By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
(For Students Who Want to Ace Their Exam & Teachers Who Need a Ready-to-Record Script)
"You’re given a single point on a line and its steepness—how do you write the equation in under 30 seconds? Master point-slope form, and you’ll crush graphing, word problems, and even calculus later!
Formula: y – y₁ = m(x – x₁)
Variables: - m = slope of the line (MEMORISE THIS) - (x₁, y₁) = any point on the line (MEMORISE THIS) - x, y = variables for any other point on the line
When to use: - When you’re given one point and the slope. - When you’re given two points (first find m, then use point-slope).
Problem: Write the equation of a line with slope m = -3 passing through (4, 7).
Step 1: Identify m and (x₁, y₁). - m = -3 - (x₁, y₁) = (4, 7)
Step 2: Plug into y – y₁ = m(x – x₁). - y – 7 = -3(x – 4)
Step 3: Simplify (optional). - Distribute: y – 7 = -3x + 12 - Add 7 to both sides: y = -3x + 19
Step 4: Check. - Plug (4, 7) into y = -3x + 19: 7 = -3(4) + 19 → 7 = -12 + 19 → 7 = 7 ✅
Final Answer: y – 7 = -3(x – 4) or y = -3x + 19
Problem: A line has slope m = 2 and passes through (1, 5). Write its equation in point-slope form.
Step 1: m = 2, (x₁, y₁) = (1, 5) Step 2: y – 5 = 2(x – 1) Step 3: (Not required here) Step 4: Check: Plug (1, 5) into y – 5 = 2(x – 1) → 0 = 0 ✅
What we did and why: We substituted the given slope and point directly into the formula. No simplification was needed because the problem asked for point-slope form.
Problem: Find the equation of a line passing through (-2, 3) and (4, -1). Write in slope-intercept form.
Step 1: Find m first. - m = (y₂ – y₁) / (x₂ – x₁) = (-1 – 3) / (4 – (-2)) = -4 / 6 = -2/3 - Pick one point: (x₁, y₁) = (-2, 3)
Step 2: y – 3 = (-2/3)(x – (-2)) → y – 3 = (-2/3)(x + 2)
Step 3: Simplify to slope-intercept form. - Distribute: y – 3 = (-2/3)x – 4/3 - Add 3: y = (-2/3)x – 4/3 + 9/3 → y = (-2/3)x + 5/3
Step 4: Check with (4, -1): - -1 = (-2/3)(4) + 5/3 → -1 = -8/3 + 5/3 → -1 = -3/3 → -1 = -1 ✅
What we did and why: We calculated the slope from two points, then used point-slope form. We simplified to y = mx + b because the problem asked for slope-intercept form.
Problem: A line has slope m = 1/2 and passes through the point (6, k). The line’s equation is y – 2 = (1/2)(x – 4). Find k.
Step 1: The line passes through (6, k) and has equation y – 2 = (1/2)(x – 4). - This means (6, k) must satisfy the equation.
Step 2: Plug (6, k) into the equation. - k – 2 = (1/2)(6 – 4) - k – 2 = (1/2)(2) - k – 2 = 1
Step 3: Solve for k. - k = 1 + 2 → k = 3
Step 4: Check. - The line’s equation is y – 2 = (1/2)(x – 4). - Plug (6, 3): 3 – 2 = (1/2)(6 – 4) → 1 = 1 ✅
What we did and why: We used the fact that the given point must satisfy the line’s equation. This is a common exam trick—disguising a problem as "find k" instead of "write the equation."
"Alright, let’s lock this in. Point-slope form is y – y₁ = m(x – x₁). You need two things: the slope m and any point (x₁, y₁) on the line. If you’re given two points, find m first using m = (y₂ – y₁)/(x₂ – x₁). Plug everything into the formula, simplify if needed, and always check your answer by plugging the point back in. Watch out for negative signs—they’re the #1 mistake. And if the problem asks for y = mx + b, just distribute and isolate y. You’ve got this!
Join 4M+ learners. Unlock unlimited quizzes, wrong-answer tracking, flashcards + reminders, study guides, and 1-on-1 challenges.