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(For Students Who Want to Ace Their Exam & Teachers Who Need a Ready-to-Record Script)
"If you can prove two triangles are congruent, you can unlock missing angles, side lengths, and even real-world problems—like designing stable bridges or checking if two pieces of furniture are identical. Today, you’ll learn the exact steps to prove congruence and crush every exam question."
Before diving into congruent triangles, you must already understand: 1. Triangle basics – Sides, angles, vertices, and how to label them (e.g., ΔABC). 2. Angle properties – Complementary, supplementary, and vertically opposite angles. 3. Basic algebra – Solving for unknowns (e.g., if 2x + 30 = 90, find x).
If any of these feel shaky, pause and review them first.
These are the 5 postulates to prove triangle congruence. MEMORISE THESE—they’re not always given on exams.
⚠️ Important Notes: - SSA does NOT prove congruence (except in special cases like HL). - AAA only proves similarity, not congruence (triangles could be different sizes).
Follow these 6 steps for every congruent triangles problem.
Problem: In the diagram, AB = AD and ∠BAC = ∠DAC. Prove ΔABC ≅ ΔADC.
Solution:
What we did and why: We used SAS because we had two sides and the angle between them. The shared side (AC) was key—always check for reflexive sides!
Problem: Prove ΔPQR ≅ ΔSTU given PQ = ST, QR = TU, and PR = SU.
Solution: 1. Identify triangles: ΔPQR and ΔSTU. 2. Given: PQ = ST, QR = TU, PR = SU. 3. All three sides are equal → SSS. 4. Congruence statement: ΔPQR ≅ ΔSTU. 5. Justification: "By SSS, ΔPQR ≅ ΔSTU because all corresponding sides are equal."
What we did and why: We matched all three sides directly. SSS is the simplest postulate—just check all sides!
Problem: In the diagram, ∠A = ∠D, ∠B = ∠E, and BC = EF. Prove ΔABC ≅ ΔDEF.
Solution: 1. Identify triangles: ΔABC and ΔDEF. 2. Given: ∠A = ∠D, ∠B = ∠E, BC = EF. 3. Missing angle: ∠C = ∠F (sum of angles in a triangle = 180°). 4. We have: Two angles (∠B = ∠E, ∠C = ∠F) and the included side (BC = EF) → ASA. 5. Congruence statement: ΔABC ≅ ΔDEF. 6. Justification: "By ASA, ΔABC ≅ ΔDEF because ∠B = ∠E, BC = EF, and ∠C = ∠F."
What we did and why: We used ASA because we had two angles and the side between them. The third angle was found using the angle sum property.
Problem: In right triangles ΔXYZ and ΔPQR, ∠Y = ∠Q = 90°, XZ = PR, and XY = PQ. Prove ΔXYZ ≅ ΔPQR.
Solution: 1. Identify triangles: ΔXYZ and ΔPQR (both right-angled at Y and Q). 2. Given: ∠Y = ∠Q = 90°, XZ = PR (hypotenuse), XY = PQ (one leg). 3. We have: Hypotenuse and one leg equal → HL. 4. Congruence statement: ΔXYZ ≅ ΔPQR. 5. Justification: "By HL, ΔXYZ ≅ ΔPQR because both are right triangles with equal hypotenuses (XZ = PR) and one equal leg (XY = PQ)."
What we did and why: We used HL because it’s the only postulate that works for right triangles with the hypotenuse and one leg. Never use SSA here!
"Alright, let’s lock this in for your exam. To prove two triangles are congruent, you’ve got five postulates: SSS, SAS, ASA, AAS, and HL (for right triangles only). Here’s your game plan: 1. Label the triangles and write down what’s given. 2. Check for missing info—shared sides, angle sums, or parallel lines. 3. Pick the right postulate—match what you have to SSS, SAS, ASA, AAS, or HL. 4. Write the congruence statement in the correct order. 5. Justify it—say which postulate you used and why.
Watch out for traps: SSA doesn’t work, AAA only proves similarity, and always look for reflexive sides. If it’s a right triangle, think HL first. Now go practice—you’ve got this!
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