By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Complete Guide for Students & Teachers
"Double angle identities let you simplify complex trig problems in seconds—like turning a 2θ equation into a θ equation, or solving integrals in calculus. Miss this, and you’ll waste minutes on every exam question. Master it, and you’ll solve faster than the mark scheme."
If you’re shaky on these, pause and review them first.
Formula: sin 2θ = 2 sin θ cos θ - Variables: - θ = any angle (in degrees or radians). - MEMORISE THIS (not always given on exam sheets).
Formulas: 1. cos 2θ = cos²θ – sin²θ 2. cos 2θ = 2 cos²θ – 1 3. cos 2θ = 1 – 2 sin²θ - Variables: - θ = any angle. - MEMORISE ALL THREE (exam sheets may give only one).
Formula: tan 2θ = (2 tan θ) / (1 – tan²θ) - Variables: - θ = any angle where tan θ is defined (θ ≠ 90° + 180°n). - MEMORISE THIS (rarely given).
Problem: Solve sin 2θ = √3/2 for 0° ≤ θ ≤ 360°.
Step 1: Identify the double angle. - Here, it’s sin 2θ.
Step 2: Choose the identity. - Use sin 2θ = 2 sin θ cos θ.
Step 3: Substitute and simplify. - 2 sin θ cos θ = √3/2 - Divide both sides by 2: sin θ cos θ = √3/4
But this is tricky to solve directly. Instead, use the original identity: - sin 2θ = √3/2 - Let 2θ = x, so sin x = √3/2.
Step 4: Solve for x. - sin x = √3/2 → x = 60° + 360°n or x = 120° + 360°n (n = integer). - But x = 2θ, so: 2θ = 60° + 360°n → θ = 30° + 180°n 2θ = 120° + 360°n → θ = 60° + 180°n
Step 5: Find θ in the range 0° ≤ θ ≤ 360°. - For n = 0: θ = 30°, 60° - For n = 1: θ = 30° + 180° = 210° θ = 60° + 180° = 240° - For n = 2: θ = 390° (out of range), 420° (out of range).
Final Solutions: θ = 30°, 60°, 210°, 240°.
What we did and why: - We rewrote sin 2θ as sin x to simplify solving. - We used the general solution for sin x = √3/2, then substituted back. - We checked all possible solutions within the given range.
Problem: Simplify cos 2θ + sin²θ.
Step 1: Identify the double angle. - cos 2θ is the double angle.
Step 2: Choose the identity. - We have sin²θ, so use cos 2θ = 1 – 2 sin²θ.
Step 3: Substitute and simplify. - cos 2θ + sin²θ = (1 – 2 sin²θ) + sin²θ - = 1 – 2 sin²θ + sin²θ - = 1 – sin²θ
Step 4: Recognize the Pythagorean identity. - 1 – sin²θ = cos²θ.
Final Answer: cos²θ.
What we did and why: - We picked the cos 2θ identity that matched the sin²θ term. - We simplified using algebra and recognized a basic identity.
Problem: Solve 2 cos 2θ = 1 for 0 ≤ θ ≤ 2π.
Step 1: Isolate the double angle. - 2 cos 2θ = 1 → cos 2θ = 1/2.
Step 2: Choose the identity. - We can use any cos 2θ identity, but let’s use cos 2θ = 2 cos²θ – 1 (since it’s in terms of cos θ).
Step 3: Substitute and solve. - 2 cos²θ – 1 = 1/2 - 2 cos²θ = 3/2 - cos²θ = 3/4 - cos θ = ±√(3/4) = ±√3/2
Step 4: Find θ in the range. - cos θ = √3/2 → θ = π/6, 11π/6 - cos θ = –√3/2 → θ = 5π/6, 7π/6
Step 5: Verify all solutions. - All values are within 0 ≤ θ ≤ 2π.
Final Solutions: θ = π/6, 5π/6, 7π/6, 11π/6.
What we did and why: - We isolated cos 2θ first to make substitution easier. - We chose the cos 2θ identity that led to a solvable equation. - We considered both positive and negative roots for cos θ.
Problem: Prove (1 – cos 2θ) / sin 2θ = tan θ.
Step 1: Identify the double angles. - cos 2θ and sin 2θ are present.
Step 2: Choose identities. - For 1 – cos 2θ, use cos 2θ = 1 – 2 sin²θ → 1 – cos 2θ = 2 sin²θ. - For sin 2θ, use sin 2θ = 2 sin θ cos θ.
Step 3: Substitute and simplify. - (1 – cos 2θ) / sin 2θ = (2 sin²θ) / (2 sin θ cos θ) - = (sin²θ) / (sin θ cos θ) - = sin θ / cos θ - = tan θ.
Step 4: Verify the identity. - Left side simplifies to tan θ, which equals the right side.
Final Answer: The identity is proven.
What we did and why: - We picked identities that would cancel terms (2 sin²θ and 2 sin θ cos θ). - We simplified step-by-step to match the right side. - We ensured every step was reversible (no division by zero).
"Alright, listen up—this is your 60-second crash course for double angle identities. Memorise these three formulas: 1. sin 2θ = 2 sin θ cos θ 2. cos 2θ has three versions—pick the one that matches your problem (cos²θ? 2 cos²θ – 1. sin²θ? 1 – 2 sin²θ). 3. tan 2θ = (2 tan θ) / (1 – tan²θ).
When you see a problem: 1. Spot the double angle (2θ, 4x, etc.). 2. Substitute the identity. 3. Simplify and solve. 4. Check your solutions—no extraneous answers!
Common traps? Watch for disguised angles (like 4θ), and always match the identity to the terms you have. If you’re stuck, convert everything to sin and cos. You’ve got this—go ace that exam!
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