By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
(For Students Who Want to Ace Their Exam & Teachers Who Need a Ready-to-Record Script)
"If you can’t expand brackets correctly, you’ll lose marks on every algebra question—from simplifying expressions to solving equations. Let’s fix that in 5 minutes."
Before expanding brackets, you must already understand: 1. Order of operations (BIDMAS/BODMAS) – Multiplication before addition/subtraction. 2. Multiplying terms – How to multiply numbers, variables (e.g., x × x = x²), and coefficients (e.g., 3 × 4x = 12x). 3. Like terms – Terms with the same variable part (e.g., 2x and 5x are like terms; 2x and 3y are not).
If any of these are unclear, review them first.
Formula: a(b + c) = ab + ac - a = term outside the bracket (can be a number, variable, or both). - b, c = terms inside the bracket.
MEMORISE THIS – It’s the foundation of all bracket expansion.
Formula: (a + b)(c + d) = ac + ad + bc + bd - a, b = terms in the first bracket. - c, d = terms in the second bracket.
MEMORISE THIS – Examiners test this frequently.
Formula: (a + b)² = a² + 2ab + b² (a – b)² = a² – 2ab + b²
MEMORISE THIS – Saves time in exams.
Formula: (a + b)(a – b) = a² – b²
MEMORISE THIS – A shortcut for specific cases.
Follow these steps in order for every problem:
Problem: Expand 3(2x – 5) + 4(x + 1)
Step 1: Identify the type of bracket. - Two single brackets: 3(2x – 5) and 4(x + 1).
Step 2: Apply the single bracket formula to each. - 3 × 2x = 6x - 3 × (-5) = -15 - 4 × x = 4x - 4 × 1 = 4
Step 3: Write all new terms. - 6x – 15 + 4x + 4
Step 4: Combine like terms. - 6x + 4x = 10x - -15 + 4 = -11
Step 5: Simplify. - 10x – 11
Final Answer: 10x – 11
Problem: Expand 5(3x – 2)
Working: 1. Multiply 5 by 3x → 15x 2. Multiply 5 by -2 → -10 3. Combine: 15x – 10
What we did and why: - Used the single bracket rule (a(b + c) = ab + ac). - Multiplied the term outside (5) by each term inside (3x and -2). - No like terms to combine, so the answer is already simplified.
Problem: Expand (x + 4)(x – 2)
Working: 1. First terms: x × x = x² 2. Outer terms: x × (-2) = -2x 3. Inner terms: 4 × x = 4x 4. Last terms: 4 × (-2) = -8 5. Combine all: x² – 2x + 4x – 8 6. Combine like terms: x² + 2x – 8
What we did and why: - Used the FOIL method (First, Outer, Inner, Last). - Multiplied every term in the first bracket by every term in the second bracket. - Combined -2x and +4x to get +2x.
Problem: Simplify 2(3x + 1) – (x – 4)
Working: 1. Expand 2(3x + 1) → 6x + 2 2. Expand –(x – 4) → -1 × x = -x and -1 × (-4) = +4 (Note: The minus sign is like a -1 outside the bracket!) 3. Combine all terms: 6x + 2 – x + 4 4. Combine like terms: 6x – x = 5x and 2 + 4 = 6 5. Final answer: 5x + 6
What we did and why: - Treated the minus sign as -1 to avoid sign errors. - Expanded both brackets separately before combining. - Combined like terms carefully to simplify.
"Okay, let’s lock this in. Expanding brackets is just multiplying—nothing more. For single brackets like 3(x + 2), multiply 3 by both x and 2 to get 3x + 6. For double brackets like (x + 1)(x + 3), use FOIL: First, Outer, Inner, Last. Multiply x × x, x × 3, 1 × x, and 1 × 3, then combine like terms. Watch out for minus signs—they’re sneaky! Always rewrite - (x + 2) as -1(x + 2) before expanding. And if you see a squared bracket like (x + 4)², use the shortcut: x² + 8x + 16. Practice 3 problems tonight, and you’ll own this for the exam. You’ve got this!
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