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Study Guide: How to Solve: Variables on Both Sides
Source: https://www.fatskills.com/k-12-assessment-tests/chapter/how-to-solve-variables-on-both-sides

How to Solve: Variables on Both Sides

By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.

⏱️ ~4 min read

How to Solve: Variables on Both Sides

(For Students Who Want to Ace Their Exam & Teachers Who Need a Ready-to-Record Script)


Introduction

"If you can solve equations with variables on both sides, you can crack word problems about phone plans, sports scores, and even college-level physics—this is the skill that separates ‘I kinda get it’ from ‘I own this exam.’"


What You Need To Know First

Before tackling variables on both sides, you must already understand: 1. Solving one-step and two-step equations (e.g., 3x + 5 = 14 or 2x – 7 = 3). 2. Combining like terms (e.g., 4x + 2x = 6x). 3. Distributive property (e.g., 3(x + 2) = 3x + 6).

If any of these feel shaky, pause here and review them first.


Key Vocabulary

Term Plain-English Definition Quick Example
Variable A letter that stands for an unknown number. In 3x + 2 = 8, x is the variable.
Coefficient The number multiplied by the variable. In 5y, 5 is the coefficient.
Like terms Terms with the same variable (or no variable). 2x and 7x are like terms.
Inverse operation The operation that "undoes" another (e.g., + undoes –). To undo +4, subtract 4.
Solution The value of the variable that makes the equation true. For x + 3 = 5, the solution is x = 2.
Distribute Multiply a term outside parentheses by each term inside. 2(x + 3) = 2x + 6.

Formulas To Know

(No formulas to memorize—just methods! But here’s what you’ll use:)

  1. Addition/Subtraction Property of Equality
  2. If a = b, then a + c = b + c and a – c = b – c.
  3. Use: Move variables or constants to one side.

  4. Multiplication/Division Property of Equality

  5. If a = b, then a × c = b × c (if c ≠ 0) and a ÷ c = b ÷ c (if c ≠ 0).
  6. Use: Isolate the variable after combining like terms.

  7. Distributive Property

  8. a(b + c) = ab + ac.
  9. Use: Expand parentheses before solving.

Step-by-Step Method

Goal: Get all variables on one side and constants on the other.

  1. Distribute (if there are parentheses).
  2. Combine like terms on each side separately.
  3. Move variables to one side using inverse operations (add/subtract).
  4. Move constants to the other side using inverse operations.
  5. Isolate the variable (divide or multiply).
  6. Check your answer by plugging it back into the original equation.

Worked Example Using the Steps

Equation: 3x + 5 = 2x + 10

Step Action Equation After Step
1 No parentheses → skip. 3x + 5 = 2x + 10
2 Combine like terms (none here). 3x + 5 = 2x + 10
3 Subtract 2x from both sides. x + 5 = 10
4 Subtract 5 from both sides. x = 5
5 Already isolated. x = 5
6 Check: 3(5) + 5 = 20 and 2(5) + 10 = 20. ✔️

Worked Examples

Example 1 – Basic

Equation: 4x – 3 = 2x + 7

Step Action Equation
1 No parentheses → skip. 4x – 3 = 2x + 7
2 Combine like terms (none). 4x – 3 = 2x + 7
3 Subtract 2x from both sides. 2x – 3 = 7
4 Add 3 to both sides. 2x = 10
5 Divide by 2. x = 5
6 Check: 4(5) – 3 = 17 and 2(5) + 7 = 17. ✔️

What we did and why: We moved 2x to the left to get all variables on one side, then moved constants to isolate x. Always check your answer!


Example 2 – Medium (Parentheses + Fractions)

Equation: 2(x + 4) = 3x – 5

Step Action Equation
1 Distribute 2. 2x + 8 = 3x – 5
2 Combine like terms (none). 2x + 8 = 3x – 5
3 Subtract 2x from both sides. 8 = x – 5
4 Add 5 to both sides. 13 = x
5 Rewrite (optional). x = 13
6 Check: 2(13 + 4) = 34 and 3(13) – 5 = 34. ✔️

What we did and why: We expanded the parentheses first, then moved variables to one side. Fractions or decimals? Clear them early (not needed here).


Example 3 – Exam Style (Disguised Variables)

Problem: "The sum of a number and 8 is equal to three times the number minus 4. Find the number."

Step Action Equation
1 Define variable: Let x = the number. x + 8 = 3x – 4
2 No parentheses → skip. x + 8 = 3x – 4
3 Subtract x from both sides. 8 = 2x – 4
4 Add 4 to both sides. 12 = 2x
5 Divide by 2. x = 6
6 Check: 6 + 8 = 14 and 3(6) – 4 = 14. ✔️

What we did and why: We translated the word problem into an equation, then solved it like any other. Always define your variable first!


Common Mistakes

Mistake Why It Happens Correct Approach
Forgetting to distribute Rushing past parentheses. Always expand a(b + c) first.
Moving terms incorrectly Adding when you should subtract (or vice versa). Use inverse operations: + undoes .
Combining unlike terms Mixing x terms with constants. Only combine x with x and numbers with numbers.
Sign errors Losing a negative sign when moving terms. Write every step clearly.
Not checking answers Assuming the answer is correct. Plug your solution back into the original equation.

Exam Traps

Trap How to Spot It How to Avoid It
Hidden parentheses Equations like 2(x + 3) = 4x – 1. Distribute first—never skip this step!
Variables that cancel out Ending with 0 = 5 or x = x. If variables disappear, check for no solution (0 = 5) or infinite solutions (x = x).
Word problems with extra info Problems like "A rectangle’s length is 5 more than twice its width. The perimeter is 34." Define variables first, then write the equation. Ignore irrelevant details.

1-Minute Recap

"Alright, listen up—this is your 60-second crash course for variables on both sides. Here’s the deal:

  1. Distribute first if you see parentheses. No shortcuts.
  2. Get all x’s on one side by adding or subtracting. Pick a side and stick with it.
  3. Move constants to the other side—same rule: add or subtract.
  4. Divide or multiply to isolate x.
  5. Check your answer by plugging it back in. If it doesn’t work, you messed up—go back!

Examiners love to hide parentheses or throw in word problems. Stay calm, define your variable, and follow the steps. You’ve got this. Now go practice—tonight’s the night you master this!




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