By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
(For Students Who Want to Ace Their Exam & Teachers Who Need a Ready-to-Record Script)
"Imagine your car tire explodes on a scorching summer road—why? Or why does a soda can explode in the freezer? Master gas laws, and you’ll predict these disasters—and crush every exam question on pressure, volume, and temperature!
Before diving into gas laws, ensure you understand: 1. Pressure (P): Force per unit area (e.g., Pascals, atm). Think of a balloon—more air = more pressure. 2. Volume (V): Space a gas occupies (e.g., liters, m³). A smaller container = less volume. 3. Temperature (T): Must be in Kelvin (K) for gas laws. Convert °C to K by adding 273.
(If you’re shaky on these, pause and review first!)
Formula: P₁V₁ = P₂V₂ - P₁ = Initial pressure - V₁ = Initial volume - P₂ = Final pressure - V₂ = Final volume - MEMORISE THIS (but it’s often given).
When to use: Temperature is constant (e.g., a piston compressing gas).
Formula: V₁/T₁ = V₂/T₂ - V₁ = Initial volume - T₁ = Initial temperature (in Kelvin!) - V₂ = Final volume - T₂ = Final temperature (in Kelvin!) - MEMORISE THIS (often given).
When to use: Pressure is constant (e.g., a balloon in hot/cold water).
Formula: P₁/T₁ = P₂/T₂ - P₁ = Initial pressure - T₁ = Initial temperature (Kelvin!) - P₂ = Final pressure - T₂ = Final temperature (Kelvin!) - MEMORISE THIS (often given).
When to use: Volume is constant (e.g., a sealed gas canister in a fire).
Formula: P₁V₁/T₁ = P₂V₂/T₂ - MEMORISE THIS (usually given, but know how to rearrange it). - When to use: When two or all three of P, V, T change.
Formula: PV = nRT - P = Pressure (Pa or atm) - V = Volume (m³ or L) - n = Moles of gas (mol) - R = Universal gas constant (given on exam sheet) - T = Temperature (Kelvin!) - MEMORISE THIS (but R is usually provided).
When to use: When you see moles (n) or need to find mass/molar mass.
(Follow these steps for any gas law problem.)
Question: A gas occupies 3.0 L at 2.0 atm. If pressure increases to 4.0 atm (temperature constant), what’s the new volume?
Step 1: Given: V₁ = 3.0 L, P₁ = 2.0 atm, P₂ = 4.0 atm. Find V₂. Step 2: Only P & V change → Boyle’s Law (P₁V₁ = P₂V₂). Step 3: Units are fine (atm and L). Step 4: (2.0 atm)(3.0 L) = (4.0 atm)(V₂) Step 5: V₂ = (2.0 × 3.0) / 4.0 = 1.5 L Step 6: Units = L (correct). Step 7: Pressure doubled → volume halved (makes sense!).
Answer: 1.5 L
Question: A balloon has a volume of 2.5 L at 25°C. What’s its volume at 50°C (pressure constant)?
Step 1: Given: V₁ = 2.5 L, T₁ = 25°C, T₂ = 50°C. Find V₂. Step 2: Only V & T change → Charles’s Law (V₁/T₁ = V₂/T₂). Step 3: Convert T to Kelvin: - T₁ = 25 + 273 = 298 K - T₂ = 50 + 273 = 323 K Step 4: 2.5 L / 298 K = V₂ / 323 K Step 5: V₂ = (2.5 × 323) / 298 = 2.71 L Step 6: Units = L (correct). Step 7: Temperature increased → volume increased (makes sense!).
Answer: 2.71 L
What we did and why: - Used Charles’s Law because only V and T changed. - Converted °C to K because gas laws only work in Kelvin. - Rearranged to solve for V₂ and checked units.
Question: A gas at 1.5 atm and 300 K occupies 4.0 L. If pressure drops to 1.0 atm and temperature rises to 400 K, what’s the new volume?
Step 1: Given: P₁ = 1.5 atm, T₁ = 300 K, V₁ = 4.0 L, P₂ = 1.0 atm, T₂ = 400 K. Find V₂. Step 2: P, V, and T change → Combined Gas Law (P₁V₁/T₁ = P₂V₂/T₂). Step 3: Units are fine (atm, K, L). Step 4: (1.5 atm × 4.0 L) / 300 K = (1.0 atm × V₂) / 400 K Step 5: V₂ = (1.5 × 4.0 × 400) / (300 × 1.0) = 8.0 L Step 6: Units = L (correct). Step 7: Pressure decreased (→ volume increases) and temperature increased (→ volume increases). Final volume is larger (makes sense!).
Answer: 8.0 L
What we did and why: - Used Combined Gas Law because all three variables changed. - Plugged in values carefully and solved for V₂. - Checked if the answer made sense (both changes should increase volume).
Question: What volume does 0.5 mol of oxygen gas occupy at 2.0 atm and 27°C?
Step 1: Given: n = 0.5 mol, P = 2.0 atm, T = 27°C. Find V. Step 2: Moles (n) involved → Ideal Gas Law (PV = nRT). Step 3: Convert T to Kelvin: 27 + 273 = 300 K. - R = 0.0821 L·atm/mol·K (given on exam sheet). Step 4: (2.0 atm)(V) = (0.5 mol)(0.0821 L·atm/mol·K)(300 K) Step 5: V = (0.5 × 0.0821 × 300) / 2.0 = 6.16 L Step 6: Units = L (correct). Step 7: 0.5 mol is a small amount, so 6.16 L is reasonable.
Answer: 6.16 L
What we did and why: - Used Ideal Gas Law because moles (n) were given. - Converted °C to K and used the correct R value. - Rearranged to solve for V and checked units.
"Alright, let’s lock this in for your exam. Gas laws are all about pressure, volume, and temperature—just pick the right formula!
Remember: Kelvin only! Convert °C to K by adding 273. Check units—don’t mix atm with kPa. And if the question mentions a sealed container, volume is constant!
Now go crush those gas law questions—you’ve got this!
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