.g., Al³⁺ + O²⁻ → Al₂O₃).
For covalent bonds:
Check the octet rule (except H, which needs 2).
Polarity:
If ΔEN > 0.5, it’s polar (unless the shape cancels it out).
Properties:
Now go practice—draw NaCl, CO₂, and NH₃ from memory. If you can do those, you’ve got this!
Final Checklist for Students: ✅ Can I predict bond type from the periodic table? ✅ Can I draw Lewis structures for ionic and covalent bonds? ✅ Can I calculate ΔEN and predict polarity? ✅ Can I link bond type to physical properties?
If yes, you’re ready for the exam. ?
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